How To Avoid Stack Overflow Error
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Stack Overflow In C Program
Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a how to avoid stack overflow in java community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up How to avoid stack overflow error up vote 2 down vote favorite I have a stack overflow in c examples program which can be defined as something like this reset() { //sets all variables to initial values //clears all arrays method1(); } method1 (){ //doSomeStuff; method2(); } method2(){ //doStuff method3(); } method3(){ //doStuff if (jobDone) reset(); //here the cycle closes else method2(); } All these methods are quite calculations heavy. Depending on the input data and the result the program may do just a couple of cycles and throw a 'stack
How To Avoid Stack Overflow In Recursion Java
overflow' error. I have changed the VM flag -Xss (-Xss8M) but this doesn't really solve the problem. Is there any way to make it working almost infinitely? java recurrence share|improve this question asked Mar 31 '13 at 21:21 strah 5,26441944 4 Well it's not clear from this pseudo-code what the point of all this is. You basically want to get rid of the recursion... but we have no idea how you should do that without knowing what you're trying to achieve. –Jon Skeet Mar 31 '13 at 21:23 Increase it further: -Xss16m –Szilagyi Donat Mar 31 '13 at 21:24 3 As far as I can see, reset calls method1 that class method2 that class method3 that can call method2 or reset and going into an infinite cycle (thus giving your StackOverflowError). –Luiggi Mendoza Mar 31 '13 at 21:24 I suspect you have a rather generous definition of the word "couple". Have you tried stepping through the code? –Ben Hocking Mar 31 '13 at 21:25 @BenHocking Nope, it can be literally 3-5 cycles. –strah Mar 31 '13 at 21:25 | show 7 more comments 1 Answer 1 active oldest votes up vote 2 down vote accepted Solution previously mentioned by Luiggi Mendoza: How to
call elimination comes to rescue3. Trampoline4. Other thoughts? The reason behindRecursion is a powerful form of loop which repeats itself in similar form, but it should have terminal condition to prevent endless loop. Last time, we even use it with when does stack (process stack) overflow? what are the remedies? the combination of setTimeout to prevent “Not responsive script” warning of long running loop. However, how to detect stack overflow in c normal recursion can possibly generate “Stack overflow” error if it repeats itself too many times. Let’s see a famous recursion example in math,
How To Prevent Stack Overflow In Recursion
factorial. 12345678function factorial(n) { return n === 0 ? 1 : n * factorial(n - 1);}// factorial(10)// => 3628800// factorial(32768)// => Uncaught RangeError: Maximum call stack size exceeded How does the stack looks like? Why is its size exceeded? http://stackoverflow.com/questions/15734657/how-to-avoid-stack-overflow-error Here introduces a term called Execution Context and you can read more following the link. Simply say, every times a function is called, an execution context is created. Hence, they are stacked together and increase as the recursion goes deeper. You can imagine the stack size of factorial(32768) given this from factorial(3). Tail call elimination comes to rescue Tail calls can be implemented without adding a new stack frame to the call stack. Most of the frame of http://www.thinkingincrowd.me/2016/06/06/How-to-avoid-Stack-overflow-error-on-recursive/ the current procedure is not needed any more, and it can be replaced by the frame of the tail call, modified as appropriate (similar to overlay for processes, but for function calls). The program can then jump to the called subroutine. Producing such code instead of a standard call sequence is called tail call elimination. Tail call elimination can be applied if we rewritten factorial in tail recursion style as below. 1234567function factorial(n) { function cal(n, result) { return n === 0 ? result : cal(n - 1, n * result); } return cal(n, 1);} However, the tail call optimization can only be supported until ECMAScript 6, which is not yet available in many JS engines. (Notes: Looks like Firefox already supports and it’s gonna be ready in Node.js V8 soon.) TrampolineWhat is Trampoline? a trampoline is a loop that iteratively invokes thunk-returning functions (continuation-passing style). … Programmers can use trampolined functions to implement tail-recursive function calls in stack-oriented programming languages. The simpliest form of trampoline is like below. 123456function trampoline(fn) { var op = fn; while (op != null && typeof op === 'function') { op = op(); }} The op is a thunk-returning function. If the execution result it returns is NOT a function anymore, then the loop stops. It’s not so easy to understand the meaning of thunk from the definition in Wiki. But the explanation in F
may consist of a limited amount of address space, often determined at the start of the program. The size of the call stack depends on many factors, including https://en.wikipedia.org/wiki/Stack_overflow the programming language, machine architecture, multi-threading, and amount of available memory. When a program attempts to use more space than is available on the call stack (that is, when it attempts to access memory beyond the call stack's bounds, which is essentially a buffer overflow), the stack is said to overflow, typically resulting in a program crash.[1] Contents 1 Infinite recursion 2 stack overflow Very deep recursion 3 Very large stack variables 4 See also 5 References 6 External links Infinite recursion[edit] Main article: Infinite recursion The most common cause of stack overflow is excessively deep or infinite recursion, in which a function calls itself so many times that the space needed to store the variables and information associated with each call is more than can fit stack overflow in on the stack.[2] An example of infinite recursion in C. int foo() { return foo(); } The function foo, when it is invoked, continues to invoke itself, allocating additional space on the stack each time, until the stack overflows resulting in a segmentation fault.[2] However, some compilers implement tail-call optimization, allowing infinite recursion of a specific sort—tail recursion—to occur without stack overflow. This works because tail-recursion calls do not take up additional stack space.[3] C compiler options will effectively enable tail-call optimization; compiling the above simple program using gcc with -O1 will result in a segmentation fault, but not when using -O2 or -O3, since these optimization levels imply the -foptimize-sibling-calls compiler option. Other languages, such as Scheme, require all implementations to include tail-recursion as part of the language standard.[4] Very deep recursion[edit] A recursive function that terminates in theory but causes a call stack buffer overflow in practice can be fixed by transforming the recursion into a loop and storing the function arguments in a stack. This is always possible, because the class of primitive recursive functions is equivalent to the class of LOOP computable fu