Error 26 De Turbo Pascal

ProgramadoresIniciar sesiónCorreo: Contraseña: Entrar Recordar sesión en este navegadorRecordar contraseña?Iniciar sesiónCrear cuentaDocumentación y RecursosCursos y ManualesBiblioteca de TemasCódigo FuenteNoticias/ArtículosForos y ConsultasForos de ConsultaChats de historia de turbo pascal prog.Nuevo!!Tablón de NotasDiccionario informáticoProgramadoresProgramadoresOfertas de TrabajoSolicitudes para prog.Lista de CorreoProgramasProgramas/UtilidadesNuestros ProgramasIconos ejercicios de turbo pascal y CursoresPreguntas/RespuestasOtrosUtilidadesColaboradoresEncuestas/EstadísticasContactarLWP » Foros » Pascal/Turbo Pascal » error 26: Type mismatch Pascal/Turbo Pascal - error 26: palabras reservadas de turbo pascal Type mismatch VolverNuevo Tema<<>> Vista: arbolcronológicoerror 26: Type mismatchHernan(23/06/2008 21:16:48)9.799 visitas4 respuestasRE:error 26: Type mismatchDiego Romero(26/06/2008 02:39:49)RE:error 26: Type mismatchLeonel Eduardo Morales Barrios(06/08/2014 06:08:11)RE:error 26: Type mismatchramon(06/08/2014 10:42:56)RE:error lenguaje de programacion turbo pascal 26: Type mismatchLaura(09/07/2015 02:01:37) error 26: Type mismatchPublicado por Hernan(3 intervenciones) el 23/06/2008 21:16:48tengo un problema... no entiendo porque me salio este problema... declaro el registro del archivo Tnov=record codmov:string[1] despues cuando pongo en el programa... begin x:=x+1; {un contador} if rnov.codmov=1 then begin... etcetera.. me sale el error 26: type mismatch... el puntero se ubica

Instrucciones De Decision En Turbo Pascal

al final del " =1" porque?? por favor ayudenme...Valora esta pregunta0ResponderOtras secciones de LWP con contenido de Pascal/Turbo Pascal- Código fuente de Pascal/Turbo Pascal- Cursos de Pascal/Turbo Pascal- Temas de Pascal/Turbo Pascal- Chat de Pascal/Turbo PascalCódigos de Pascal/Turbo Pascal- Toros y Vacas- Permutaciones- calcular areas y perimetros con case-of RE:error 26: Type mismatchPublicado por Diego Romero(997 intervenciones) el 26/06/2008 02:39:49http://www.driverop.com.ar/Debido a que el campo codmov es de tipo string tienes que comparar con otro tipo string; en el código que has posteado lo estás comparando con un tipo entero, de allí el mensaje de error ("tipos no coinciden"). La solución: if rnov.codmov='1' then Pero aún así veo otro problema de fondo. Esto: codmov:string[1]; es equivalente a esto: codmov:char; Ya que codmov al ser un string que almacena un caracter es igual a decararlo como un char que también almacena un caracter. En fin, espero que no sea un problema...Valora esta respuesta0Comentar RE:error 26: Type mismatchPublicado por Leonel Eduardo Morales Barrios(1 intervención) el 06/08/2014 06:08:11Hola, yo tengo tambi

Merise UML JavaPlateforme et langage Java Java Java Web Spring Android Eclipse NetBeans .NETMicrosoft Framework .NET Microsoft DotNET Visual Studio ASP.NET C# VB.NET Windows Phone Microsoft Azure Dév. WebDéveloppement Web et Webmarketing Développement Web AJAX Apache ASP CSS Dart Flash / Flex JavaScript PHP Ruby & Rails TypeScript Web sémantique Webmarketing (X)HTML EDIEnvironnements de Développement Intégré EDI 4D Delphi Eclipse LabVIEW NetBeans MATLAB Scilab Visual Studio WinDev Visual Basic 6 Lazarus Qt Creator ProgrammationProgrammation et langages de programmation applicatifs Programmation Débuter - Algorithmique 2D - 3D - Jeux Assembleur C C++ Go Objective C Pascal Perl Python Swift Qt XML Autres SGBDSystèmes http://www.lawebdelprogramador.com/foros/Pascal-Turbo-Pascal/991846-error-26-Type-mismatch.html de Gestion de Bases de Données SGBD & SQL 4D Access Big Data DB2 Firebird InterBase MySQL NoSQL PostgreSQL Oracle Sybase SQL-Server OfficeBureautique pour l'entreprise Microsoft Office Access Excel Word Outlook PowerPoint SharePoint Microsoft Project OpenOffice & LibreOffice Solutions d'entrepriseAutres logiciels pour l'entreprise Solutions d'entreprise Big Data BPM Business Intelligence ERP / PGI CRM SAS Cloud Computing SAP Microsoft BizTalk Server Talend IBM Bluemix ApplicationsApplications logicielles Applications Libres http://www.developpez.net/forums/d1043854/autres-langages/pascal/turbo-pascal/debutant-tableau-erreur-26-type-mismatch/ & Open Source OpenOffice & LibreOffice Projets MobilesLogiciels et matériels mobiles Mobiles Android iOS Windows Phone SystèmesLogiciels et matériels systèmes Systèmes Windows Linux Sécurité Hardware Mac Raspberry Pi Réseau Green IT Systèmes Embarqués Virtualisation Programmation Algorithmique 2D-3D-Jeux Assembleur C C++ Go Objective C Pascal Perl Python Swift Qt XML Autres ACTUALITÉS PASCAL FORUM PASCAL F.A.Q PASCAL TUTORIELS EXERCICES SOURCES COMPILATEURS OUTILS LIVRES WIKI S'inscrire Aide Quoi de neuf ? Forum Actions Marquer les forums comme lus Bugs & Suggestions Réseau social Groupes Liste des utilisateurs FAQ forum Voir l'équipe du site Blogs Agenda Règles Blogs Projets Recherche avancée Index du forum Autres langages Pascal Turbo Pascal [Turbo Pascal] [Débutant] Tableau : erreur 26 "type mismatch" + Répondre à la discussion Discussion: [Débutant] Tableau : erreur 26 "type mismatch" Outils de la discussion Afficher une version imprimable S'abonner à cette discussion… Affichage Mode linéaire Choisir le mode hybride Choisir le mode arborescent 27/02/2011,00h27 #1 khmamed Futur Membre du Club Inscrit enfévrier 2011Messages12Détails du profilInformations forums :Inscription : février 2011Messages : 12Points : 5Points5 [Débutant] Tableau : erreur 26 "type mismatch" Salut à tous premièrement, merci à ce forum qui est un grand soutien pour les apprenants de développement. Code : Sélectionner tout -

different type than the expression in the assignment. You are calling a function or procedure with http://www.freepascal.org/docs-html/user/userse63.html parameters that are incompatible with the parameters in the function or procedure definition. Error: Incompatible types: got "arg1" expected "arg2" There is no conversion possible between the http://stackoverflow.com/questions/12604323/whats-wrong-with-this-pascal-syntax two types. Another possiblity is that they are declared in different declarations:  Var      A1 : Array[1..10] Of Integer;      A2 : Array[1..10] Of Integer;     Begin      A1:=A2; { This statement also gives this error. It                is due to the strict type checking of Pascal }   End.    Error: Type mismatch between "arg1" and turbo pascal "arg2" The types are not equal. Error: Type identifier expected The identifier is not a type, or you forgot to supply a type identifier. Error: Variable identifier expected This happens when you pass a constant to a routine (such as Inc var or Dec) when it expects a variable. You can only pass variables as de turbo pascal arguments to these functions. Error: Integer expression expected, but got "arg1" The compiler expects an expression of type integer, but gets a different type. Error: Boolean expression expected, but got "arg1" The expression must be a boolean type. It should be return True or False. Error: Ordinal expression expected The expression must be of ordinal type, i.e., maximum a Longint. This happens, for instance, when you specify a second argument to Inc or Dec that doesn't evaluate to an ordinal value. Error: pointer type expected, but got "arg1" The variable or expression isn't of the type pointer. This happens when you pass a variable that isn't a pointer to New or Dispose. Error: class type expected, but got "arg1" The variable or expression isn't of the type class. This happens typically when The parent class in a class declaration isn't a class. An exception handler (On) contains a type identifier that isn't a class. Error: Can't evaluate constant expression This er

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up What's wrong with this Pascal syntax? up vote 0 down vote favorite I can't understand what's going on here. Can you give me a hand? This is the problematic code: While not EOF(Archi) do begin index:= index + 1; Read(Archi, Alumno[index]); Promes[index] := (Alumno[index].nota1 + Alumno[index].nota2) / 2; if Promes[index] >= 6 then begin alguPromo := true; PromosIndex := PromosIndex + 1; Promos[PromosIndex]:= Alumno[index]; end; else begin if Promes[index] > 4 then cantiRecu:= cantiRecu + 1; else begin LibresIndex += 1; Libres[LibresIndex] := Alumno[index]; end; end; end; The compiler marks error in the line 10 of this code (else begin). The error is: Fatal: Syntax error, ; expected but ELSE found. If someone wants to tray compile here is the entire code: http://pastebin.com/dRg1Lguu pascal share|improve this question edited Sep 26 '12 at 14:50 asked Sep 26 '12 at 14:43 sanfilippopablo 4581611 Are you sure that pascal support += operator? –CAMOBAP Sep 26 '12 at 14:44 What is the problem with the code? –BugFinder Sep 26 '12 at 14:46 2 There should not be a semicolon after the end before the else. Ditto for the line cantiRecu:= cantiRecu + 1 - this should not have a semicolon either. –Paul R Sep 26 '12 at 14:47 Thanks man! Was the semicolon! I had a suspect that was that, but i couldn't fix it. Done. Thanks man. –sanfilippopablo Sep 26 '12 at 14:55 @user1491651: OK - I've fleshed this out into a complete answer now - please up-vote and accept it if it has been useful to you. –Paul R Sep 26 '12 at 14:57 add a comment| 2 Answers 2 active oldest votes up vote 5 down vote accepted Note that in Pascal the semicolon is a separator, not a terminator. Sometimes this doesn't matter, but in some cases it does, particularly before an else. Your code should be: while not EOF(Archi) do begin index:= index + 1; Read(Archi, Alumno[index]); Promes[index] := (Alumno[index].nota1 + Alumno[index].nota2) / 2;