Error Called Object Is Not A Function In C

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow error called object is not a function or function pointer the company Business Learn more about hiring developers or posting ads with us Stack error called object type 'int' is not a function or function pointer Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community called object is not a function c programming of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up C compilation error, called object is not a function up vote -2 down vote favorite I have

Error Called Object Time Is Not A Function

the following code in C to make some arithmatic calculation #include #include int main() { float x,y; float z; printf("Enter x y z \n"); scanf("%f %f %f ", &x, &y , &z); z = ((4.2 (x+y)))/ (z - (0.25*z))/ (y+z)/ ((x+y) * (x+y)); printf("\n z = %f", z); return 0; } when i build the program , i get the following error message in the following code line z = called object is not a function or function pointer c++ ((4.2 (x+y)))/ (z - (0.25*z))/ (y+z)/ ((x+y) * (x+y)); called object is not a function or dunction pointer c compiler-errors share|improve this question edited Nov 6 '14 at 11:36 asked Nov 6 '14 at 11:33 Developer 4081722 8 You miss something after 4.2 –downhillFromHere Nov 6 '14 at 11:36 6 There should be an operator after 4.2 –stark Nov 6 '14 at 11:36 4.2(x+y) might be what you've learned in school but in C you have to use 4.2*(x+y) instead of the other one –Cool Guy Nov 6 '14 at 11:40 add a comment| 1 Answer 1 active oldest votes up vote 3 down vote That's a typo, you're missing an operator: z = ((4.2 * (x + y))) / (z - (0.25*z)) / (y + z) / ((x + y) * (x + y)); ^ whatever the operator is C has no support for mathematics-implicit multiplication operator (more or less as you would write in an equation in school). E.g. // y = 2x int y; y = 2 * x; share|improve this answer edited Nov 6 '14 at 11:50 answered Nov 6 '14 at 11:39 Marco A. 29.2k1159141 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Goog

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Called Object Is Not A Function C++

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Called Object Is Not A Function Or Function Pointer Objective C

Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only http://stackoverflow.com/questions/26778458/c-compilation-error-called-object-is-not-a-function takes a minute: Sign up Can't figure out this “called object is not a function” C time error up vote 2 down vote favorite 1 So for part of my school assignment, I need to find the current time, and i used this as a reference:http://www.cplusplus.com/reference/ctime/localtime/ I tried to copy what they did, but I keep getting this error: l8stat.c:33: http://stackoverflow.com/questions/20273402/cant-figure-out-this-called-object-is-not-a-function-c-time-error error: called object '15552000' is not a function This is the line: time(¤t_time); I really don't understand why this is happening when I'm doing the same thing as the example. Here's my code: #include #include #include #include #include #include #include #include #include #include #include #include #define SEC_PER_DAY (24 * 60 * 60) #define time (SEC_PER_DAY*180) void print_data(char *path ){ setlocale (LC_NUMERIC, "en_US"); struct stat *new=malloc(sizeof(struct stat)); char linkname[PATH_MAX + 1]; int status=lstat(path, new); if(status==0){ printf("%.6o %9d ",new->st_mode, new->st_size ); } else{ fprintf (stderr, "l8stat: %s: %s\n", path, strerror (errno)); } time_t current_time; struct tm *local_time; time(¤t_time); local_time=localtime(¤t_time); char buffer[50]; if(current_time-new->st_mtime<=time ){ strftime(buffer,50,"%b %e %R",new->st_mtime); puts(buffer); } else{ strftime(buffer,50,"%b %e %Y",new->st_mtime); puts(buffer); } ssize_t retval = readlink (path, linkname, sizeof linkname); if(retval >=0){ linkname[retval < PATH_MAX + 1 ? retval : PATH_MAX] = '\0'; printf ("%s -> \"%s\"\n", path, linkname); } printf(" %s",path); } int main (int argc, char **argv) { int exit_status=EXIT_SUCCESS; for(int argi = 1; argi

Programming Boards C Programming Getting Error: Called Object is not a Function Getting started with C or C++ | C Tutorial | C++ Tutorial | C and C++ FAQ | Get a http://cboard.cprogramming.com/c-programming/128003-getting-error-called-object-not-function.html compiler | Fixes for common problems Thread: Getting Error: Called Object is not a http://www.dreamincode.net/forums/topic/334210-problem-called-object-type-not-a-function-or-function-pointer/ Function Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 06-22-2010 #1 Ketsueki View Profile View Forum Posts Registered User Join Date Jun 2010 Posts 2 Getting Error: Called Object is not a Function Hello All, This is just a simple programming challenging from called object a book I'm using to learn C, it doesn't call for the if/else statement but I wanted to add it. I have used if/else before successfully, but for some reason now on the else portion it wont do the calculation. At first I thought celsius was a reserved word and thats why it was failing, but so I changed the variables name but still same error. Code: #include int main(void) { int is not a Choice; /* stores users choice on conversion */ double fahrenheit; /* stores the temp in Fahrenheit */ double centigrade; /* stores the temp in Celsius */ /* Asks the user what they want to convert. */ printf("Please choose how you want to convert\n"); printf("Press 1 for Celsius to Fahrenheit\n"); printf("Press 2 for Fahrenheit to Celsius: "); scanf("%d", &Choice); /*Determines what the user chooses */ if (Choice == 1) { /* Obtains the temp and converts to fahrenheit */ printf("\nPlease enter in the Temp in degree's Celsius: "); scanf("%lf", ¢igrade); fahrenheit = (9/5 * centigrade)+32; printf("\n %.2f Celsius is %.2f Fahrenheit\n ", centigrade, fahrenheit); } else { /* Obtains the temp and converts to Celsius */ printf("\nPlease enter in the Temp in degree's Fahrenheit: "); scanf("%lf", &fahrenheit); centigrade = (5/9)(fahrenheit - 32); printf("\n %.2f Fahrenheit is %.2f Celsius\n", fahrenheit, centigrade); } return(0); } when compiled I get this error ConvertTemp.c:40: error: called object is not a function and line 40 is centigrade = (5/9)(fahrenheit -32); but the equation in the if statement runs fine, and if I take else out completely it runs fine. I read around about people with similar errors, and tried to use the fixes they had but most were when they were actually calling a function aside from stdio.h I'm not calling any

function pointer? Page 1 of 1 New Topic/Question Reply 3 Replies - 8713 Views - Last Post: 16 November 2013 - 05:13 PM Rate Topic: #1 SonicSoundVW New D.I.C Head Reputation: 0 Posts: 35 Joined: 05-November 13 problem, called object type not a function or function pointer? Posted 16 November 2013 - 04:52 PM My code will not compile due to 2 errors. called object type 'char *' is not a function or function pointer and expected unqualified-id. i have moved the brackets and to be honest, with my limited knowledge, i honestly don't see what is wrong. If somebody could point me in the right direction and or give any advice about my code it would be greatly appreciated. Thank you in advance. :-) #include using namespace std; int sentenceCount (char[]); void allCap(char[], int); void displaySentence(char []); void numVowels(char [], int&, int&, int&, int&, int&); void reverseSentence(char [],char []); int main() { const int SIZE = 50; char sentence[SIZE]; char reverseSentence[SIZE]; int a, e, i, o, u; int howMany = 0; cout << "Please enter a sentence of no more than" << endl; cout << (SIZE -1) << " characters:\n"; cin.getline(sentence, SIZE); cout << endl; cout << "The sentence you entered is:\n"; displaySentence(sentence); cout << endl << endl; howMany = sentenceCount(sentence); cout << "There were " << howMany << " charcters entered." << endl; cout << endl; allCap(sentence, howMany); cout << "This is what the sentence would look like" << endl; cout << "with all capital letters: " << endl; displaySentence(sentence); cout << endl << endl; numVowels(sentence, a, e, i, o, u); cout << "This sentence contains:" << endl; cout << a << " As " << e << " Es " << i << " Is "; cout << o << " Os and " << u << " Us " << endl << en