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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site cannot convert std string to const char * for argument 1 About Us Learn more about Stack Overflow the company Business Learn more about no suitable conversion function from std string to const char * hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join

Convert String To Const Char C++

the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Cannot convert ‘std::string’ to

Convert String To Const Char Arduino

‘const char* up vote 2 down vote favorite 1 Hi can any one tell what wrong with this code ?. string s=getString(); //return string if(!strcmp(s,"STRING")){ //Do something } while compiling I am getting the error like error: cannot convert ‘std::string’ to ‘const char*’ for argument ‘1’ to ‘int strcmp(const char*, const char*)’| c++ share|improve this question edited May 29 '13 at 9:47 Jeyaram 5,37221643 asked May cannot convert 'string' to 'const char*' arduino 29 '13 at 9:40 Haris 6,62443255 2 You want if ( s == "STRING" ). strcmp is the const char* version. (You could use if (!strcmp(s.c_str(), "STRING"), but don't). –BoBTFish May 29 '13 at 9:42 1 Did you look at the documentation for strcmp to see what arguments it accepts? Why do you even use strcmp like that when you already have an std::string that defines operator==? –Jon May 29 '13 at 9:42 5 @BoBTFish (s == "STRING") in this case. –ForEveR May 29 '13 at 9:43 5 @Rakkun: that's not good practice... the std::string type overloads comparison to a const char* to avoid creating a std::string temporary as your suggested code does.... –Tony D May 29 '13 at 9:48 4 The beauty of C++: Where string == "foo" means exactly what it says. –stefan May 29 '13 at 9:51 | show 3 more comments 5 Answers 5 active oldest votes up vote 11 down vote accepted strcmp accepts const char* as argument. You can use c_str method: if(!strcmp(s.c_str(),"STRING")) Or just use overloaded operator== for std::string: if(s == "STRING") share|improve this answer answered May 29 '13 at 9:42

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Cannot Convert String To Const Char * For Argument Atoi

Us Learn more about Stack Overflow the company Business Learn more about hiring no known conversion for argument 1 from 'string' to 'const char*' arduino developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the string to const char arduino Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up .cpp:23: error: cannot convert ‘std::string’ to http://stackoverflow.com/questions/16810485/cannot-convert-stdstring-to-const-char ‘const char*’ for argument ‘1’ to ‘int atoi(const char*)’ up vote 1 down vote favorite Here a basic code I'm trying to run But I'm having trouble with stoi (it's c++) I keep getting error: ‘stoi’ was not declared in this scope I tried atoi and strtol with this error .cpp:23: error: cannot convert ‘std::string’ to ‘const char*’ for argument ‘1’ to ‘int atoi(const char*)’ The http://stackoverflow.com/questions/30971933/cpp23-error-cannot-convert-stdstring-to-const-char-for-argument-1-t code: using namespace std; int main(){ string numberGuessed; int intNumberGuessed = 0; do { cout << "Guess a numeber btw 1 - 10: " << endl; getline(cin, numberGuessed); intNumberGuessed = atoi(numberGuessed); cout << intNumberGuessed << endl; } while(intNumberGuessed != 4); cout<< "you win" << endl; return 0; } c++ string share|improve this question edited Jun 22 '15 at 5:12 Hi-Angel 1,33951540 asked Jun 22 '15 at 3:55 kirk mgurk 814 1 Use e.g. atoi(numberGuessed.c_str());. –Jonathan Potter Jun 22 '15 at 3:56 std::stoi requires you to #include , but it also requires a modern (C++11 compatible) compiler -- see en.cppreference.com/w/cpp/string/basic_string/stol. atoi requires a c-string which you can obtain with numberGuessed.c_str() –kfsone Jun 22 '15 at 4:33 Just use intNumberGuessed = atoi(numberGuessed.data()); and you are good to go. –Milan Patel Jun 22 '15 at 4:34 1 note: The original MinGW doesn't have stoi or to_string, however MinGW-w64 does –M.M Jun 22 '15 at 5:37 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted Use stoi, it's the modern C++ version of C's atoi. Update: Since the original answer text above the question was amended with the foll

problem with an assignment that I'm not sure how to fix I'm getting the following error: accountdb.cpp:55: error: cannot https://www.daniweb.com/programming/software-development/threads/412343/error-convert-string-to-const-char convert std::string to const char* for argument 1 to int strcmp(const char*, const char*) Here is my header file: #ifndef ACCOUNTDB_H #define ACCOUNTDB_H #include "account.h" #include class AccountDB { private: Account AccountArray[30]; int ObjectsStored; public: AccountDB(); AccountDB(const char*); void print () const; void sortAccounts(); }; #endif And here is where the error const char is comming from (accountdb.cpp): #include "account.h" #include "accountdb.h" #include #include #include #include #include #include using namespace std; AccountDB::AccountDB() { ObjectsStored = 0; } AccountDB::AccountDB(const char* accountdb) { ifstream inFile; inFile.open(accountdb, ios::binary); if (!inFile) { cout << "Unable to open file accountdb" << endl; exit(-1); } inFile.read((char*) this, string to const sizeof(AccountDB)); inFile.close(); sortAccounts(); } void AccountDB::print() const { cout << "Account Database Listing" << endl << endl; for (int i = 0; i < ObjectsStored; i++) { AccountArray[i].print(); cout << endl; } } void AccountDB::sortAccounts() { int i, j; Account bucket; for (i = 1; i < ObjectsStored; i++) { bucket = AccountArray[i]; for (j = i; (j > 0) && (strcmp(AccountArray[j - i].getAccountNumber(), bucket.getAccountNumber() )> 0); j --) AccountArray[j] = AccountArray[j - 1]; AccountArray[j] = bucket; } } The sortAccounts method should sort ACCOUNTS in ascending order. I'm getting an error and I'm not sure how to fix and I've been stuck for a while now. Anyone know how I can fix it? I tried using c_str but I probably used it wrong and it ended up giving me more errors. Any way to do it while using strcmp? Thank you for your help. randrum1707 11 posts since Feb 2012 Community Member 2Contributors 2Replies 3Views 4 YearsDiscuss

 

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