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Error Const Char* Is Not A Structure Type

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Error A Value Of Type Const Char

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Error Invalid Conversion From Const Char * To Char * Fpermissive

only takes a minute: Sign up C++ Member Reference base type 'int' is not a structure or union up vote 3 down vote favorite I'm running into a Problem in my C++ Code. I have a union StateValue: union StateValue a value of type const char cannot be assigned to lpcwstr { int intValue; std::string value; }; and a struct StateItem struct StateItem { LampState state; StateValue value; }; I have a method which goes through a vector of type StateItem for(int i = 0; i < stateItems.size(); i++) { StateItem &st = stateItems[i]; switch (st.state) { case Effect: result += std::string(", \"effect\": ") + st.value.value; break; case Hue: result += std::string(", \"hue\": ") + st.value.intValue.str(); break; case On: result += std::string(", \"on\": ") + std::string(st.value.value); break; default: break; } } a value of type const char cannot be assigned to an entity of type char In the case Hue I get the following Compiler error: Member reference base type 'int' is not a structure or union I can´t understand the problem here. Can anyone of you please help me? c++ share|improve this question edited Sep 24 '14 at 18:39 user39275 356 asked Jan 27 '14 at 17:36 Alex 1791313 6 int doesn't have a str() function. It's not even a class. –chris Jan 27 '14 at 17:38 Note that being able to use non-pod types (like std::string) in unions is new with C++11, so if you try to compile it with older compilers that doesn't support C++11 then you will get an error. –Joachim Pileborg Jan 27 '14 at 17:45 As for your problem, you might want to look at the function std::to_string. –Joachim Pileborg Jan 27 '14 at 17:46 add a comment| 4 Answers 4 active oldest votes up vote 4 down vote accepted You're trying to call a member function on intValue, which has type int. int isn't a class type, so has no member functions. In C++11 or later, there's a handy std::to_string function to convert int and other built-in types to std::string: result += ", \"hue\": " + std::to_string(st.value.intValue); Historically, you'd have to mess around with string streams: { std::stringstream ss; ss << st.value.intValue; result += ", \"hue\": " + ss.str(); } share|improve this answer answered Jan 27 '14 at 17:45 Mike Seymour 1

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Invalid Operands Of Type Const Char

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Argument Of Type Const Char * Is Incompatible With Parameter Of Type Char *

takes a minute: Sign up Error converting const char to char in struct? up vote 1 down vote favorite This is a bit written from memory so I apologize if I made a mistake in this posting. I created a http://stackoverflow.com/questions/21387687/c-member-reference-base-type-int-is-not-a-structure-or-union struct and wanted to assign a name to it, but I get this error: error: incompatible types in assignment of const char[3]' tochar[15]' For the life of me I tried to understand what exactly is wrong here, I thought a constant char can still be assigned. # include struct type{ char name[15]; int age; }; main(){ struct type foo; foo.name = "bar"; //error here foo.age=40; printf("Name- %s - Age: %d", foo.name, foo.age); } c char const share|improve this question edited http://stackoverflow.com/questions/4528321/error-converting-const-char-to-char-in-struct Aug 18 '12 at 15:13 bitmask 13.8k644103 asked Dec 24 '10 at 20:58 Dajue R. 813 What you've written is not C++, why the tag? –GManNickG Dec 24 '10 at 21:27 similar question asked here : stackoverflow.com/q/4362801/513660 –Will Dec 24 '10 at 21:32 @GMan: What OP has written is not C either, since C does not have assignment to arrays... –R.. Dec 24 '10 at 22:01 @R: You get what I mean. –GManNickG Dec 24 '10 at 22:02 By the way, the error message seems incorrect. "bar" has type char [4], not const char [3]. The const could be a result of compiling C with a C++ compiler, but the [3] is nonsense... –R.. Dec 24 '10 at 22:03 add a comment| 4 Answers 4 active oldest votes up vote 3 down vote accepted char name[15]; declares an array, which is not assignable in C. Use string copying routines to copy the values, or declare name as a pointer - char* name; (here you'd have to worry about memory pointed to still being valid). You can initialize a struct-type variable as a whole though: struct type foo = { "bar", 40 }; Here string literal "bar" (four bytes including zero-terminator) will be copied into the name member array. share|improve this answer edited Dec 24 '10 at 21:14 answered Dec 24 '10 at 21:04 Nikolai N Fetissov 62k765125 add a comment

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About http://stackoverflow.com/questions/11712578/objective-c-member-reference-base-type-error Us Learn more about Stack Overflow the company Business Learn more about hiring developers https://paiza.io/projects/5kyhheJnlNZjj3sIx6ipWA or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Objective C Member reference base type error const char up vote 1 down vote favorite I'm following the code from the Learning iOS Programming 2nd Edition book by Alasdair Allan page 91. I'm trying to make a table view output information to the text view. Everything else works before I add this code. The delegate.cities refers to a NSMutableArray called cities in the AppDelegate. I think is might have something to do with objectAtIndex expecting of type const a NSUInteger, but the book says to send it index.row. index is of type NSIndexPath which is in my SimpleView class which I imported into this class. row is of type NSInteger so I'm assuming that the problem is that the book wants me to send objectAtIndex a signed integer when it is expecting an unsigned integer. Could that be he problem? If so, how do I fix it? Error message: Member reference base type 'char (const char,int)' is not a structure or union Here's my function: -(void)viewDidLoad { [super viewDidLoad]; AppDelegate *delegate = (AppDelegate *)[[UIApplication sharedApplication] delegate]; City *thisCity = [delegate.cities objectAtIndex:index.row]; //error with index.row self.title = thisCity.cityName; } iphone objective-c ios share|improve this question edited Apr 27 at 19:59 mylogon 7031928 asked Jul 29 '12 at 20:16 apples 816 Integer conversion occurs automagically. It's irrelevant/unrelated. I'm sure you use NSIndexPath index instead of NSIndexPath *index. –user529758 Jul 29 '12 at 20:21 add a comment| 1 Answer 1 active oldest votes up vote 2 down vote The global function index() in the system header string.h is defined with a signature similar to that of the error (char* (const char*, int)). It appears that the com

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