Differentials Approximate Maximum Error
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available. Most of the classes have practice problems with solutions available on the practice problems use differentials to approximate the maximum error pages. Also most classes have assignment problems for instructors to differentials to approximate change assign for homework (answers/solutions to the assignment problems are not given or available on the site).
Differentials To Approximate Square Root
Algebra [Notes] [Practice Problems] [Assignment Problems] Calculus I [Notes] [Practice Problems] [Assignment Problems] Calculus II [Notes] [Practice Problems] [Assignment Problems] Calculus III [Notes] [Practice Problems] [Assignment
Differentials To Approximate Volume
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Use Differentials To Approximate The Value Of The Expression
je taal. Sluiten Meer informatie View this message in English Je gebruikt use differentials to approximate the quantity YouTube in het Nederlands. Je kunt deze voorkeur hieronder wijzigen. Learn more You're viewing YouTube in Dutch. You can use differentials to approximate cube root of 28 change this preference below. Sluiten Ja, nieuwe versie behouden Ongedaan maken Sluiten Deze video is niet beschikbaar. WeergavewachtrijWachtrijWeergavewachtrijWachtrij Alles verwijderenOntkoppelen Laden... Weergavewachtrij Wachtrij __count__/__total__ Using differentials to estimate maximum error http://tutorial.math.lamar.edu/Classes/CalcI/Differentials.aspx Mitch Keller AbonnerenGeabonneerdAfmelden3636 Laden... Laden... Bezig... Toevoegen aan Wil je hier later nog een keer naar kijken? Log in om deze video toe te voegen aan een afspeellijst. Inloggen Delen Meer Rapporteren Wil je een melding indienen over de video? Log in om ongepaste content te melden. Inloggen Transcript Statistieken 5.950 weergaven 6 Vind je dit een leuke video? Log in om https://www.youtube.com/watch?v=pFtpxooa7kw je mening te geven. Inloggen 7 2 Vind je dit geen leuke video? Log in om je mening te geven. Inloggen 3 Laden... Laden... Transcript Het interactieve transcript kan niet worden geladen. Laden... Laden... Beoordelingen zijn beschikbaar wanneer de video is verhuurd. Deze functie is momenteel niet beschikbaar. Probeer het later opnieuw. Gepubliceerd op 6 feb. 2014An example of using differentials to determine the maximum error in a volume calculation if you know the manufacturing error possibilities for the dimensions Categorie Onderwijs Licentie Standaard YouTube-licentie Meer weergeven Minder weergeven Laden... Autoplay Wanneer autoplay is ingeschakeld, wordt een aanbevolen video automatisch als volgende afgespeeld. Volgende Errors Approximations Using Differentials - Duur: 5:24. IMA Videos 17.127 weergaven 5:24 Calculus - Differentials with Relative and Percent Error - Duur: 8:34. Stacie Sayles 3.364 weergaven 8:34 Greatest Possible Error - Duur: 10:36. MrsRZimmerman 2.257 weergaven 10:36 Differentials: Propagated Error - Duur: 9:31. AllThingsMath 9.298 weergaven 9:31 Error Propagation - Duur: 7:27. ProfessorSerna 6.929 weergaven 7:27 The Squeeze Theorem - Duur: 8:58. Mitch Keller 33 weergaven 8:58 Propagation of Error - Duur: 7:01. Matt Becker 10.709 weerg
Solutions 1. Approximations If a quantity x (eg, side of a square) is obtained by measurement and a quantity y (eg, area of the square) is calculated as a function of x, say http://www.phengkimving.com/calc_of_one_real_var/08_app_of_the_der_part_2/08_04_approx_of_err_in_measrmnt.htm y = f(x), then any error involved in the measurement of x produces an error in the calculated value of y as well. Recall from Section 4.3 Part 2 that the Section 8.3 Part 1, we have: That is, the error in x is dx and the corresponding approximate error in y is dy = f '(x) dx. Fig. 1.1 Fig. 1.2 – 1st differentials to and 2nd axes: if 1,000 = xa – 1 then xa = 1,001, – 1st and 3rd axes: if 1,000 = xa + 1 then xa = 999, therefore xa is somewhere in [999, 1,001]. Example 1.1 Solution Let s be the side and A the area of the square. Then A = s2. The error of the side is ds = 1 m. The approximate error of differentials to approximate the calculated area is: dA = 2s ds = 2(1,000)(1) = 2,000 m2. EOS Note that we calculate dA from the equation A = s2, since the values of s and ds are given. To find the differential of A we must have an equation relating A to s. So even if the measured value of the side is given we still define the variable s that takes on as a value the measured value. In general, when the measured value say V of a quantity and the error say E in the measurement are given, we define a variable say x for the quantity, so that x = V and dx = E, which will be used later on in the solution. When using the quantity, first use the variable x, not the value V, then use the value V when a value is to be obtained. Go To Problems & Solutions Return To Top Of Page 2. Types Of Errors A measurement of distance d1 yields d1 = 100 m with an error of 1 m. A measurement of distance d2 yields d2 = 1,000 m with an error of 1 m. Both measurements have the same absolute error of 1 m. However, intuitively we feel that measurement of d2 has a smaller error because it's 10 times larger