Differentials To Estimate The Maximum Possible Error
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Use Differentials To Estimate The Maximum Error
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Use Differentials To Estimate The Maximum Error In The Calculated Area Of The Disk
the maximum possible error, relative error, and percentage error in computing? The edge of a cube was found to be 15 cm with a possible error in measurement of 0.4 cm. Use differentials to estimate the maximum possible error, relative error, and percentage error in computing the volume of the cube and the surface area of the cube. Follow 2 answers 2 Report Abuse Are you sure you
Use Differentials To Estimate The Maximum Error In The Calculated Volume
want to delete this answer? Yes No Sorry, something has gone wrong. Trending Now Keanu Reeves Hilary Duff Jackie Bradley Jr Taylor Swift Wiz Khalifa Online Schools Keith Richards Microsoft Office Toyota 4runner Cleveland Browns Answers Best Answer: I am reasonably confident the following is the correct answer V=x^3 dV=3x^2dx Our error in x is 0.4. Hence, dx=0.4 and x=15 dV=3*(15)^2*0.4=270cm^3 -> This is maximum error, namely +/- 270cm^3 Percentage error= dV/V *100= 270/(15^3) *100=270/3375*100=0.08*100=8% Source(s): Answer-Man · 7 years ago 3 Thumbs up 0 Thumbs down Comment Add a comment Submit · just now Report Abuse Let x be the edge Volume = x^3 Let y be the volume y=x^3 = (15)^3 = 225 dy = 3x^2 dx dy = 3(15)^2 (0.4) = 270 Maximum possible error = |225-270| = 55 cm^3 Relative error = |225 - 270| / |225| = 55/225 = 0.2444 Percentage error = relative error x 100 = 24.44 % Source(s): http://en.wikipedia.org/wiki/Approximati... cidyah · 7 years ago 1 Thumbs up 1 Thumbs down Comment Add a comment Submit · just now Report Abuse Add your answer Use differentials to estimate the maximum possible error, relative error, and percentage error in computing? The edge of a
available. Most of the classes have practice problems with solutions available on the practice problems pages. Also most classes have assignment use differentials to estimate the maximum error in the viscosity problems for instructors to assign for homework (answers/solutions to the assignment
Use Differentials To Estimate The Propagated Error
problems are not given or available on the site). Algebra [Notes] [Practice Problems] [Assignment Problems] Calculus I [Notes] differentials to estimate value [Practice Problems] [Assignment Problems] Calculus II [Notes] [Practice Problems] [Assignment Problems] Calculus III [Notes] [Practice Problems] [Assignment Problems] Differential Equations [Notes] Extras Here are some extras topics that https://answers.yahoo.com/question/index?qid=20100409080604AA8Rb95 I have on the site that do not really rise to the level of full class notes. Algebra/Trig Review Common Math Errors Complex Number Primer How To Study Math Close the Menu Current Location : Calculus I (Notes) / Applications of Derivatives / Differentials Calculus I [Notes] [Practice Problems] [Assignment Problems] Review [Notes] [Practice Problems] [Assignment Problems] Review http://tutorial.math.lamar.edu/Classes/CalcI/Differentials.aspx : Functions [Notes] [Practice Problems] [Assignment Problems] Review : Inverse Functions [Notes] [Practice Problems] [Assignment Problems] Review : Trig Functions [Notes] [Practice Problems] [Assignment Problems] Review : Solving Trig Equations [Notes] [Practice Problems] [Assignment Problems] Review : Trig Equations with Calculators, Part I [Notes] [Practice Problems] [Assignment Problems] Review : Trig Equations with Calculators, Part II [Notes] [Practice Problems] [Assignment Problems] Review : Exponential Functions [Notes] [Practice Problems] [Assignment Problems] Review : Logarithm Functions [Notes] [Practice Problems] [Assignment Problems] Review : Exponential and Logarithm Equations [Notes] [Practice Problems] [Assignment Problems] Review : Common Graphs [Notes] [Practice Problems] [Assignment Problems] Limits [Notes] [Practice Problems] [Assignment Problems] Tangent Lines and Rates of Change [Notes] [Practice Problems] [Assignment Problems] The Limit [Notes] [Practice Problems] [Assignment Problems] One-Sided Limits [Notes] [Practice Problems] [Assignment Problems] Limit Properties [Notes] [Practice Problems] [Assignment Problems] Computing Limits [Notes] [Practice Problems] [Assignment Problems] Infinite Limits [Notes] [Practice Problems] [Assignment Problems] Limits At Infinity, Part I [Notes] [Practice Problems] [Assignment Problems] Limits At Infinity, Part II [Notes] [Practice Problems] [Assignment Problems] Conti
of a sphere was measured to be 84 cm with a possible error of .5 cm. a) Use differentials to estimate the maximum error in the calculated surface http://www.freemathhelp.com/forum/archive/index.php/t-60934.html?s=81349e7c156e89af0e48100743b7ef6d area. What is the relative error? b) Use differentials to estimate the maximum error in the calculated volume. What is the relative error?" First, I use the circumference to find the radius. since C = 2*pi*r, 84 = 2*pi*r, 42 = pi * r, then r = 42 / pi.. a) dr = .5, A = 4*pi*r^2, dA = 8*pi*(42/pi)*.5 = 168 cm squared maximum differentials to error. total surface area = 2245.99 cm squared = A. dA / A = .07 or 7% b) V = (4/3)*pi*r^3, dV = (4*pi*(42/pi)^2) *.5 = 1122.99 cm cubed maximum error. total volume = 10008.91 cm cubed = V. dV / V = .11 or 11% The answers in the appendix give: for a) 27 cm squared max, .012 relative for b) 179 cm cubed differentials to estimate max, .018 relative Where is my error? soroban04-27-2009, 05:07 AMHello, Jakotheshadows! The circumference of a sphere was measured to be 84 cm with a possible error of 0.5 cm. a) Use differentials to estimate the maximum error in the calculated surface area. What is the relative error? b) Use differentials to estimate the maximum error in the calculated volume. What is the relative error? First, I use the circumference to find the radius. \text{Since }C = 2\pi r,\;84 = 2\pi r \quad\Rightarrow\quad r = \frac{42}{\pi} . Right! a)\;dr = 0.5 . . . . no The answers in the appendix give: . . a)\;27\text{ cm}^2,\;\;0.012 . . b)\;179\text{ cm}^3,\;\;0.018 We have: .C \:=\:2\pi r \quad\Rightarrow\quad dC \:=\:2\pi\,dr\;\;[1] When they measured the circumference, they found that C = 84 cm . . with a possible error of 0.5 cm in the circumference. \text{That is: }\:dC = 0.5 = \tfrac{1}{2} \text{So [1] becomes: }\;\tfrac{1}{2} \:=\:2\pi dr \quad\Rightarrow\quad dr \:=\:\tfrac{1}{4\pi} Now you can give it another try . . . Jakotheshadows04-27-2009, 05:31 PMThank you. I should pay closer attention to the wording. Powered by vBulletin Version 4.2.2 Copyright © 2016 vBulletin Solutions, Inc. All rights reserved.