C Programming Error Implicit Declaration Of Function

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Error Implicit Declaration Of Function 'create_proc_entry'

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Error Implicit Declaration Of Function ‘skb_copy Datagram Iovec’

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Error Implicit Declaration Of Function ‘create_proc_read_entry’

all my functions up vote 1 down vote favorite Here's the code main() { short sMax = SHRT_MAX; int iMax = INT_MAX; long lMax = LONG_MAX; // Printing min and max values for types short, int and long using constants printf("range of short int: %i ... %i\n", SHRT_MIN, SHRT_MAX); printf("range of int: %d ... %d\n", INT_MIN, INT_MAX); printf("range of long int: %ld ... %ld\n", LONG_MIN, LONG_MAX); error implicit declaration of function ‘strnicmp’ // Computing and printing the same values using knowledge of binary numbers // Short int computed_sMax = computeShort() / 2; printf("\n Computed max and min short values: \n %i ... ", computed_sMax); int computed_sMin = (computeShort()/2 + 1) * -1; printf("%i\n", computed_sMin); //Int int computed_iMax = computeInt() / 2; printf("\n Computed min and max int values: \n %i ... ", computed_iMax); int computed_iMin = computeInt() / 2; printf("%i", computed_iMin); return 0; } int computeShort() { int myShort = 0; int min = 0; int max = 16; for (int i = min; i < max; i++) { myShort = myShort + pow(2, i); } return myShort; } int computeInt() { int myInt = 0; int min = 0; int max = 32; for (int i = min; i < max; i++) { myInt = myInt + pow(2, i); } return myInt; } c share|improve this question edited Mar 6 '13 at 11:14 Kaunteya 7851233 asked Mar 6 '13 at 10:50 papercuts 4401613 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote accepted You have to declare the functions before you use them: int computeShort(); // declaration here int main() { computeShor

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring error implicit declaration of function ‘generic_file_aio_read’ developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question error implicit declaration of function ‘memcpy_toiovec’ x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join error implicit declaration of function ‘printf’ them; it only takes a minute: Sign up c - warning: implicit declaration of function ‘printf’ up vote 24 down vote favorite 3 I know alot of similar questions were asked before but i couldn't find something that would fix http://stackoverflow.com/questions/15245284/error-implicit-declaration-of-function-on-all-my-functions this warning i get: MyIntFunctions.c:19:2: warning: implicit declaration of function ‘printf’ [-Wimplicit-function-declaration] Occurs here: void IntPrint (const void *key) { printf("%d", *(int*)key); // line 19 printf("\t-->\t"); } and a similar warning: MyStringFunctions.c:22:2: warning: implicit declaration of function ‘printf’ [-Wimplicit-function-declaration] void StringPrint (const void *key) { printf("%s",(char*)key); //line 22 printf("\t-->\t"); } I really want to understand what is wrong so i won't do that again in the future. c share|improve this question asked Dec 28 '12 at 11:59 Tom 2,264124694 http://stackoverflow.com/questions/14069226/c-warning-implicit-declaration-of-function-printf 3 Did you consider including –WhozCraig Dec 28 '12 at 12:00 2 Please show us how do you include header file. –Adam Sznajder Dec 28 '12 at 12:01 add a comment| 3 Answers 3 active oldest votes up vote 39 down vote accepted You need to include the appropriate header #include If you're not sure which header a standard function is defined in, the function's man page will state this. share|improve this answer answered Dec 28 '12 at 12:00 simonc 33.2k45580 add a comment| up vote 8 down vote Yo need to include a declaration of printf function. #include share|improve this answer answered Dec 28 '12 at 12:03 oleg_g 34615 add a comment| up vote 1 down vote the warning or error of kind IMPLICIT DECLARATION is that the compiler is expecting a Function Declaration/Prototype.. It might either be a header file or your own function Declaration.. share|improve this answer answered Dec 28 '12 at 13:33 Raghu Srikanth Reddy 1,99872035 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service. Not the answer you're looking for? Browse other questions tagged c or ask you

Programming Boards C Programming Compiler error: warning: implicit declaration of function 'strdup' Getting started with C or C++ | C Tutorial | C++ Tutorial | C and C++ FAQ | http://cboard.cprogramming.com/c-programming/95462-compiler-error-warning-implicit-declaration-function-strdup.html Get a compiler | Fixes for common problems Thread: Compiler error: warning: implicit declaration http://www.dummies.com/programming/c/how-to-prototype-a-function-in-c-programming/ of function 'strdup' Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 11-06-2007 #1 TalonStriker View Profile View Forum Posts Registered User Join Date Nov 2007 Posts 23 Compiler error: warning: implicit declaration of function 'strdup' Hi guys, When I compile this code, error implicit I'm getting the following error: warning: implicit declaration of function 'strdup' I've included and so I shouldn't be getting the error right? The line of code in question is: Code: //some declarations inside a static function simple_path = strdup(path); Any help is appreciated. Thanks EDIT: Here's a entire function until the point of the error: Code: #include #include #include #include /* some other functions*/ static error implicit declaration Item * parse(Item * const root, Item * const curr, char * path) { char *simple_path; char *a, *b; char temp[80] = {0}; Item * true_item = NULL; int finished = 0; simple_path = strdup(path); //error here //blah blah 11-06-2007 #2 brewbuck View Profile View Forum Posts Officially An Architect Join Date Mar 2007 Location Portland, OR Posts 7,396 Originally Posted by TalonStriker I've included and so I shouldn't be getting the error right? I've seen environments where strdup() was declared in stdlib.h instead of string.h where it was supposed to be. Alternatively, you could be banging up against Microsoft's stupid attempts to "make C secure," by deprecating basic language functions. Do you happen to be compiling with a MS compiler? EDIT: Haha, nevermind. I forgot that strdup() isn't standard C, so if your compiler doesn't support it... That's tough. Write it yourself: Code: char *strdup(const char *str) { int n = strlen(str) + 1; char *dup = malloc(n); if(dup) { strcpy(dup, str); } return dup; } 11-06-2007 #3 TalonStriker View Profile View Forum Posts Registered User Join Date Nov 2007 Posts 23 Well I'm using the gcc compiler. Originally Posted by brewbuck EDIT: Haha, nevermind. I forgot that strdup() isn't standard C, so if your compiler doesn't su

WorkSocial MediaSoftwareProgrammingWeb Design & DevelopmentBusinessCareersComputers Online Courses B2B Solutions Shop for Books San Francisco, CA Brr, it´s cold outside Search Submit Learn more with dummies Enter your email to join our mailing list for FREE content right to your inbox. Easy! Your email Submit RELATED ARTICLES How to Prototype a Function in C Programming C For Dummies, 2nd Edition C All-in-One Desk Reference For Dummies Objective-C Programming For Dummies Beginning Programming with C For Dummies Load more ProgrammingCHow to Prototype a Function in C Programming How to Prototype a Function in C Programming Related Book Beginning Programming with C For Dummies By Dan Gookin What happens when you don't prototype? As with anything in C programming, when you goof up, the compiler or linker lets you know with an error message -- or the program just doesn't run properly. It's not the end of the world -- no, not like programming a military robot or designing genetic code for a new species of Venus flytrap. BASIC FUNCTION; NO RETURN #include void prompt(); /* function prototype */ int main() { int loop; char input[32]; loop=0; while(loop<5) { prompt(); fgets(input,31,stdin); loop=loop+1; } return(0); } /* Display prompt */ void prompt() { printf("C:\DOS> "); } Exercise 1: Modify the source code from Basic Function; No Return. Comment out the prototype from Line 3. Build the result. Compiler errors are wonderful things, delightfully accurate yet entirely cryptic. Here is the error message generated by Code::Blocks, although only the relevant parts of the message: 13 Warning: implicit declaration of function 'prompt' 23 Warning: conflicting types for 'prompt' 13 Warning: previous implicit declaration of 'prompt' was here The first warning occurs at Line 13 in the source code file, where the prompt() function is used inside the main() function. The compiler is telling you that you're using a function without a prototype. As the error message says, you're implicitly declaring a function. That's a no-no, but not a full-on error. The second warning occurs where the prompt() function dwells in the program. In the source code, it's at Line 23. The warning states that prompt() was already declared (at Line 11) and that the second use may conflict with the first. The final warning is a reference back to where the function was called, again at Line 13. To put it succinctly: The compiler has no idea what's up with the prompt() function. Your code compiles, but running it is risky. You may draw the conclusion that prototyping is an absolute necessity in your C code. That's not enti