Propagation Of Error Addition And Subtraction
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or more quantities, each with their individual uncertainties, and then combine the information from these quantities in order to come up with a final result of our experiment. How can you error propagation formula physics state your answer for the combined result of these measurements and their
Error Propagation Square Root
uncertainties scientifically? The answer to this fairly common question depends on how the individual measurements are combined in the
Error Propagation Chemistry
result. We will treat each case separately: Addition of measured quantities If you have measured values for the quantities X, Y, and Z, with uncertainties dX, dY, and dZ, and your
Error Propagation Inverse
final result, R, is the sum or difference of these quantities, then the uncertainty dR is: Here the upper equation is an approximation that can also serve as an upper bound for the error. Please note that the rule is the same for addition and subtraction of quantities. Example: Suppose we have measured the starting position as x1 = 9.3+-0.2 m error propagation average and the finishing position as x2 = 14.4+-0.3 m. Then the displacement is: Dx = x2-x1 = 14.4 m - 9.3 m = 5.1 m and the error in the displacement is: (0.22 + 0.32)1/2 m = 0.36 m Multiplication of measured quantities In the same way as for sums and differences, we can also state the result for the case of multiplication and division: Again the upper line is an approximation and the lower line is the exact result for independent random uncertainties in the individual variables. And again please note that for the purpose of error calculation there is no difference between multiplication and division. Example: We have measured a displacement of x = 5.1+-0.4 m during a time of t = 0.4+-0.1 s. What is the average velocity and the error in the average velocity? v = x / t = 5.1 m / 0.4 s = 12.75 m/s and the uncertainty in the velocity is: dv = |v| [ (dx/x)2 + (dt/t)2 ]1/2 = 12.75 m/s [(0.4/5.1)2 + (0.1/0.4)2]1/2 = 3.34 m/s Multiplication with a constant What if y
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find that the error in this measurement is 0.001 in. To find the area we multiply the width (W) and length (L). The area then is L x W = (1.001 in) x (1.001 in) = 1.002001 in2 which rounds to 1.002 in2. This http://www.utm.edu/~cerkal/Lect4.html gives an error of 0.002 if we were given that the square was exactly super-accurate 1 inch a side. This is an example of correlated error (or non-independent error) since the error in L and W are the same. The error in L is correlated with that of in W. Now, suppose that we made independent determination of the width and length separately with an error of 0.001 in each. In this case where two independent measurements are performed the errors are independent or error propagation uncorrelated. Therefore the error in the result (area) is calculated differently as follows (rule 1 below). First, find the relative error (error/quantity) in each of the quantities that enter to the calculation, relative error in width is 0.001/1.001 = 0.00099900. The resultant relative error is Relative Error in area = Therefore the absolute error is (relative error) x (quantity) = 0.0014128 x 1.002001=0.001415627. which rounds to 0.001. Therefore the area is 1.002 in2± 0.001in.2. This shows that random relative errors do propagation of error not simply add arithmetically, rather, they combine by root-mean-square sum rule (Pythagorean theorem). Let’s summarize some of the rules that applies to combining error when adding (or subtracting), multiplying (or dividing) various quantities. This topic is also known as error propagation. 2. Error propagation for special cases: Let σx denote error in a quantity x. Further assume that two quantities x and y and their errors σx and σy are measured independently. In this case relative and percent errors are defined as Relative error = σx / x, Percent error = 100 (σx / x) Multiplying or dividing with a constant. The resultant absolute error also is multiplied or divided. Multiplication or division, relative error. Addition or subtraction: In this case, the absolute errors obey Pythagorean theorem. If a and b are constants, If there are more than two measured quantities, you can extend expressions provided above by adding more terms under the square root sign. Square or cube of a measurement : The relative error can be calculated from where a is a constant. Example 1: Determine the error in area of a rectangle if the length l=1.5 ±0.1 cm and the width is 0.42±0.03 cm. Using the rule for multiplication, Example 2: The area of a circle is proportional to the square of the radius. If the radius is determined as r = 10.0 ±0.3 cm, what is the uncertainty in the
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