Php Code Error Reporting
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Php Hide Errors
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Php Display Errors Off
hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges php error message Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each php error checker other. Join them; it only takes a minute: Sign up How do I get PHP Errors to display? up vote 679 down vote favorite 204 I have checked my PHP ini file and display errors is set and also http://php.net/manual/en/function.error-reporting.php error reporting is E_ALL. I have restarted my apache web server. I have even put these lines at the top of my script and it doesn't even catch simple parse errors. For example, I declare variables with a "$" and I don't close statements";". But all my scripts show a blank page on these errors, but i want to actually see the errors in my browser output. error_reporting(E_ALL); ini_set('display_errors', 1); What is left to do? php error-reporting share|improve http://stackoverflow.com/questions/1053424/how-do-i-get-php-errors-to-display this question edited Mar 9 at 7:16 Maninderpreet Singh 1,7111524 asked Jun 27 '09 at 19:09 Abs 13.4k68209356 3 I've yet to nail down exactly why this works sometimes and not others, but for anyone wanting to quickly toggle errors in a php script (or enable them via a $_REQUEST parameter) these two lines will work most of the time. –brandonscript Oct 28 '13 at 20:15 well you can see details of the error by enabling xdebug from php ini file. –jewelhuq Jan 13 at 10:14 add a comment| 13 Answers 13 active oldest votes up vote 1359 down vote accepted This always works for me: ini_set('display_errors', 1); ini_set('display_startup_errors', 1); error_reporting(E_ALL); However, this doesn't make PHP to show parse errors - the only way to show those errors is to modify your php.ini with this line: display_errors = on share|improve this answer edited Oct 23 '15 at 12:24 tleb 1,173721 answered Jan 29 '14 at 11:25 Fancy John 14k2915 4 why is this not the best answer? –özg Jul 4 '14 at 11:52 13 @özg Because this configuration doesn't show parser errors (errors due to syntactically incorrect scripts --e.g: ill-formed scripts). The Zend parser (the one used by php) is executed before the script is executed. So, if the script has syntactic errors, these ini_set directives are never executed and every existing syntactic error is
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About http://stackoverflow.com/questions/16933606/error-reportinge-all-does-not-produce-error Us Learn more about Stack Overflow the company Business Learn more about hiring http://www.kreci.net/web-development/how-to-enable-error-reporting-in-php-script/ developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up error_reporting(E_ALL) does not produce error up php error vote 24 down vote favorite 3 This is my php script- ' ;. $thisdoesnotexist); ?> Which obviously should show something if it were to be executed. All I see is an empty page. Why is error_reporting(E_ALL) not working? ' ;. $thisdoesnotexist); ?> Does not help either. All I get is an empty page. I've php code error been to php.ini and set display_errors = On and display_startup_errors = On. Nothing happens. php share|improve this question edited Jun 5 '13 at 7:20 asked Jun 5 '13 at 7:07 Samik Sengupta 56761333 How is display_errors setup? –PeeHaa Jun 5 '13 at 7:09 check display_errors setting –Roman Newaza Jun 5 '13 at 7:09 Does not help, as I've reflected in my question edit. –Samik Sengupta Jun 5 '13 at 7:11 You can check your syntax first by running php -l
PHP script Published on May 6, 2009 in Misc and Web development. Tweet If error reporting is disabled by default on your host you have two solutions. First is to add to your PHP script this little piece of code: Additionally it is very useful to enable E_STRICT reporting level as well (not included in E_ALL). E_STRICT run-time notices, enable to have PHP suggest changes to your code which will ensure the best interoperability and forward compatibility of your code. To turn it on your code should look like this: But putting this code on the top of your script will not catch any parse errors. A missing ")" or ";" will still lead to a blank page. This is because the entire script is parsed before any of it is executed. If you are unable to change php.ini (that would be the best solution) and set in it
display_errors On
then there is a possible workaround (found on comments on php.net website). This code would solve this problem: You may go even further and make a little debug script with error reporting (when it is disabled for the rest of your scripts). Just create a file called "debug.php" with this content: Then you will be able to execute any script on your web host just by calling "debug.php" with urls like this http://domain.com/folder/debug.php?file=file_with_errors.php http://domain.com/folder/debug.php?file=subfolder/file_with_errors.php http://domain.com/folder/debug.php?file=../file_with_errors.php Second alternative soulution is to edit your .htaccess file. It would enable error reporting for all files in current directory. All you need to do is to simply add the following lines:
php_value display_errors 1
php_value display_startup_errors 1
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