Access 2010 Vba Runtime Error 91
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Excel Vba Runtime Error 91
policies of this site About Us Learn more about Stack Overflow the company Business Learn excel vba runtime error 91 find more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community vba runtime error 1004 Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Why do I get Run-time Error 91 in this MS Access code? up vote 1 down vote favorite So, I have a MS Access database application. In
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this application is a main form, which contains a number of subforms. One form in particular has a drop down box that I populate with dates from a database query. When one of these dates is selected, I run a subroutine that is supposed to update a recordset on the subform with history information. Below is some edited code (just removed the large number of fields from the queries) Private Sub pickdate_AfterUpdate() ''''''''''''''''''''''''''''''''''''''''' ' Add review history by selected date ''''''''''''''''''''''''''''''''''''''''' Dim rs As Recordset Set rs = CurrentDb.OpenRecordset("SELECT model, entered_date FROM history WHERE entered_date=#" & Me.pickdate.value & "# ORDER BY model DESC", dbOpenDynaset, dbSeeChanges) If rs.BOF = False Then rs.MoveFirst While rs.EOF = False Forms!main!histories.Form.Recordset.AddNew Forms!main!histories.Form.Recordset![model] = rs![model] Forms!main!histories.Form.Recordset![entered_date] = rs![entered_date] Forms!main!histories.Form.Recordset.Update rs.MoveNext Wend End Sub I get the error on the Forms!main!histories.Form.Recordset.AddNew line. I have tried the following versions of that line: Forms!main!histories.Form.Recordset.AddNew main!histories.Form.Recordset.AddNew histories.Form.Recordset.AddNew Me.Form.Recordset.AddNew Me.Recordset.AddNew Me.AddNew Me.main
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Run Time Error 91 Vba
Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up VBA ACCESS error 91 object variable http://stackoverflow.com/questions/12205496/why-do-i-get-run-time-error-91-in-this-ms-access-code or with block variable not set up vote 1 down vote favorite In a form, when pressing a button called "asignar", I want to insert values to an existing table called "movimientos" Private Sub ASIGNAR_Click() Dim db As Database Dim rs As DAO.Recordset Set rs = db.OpenRecordset("MOVIMIENTOS") rs.AddNew rs("ESTATUSDOC").Value = "Blah" rs("FOLIOFED").Value = "Blah" rs("NOMBREDOC").Value = "Blah" rs("PREL").Value = "Blah" rs("CURP").Value = "Blah" rs.Update End Sub http://stackoverflow.com/questions/31274060/vba-access-error-91-object-variable-or-with-block-variable-not-set When I press run it keep showing error: Error 91 object variable or with block variable not set vba ms-access share|improve this question edited Jul 7 '15 at 16:37 Newd 2,0061928 asked Jul 7 '15 at 16:14 Adan Lopez 84 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted I think your syntax is a little off, your code should look like this: Private Sub ASIGNAR_Click() Dim db As DAO.Database Dim rs As DAO.Recordset Set db = CurrentDb Set rs = db.OpenRecordset("MOVIMIENTOS", dbOpenDynaset, dbAppendOnly) rs.AddNew rs("ESTATUSDOC").Value = "Blah" rs("FOLIOFED").Value = "Blah" rs("NOMBREDOC").Value = "Blah" rs("PREL").Value = "Blah" rs("CURP").Value = "Blah" rs.Update rs.Close Set rs = Nothing Set db = Nothing End Sub The issue likes like is primarily the way that you were declaring and setting your db variable. I have also adjusted the OpenRecordset to match what you are doing. share|improve this answer edited Jul 8 '15 at 12:11 answered Jul 7 '15 at 16:23 Newd 2,0061928 All good, though don't forget to close opened recordsets rs.Close and clean your memory with Set rs = Nothing and Set db = Nothing –Matt Hall Jul 7 '15 at 22:
+ Ask a Question Need help? Post your question and get tips & solutions from a community of 418,417 IT Pros https://bytes.com/topic/access/answers/506689-run-time-error-91-object-variable-block-variable-not-set & Developers. It's quick & easy. Run-time error 91 Object Variable or With block variable not set P: n/a Richard Hollenbeck I've marked the line in this subroutine where I've been getting this error. It may be something stupid but I've been staring at this error trying to fix it for over an hour. I'm pretty sure the table and field names time error and controls are all named correctly, and the control referred to in the errant code is open, and it has data in it. Private Sub cmdAddIngredientToRecipe_Click() ' Get RecipeID for future action query Dim recipeID As Long Dim dbGetRecipeID As DAO.Database Dim rsGetRecipeID As DAO.Recordset Dim StrSQL As String Set dbGetRecipeID = CurrentDb() StrSQL = "SELECT tblRecipes.lngRecipeID FROM tblRecipes WHERE (((tblRecipes.lngRecipeID)= " vba runtime error & [Forms]![frmRecipes]![lngRecipeID] & "));" Set rsGetRecipeID = dbGetRecipeID.OpenRecordset(StrSQL, dbOpenDynaset) recipeID = rsGetRecipeID.Fields(0) Set rsGetRecipeID = Nothing Set dbGetRecipeID = Nothing ' This works fine to this point ' Get IngredientID for future action query Dim IngredientID As Long Dim dbGetIngredientID As DAO.Database Dim rsGetIngredientID As DAO.Recordset 'I'm filling variables to use in an append query down later in this subroutine. StrSQL = "SELECT tblIngredients.lngIngredientID FROM tblIngredients WHERE tblIngredients.IngredientName = '" & cboIngredientName & "'" 'IngredientName is a text field. ' The next line is flagged as a problem. I get a run-time error 91" Object Variable ' or with block variable not set. I'm predicting something is wrong with my SQL statament on the previous line. Set rsGetIngredientID = dbGetIngredientID.OpenRecordset(StrSQL, dbOpenDynaset) IngredientID = rsGetIngredientID.Fields(0) Set rsGetRecipeID = Nothing Set dbGetRecipeID = Nothing MsgBox IngredientID 'just to test my code this far. End Sub Jun 29 '06 #1 Post Reply Share this Question 3 Replies P: n/a John Mishefske Richard Hollenbeck wrote: I've marked the line in this subroutine where I've been getting this error. It may be something stupid but I've been staring