Divide Error Overflow
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Divide Overflow Error In Assembly Language
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Divide Overflow Ensamblador
them; it only takes a minute: Sign up error like this divide error - overflow. to manually process this error, change address of INT 0 in interrupt vector table up vote 2 down vote favorite .model small .stack 100h divide overflow error in dos .data number dw '12345' result db 15 dup('$') .code main proc mov ax,@data mov ds,ax mov ax,number mov bx,offset result mov cx,0 l1: mov dx,0 div cx add dx,48 push dx inc cx cmp ax,0 jne l1 l2: pop dx mov [bx],dl inc bx loop l2 mov ah,9 mov dx,offset result int 21h mov ax,4c00h int 21h main endp end main assembly x86 ms-dos share|improve this question edited Aug 29 '14 at 6:12 Ross Ridge 17.8k22050 asked Aug 29 divide overflow error ghost '14 at 6:07 Mohammad Sadiq 142 Why are there single quotes around 12345? –Michael Aug 29 '14 at 6:12 You should put a question in your post. What are you trying to do? What have you tried so far? What went wrong? –Ross Ridge Aug 29 '14 at 6:14 Please comment your code –User.1 Aug 29 '14 at 8:02 add a comment| 1 Answer 1 active oldest votes up vote 2 down vote I assume you are using EMU8086. The error happens at div cx. This instruction means: AX = DX:AX / CX. If CX is zero, you get a "divide by zero error" - in EMU8086-syntax: "divide error - overflow.". You have at least to take care that CX won't become zero. share|improve this answer answered Aug 29 '14 at 8:33 rkhb 7,55271628 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service. Not the answer you're looking for? Browse other questions tagged assembly x86 ms-dos or ask your own question. asked 2 years ago viewed 1046 times active 2 years ago Related 1assembly x86 Using stack's value as pointer?08086 A
by 0" or "Divide Overflow" error messages. The divide error messages are caused when the computer or software attempts run a
Your Program Caused A Divide Overflow Error
process that attempts to perform a mathematical division by zero, which is divide by zero or overflow error an illegal operation. This error message could also be caused by a computer or software limitation or conflict
Divide Overflow Is Generated When
with computer memory. Improper calculation If you or the program you are using performs a calculation in any program and experience a divide error, ensure that the calculation being performed is http://stackoverflow.com/questions/25562535/error-like-this-divide-error-overflow-to-manually-process-this-error-change possible. Some programs are not capable of verifying the accuracy of a calculation and may perform an illegal instruction. Programs such as Microsoft Excel, will generate a #DIV!0 error indicating the formula or calculation is invalid, or you are attempting to divide by zero. Hardware or software incompatibility This issue can occur if software is being run on a computer that http://www.computerhope.com/issues/ch000396.htm has hardware that is incompatible with the software. For example, this issue may occur with restore software designed for a specific computer and is being run on another computer or on the correct computer that has added hardware within it. Make sure all software installed on the computer is up to date and fully compatible with the system. Driver issue If you are encountering a divide error while using Windows, make sure you are running the latest drivers and software for all component hardware devices. Verify the video card, sound card, network card and modem drivers on the computer. You can find a listing of computer drivers on our driver page. Software issue If the divide error happens while in a game or program and the above recommendations does not resolve your issue, verify all software patches and upgrades have been obtained and applied. Also, verify no other program is running in the background that could be causing your problem by End Tasking all background programs and TSRs. External cache or 2nd level cache If you are encountering the divide error
when you try to preform division by zero. This is an illegal operation and causes an exception. Posted on 2006-04-17 09:36:25 by Synfire Re: divide overflow From "Art of Assembly"Division by zero and Division Overflow (they're NOT the same thing):You cannot, on the 80x86, simply divide one http://www.asmcommunity.net/forums/topic/?id=24616 eight bit value by another. If the denominator is an eight bit value, the numerator must http://www.programmingforums.org/post12771.html be a sixteen bit value. If you need to divide one unsigned eight bit value by another, you must zero extend the numerator to sixteen bits. You can accomplish this by loading the numerator into the al register and then moving zero into the ah register. Then you can divide ax by the denominator operand to produce the correct result. Failing to zero extend al before executing divide overflow div may cause the 80x86 to produce incorrect results! When you need to divide two 16 bit unsigned values, you must zero extend the ax register (which contains the numerator) into the dx register. Just load the immediate value zero into the dx register12. If you need to divide one 32 bit value by another, you must zero extend the eax register into edx (by loading a zero into edx) before the division. When dealing with signed integer values, you will need to sign divide overflow error extend al to ax, ax to dx or eax into edx before executing idiv. To do so, use the cbw, cwd, cdq, or movsx instructions. If the H.O. byte or word does not already contain significant bits, then you must sign extend the value in the accumulator (al/ax/eax) before doing the idiv operation. Failure to do so may produce incorrect results. There is one other catch to the 80x86’s divide instructions: you can get a fatal error when using this instruction. First, of course, you can attempt to divide a value by zero. Furthermore, the quotient may be too large to fit into the eax, ax, or al register. For example, the 16/8 division “8000h / 2??? produces the quotient 4000h with a remainder of zero. 4000h will not fit into eight bits. If this happens, or you attempt to divide by zero, the 80x86 will generate an int 0 trap. This usually means BIOS will print “division by zero??? or “divide error??? and abort your program. If this happens to you, chances are you didn’t sign or zero extend your numerator before executing the division operation. Since this error will cause your program to crash, you should be very careful about the values you select when using division. Posted on 2006-04-17 23:48:27 by ti_mo_n Re: divide overflow The "Divide Overflow" or "Divide by Zero" is an exception that occurs when you try to preform division by zero. This is an illegal operation and causes an exception.Divide Overflow is no
Thread Tools Display Modes Dec 8th, 2004, 10:45 PM #1 saxman Newbie Join Date: Dec 2004 Posts: 7 Rep Power: 0 I'm not new to x86 ASM, but I am new to the square-root-related instructions that Intel has provided. I don't know what I'm doing wrong in my program, but I get a divide overflow. Perhaps someone could take a look at my code and see what is causing this. This program isn't finished yet, but it's going to draw a sphere. I am doing it purely out of experimental interest. Right now I am just trying to get it to draw pixels to the screen, but I won't know if my algorithms and such are right or not if I can't see anything but an error. I wonder if it's the way I've used the square-root. This is the first time I've made use of it in ASM, so I don't even know if I did it right or not. Anyway, any help would be appreciated. BTW: If you find the below code to be hard to read due to the lack of 'tabs' on these forums, you can download the source file -- http://shadowsoft-games.com/saxman/3D.ASM (Toggle Plain Text) ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ; This program is designed to draw a sphere using the following: ; ; Ymax = (Ry/Rx) SQRT(Rx^2 - X^2) ; Zmax = (Rz/Ry) SQRT(Ry^2 - Y^2) ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; jmp start xpos* dw ?*; X position (0-319) ypos* db ?*; Y position (0-199) zpos* db ?*; Z position (0-255) xrad* db 64*; X radius (0-255) yrad* db 64*; Y radius (0-255) zrad* db 64*; Z radius (0-255) store1 dd ?*; Used to store a floating-point ymax* db ?*; Ymax = (Ry/Rx) SQRT(Rx^2 - X^2) zmax* db ?*; Zmax = (Rz/Ry) SQRT(Ry^2 - Y^2) palette db 00, 00, 00, 01, 01, 01, 02, 02, 02, 03, 03, 03 * db 04, 04, 04, 05, 05, 05, 06, 06, 06, 07, 07, 07 * db 08, 08, 08, 09, 09, 09, 10, 10, 10, 11, 11, 11 * db 12, 12, 12, 13, 13, 13, 14, 14, 14, 15, 15, 15 * db 16, 16, 16, 17, 17, 17, 18, 18, 18, 19, 19, 19 * db 20, 20, 20, 21, 21, 21, 22, 22, 22, 23, 23, 23 * db 24, 24, 24, 25, 25, 25, 26, 26, 26, 27, 27, 27 * db 28, 28, 28, 29, 29, 29, 30, 30, 30, 31, 31, 31 * db 32, 32, 32, 33, 33, 33, 34, 34, 34, 35, 35, 35 * db 36, 36, 36, 37, 37, 37, 38