Error Does Not Name A Type Cpp
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C++ Error Does Not Name A Type
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C++ Does Not Name A Type Struct
the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up “does not name a type” c++ does not name a type typedef error up vote 54 down vote favorite 13 I have two classes declared as below: class User { public: MyMessageBox dataMsgBox; }; class MyMessageBox { public: void sendMessage(Message *msg, User *recvr); Message receiveMessage(); vector
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C++ Does Not Name A Type Constructor
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Vector Does Not Name A Type C++
Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up `does not name a type` error in C++ up vote 8 down http://stackoverflow.com/questions/2133250/does-not-name-a-type-error vote favorite 2 I don't know what to search to find an explanation for this, so I am asking. I have this code which reports error: struct Settings{ int width; int height; } settings; settings.width = 800; // 'settings' does not name a type error settings.height = 600; // 'settings' does not name a type error int main(){ cout << settings.width << " " << settings.height << endl; but http://stackoverflow.com/questions/16938810/does-not-name-a-type-error-in-c if I put the value assignment in main, it works: struct Settings{ int width; int height; } settings; main () { settings.width = 800; // no error settings.height = 600; // no error Can you explain me why? EDIT: Regarding to Ralph Tandetzky's answer, here is my full struct code. Could you show me how to assign the values as you did with my snippet struct? struct Settings{ struct Dimensions{ int width; int height; } screen; struct Build_menu:Dimensions{ int border_width; } build_menu; } settings; c++ class struct variable-assignment share|improve this question edited Jun 5 '13 at 11:49 asked Jun 5 '13 at 11:31 Qwerty 4,36413042 add a comment| 2 Answers 2 active oldest votes up vote 17 down vote accepted You cannot put assignments outside the context of a function in C++. If you're puzzled by the fact that you sometimes saw the = symbol being used outside the context of a function, such as: int x = 42; // <== THIS IS NOT AN ASSIGNMENT! int main() { // ... } That's because the = symbol can be used for initialization as well. In your example, you are not initializing the data members width and height, you are assigning a value to them. share|i
topic ForumsMembersHelp Files Developer Journals Gallery Calendar Downloads Resources Store Classifieds Tracker Links Home For Beginners Articles All Articles Post an Article Technical http://www.gamedev.net/topic/673194-object-member-does-not-name-a-type-c/ Game Programming General Programming Graphics Programming and Theory DirectX and XNA OpenGL and Vulkan Multiplayer and Network Programming Artificial Intelligence Math and Physics Mobile Development Middleware, Libraries, and Tools Virtual and http://arduino.stackexchange.com/questions/12304/arduino-raise-the-error-does-not-name-a-type-when-an-object-is-used-outside-o Augmented Reality Creative Game Design Music and Sound Visual Arts Business Breaking into the Industry Production and Management Interviews Business and Law Event Coverage Forums All Forums Technical Game Programming does not General Programming Graphics Programming and Theory DirectX and XNA OpenGL & Vulkan Multiplayer and Network Programming Artificial Intelligence Math and Physics Mobile & Console Development Build Systems & Source Control Middleware, Libraries, and Tools Virtual and Augmented Reality Creative Game Design Writing For Games Music and Sound Visual Arts Gallery Business Breaking into the Industry Business & Law Production & Management Community does not name GDNet Lounge Coding Horrors Article Writing Comments, Suggestions and Ideas Your Announcements Hobby Project Classifieds Indie Project Showcase Community Developer Journals GDNet+ Subscriptions Gallery Store Classifieds Jobs Freelancers Hobby Projects Marketplace Newsletter » Home » Forums » The Technical Side » For Beginners Chat Watched Content New Content 1 Object member does not name a type C++ Started by UAas, Nov 14 2015 12:26 PM Old topic! Guest, the last post of this topic is over 60 days old and at this point you may not reply in this topic. If you wish to continue this conversation start a new topic. You cannot reply to this topic 13 replies to this topic #1 UAas Members -Reputation: 208 Like 0Likes Like Posted 14 November 2015 - 12:26 PM I actually have two errors and i hope i can get an explination of why this doesn't work and how i can make them work. The error And my code PP.h #ifndef PP_H #define PP_H #include "person.h" #include "nameRandomizer.h" #include
a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Arduino beta Questions Tags Users Badges Unanswered Ask Question _ Arduino Stack Exchange is a question and answer site for developers of open-source hardware and software that is compatible with Arduino. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Arduino raise the error: `does not name a type` when an Object is used outside of the main two blocks setup and loop up vote 0 down vote favorite I have this: class Person{ public: int age; }; Person p; p.age; void setup() { ... } void loop() { ... } And I got this error: Compiling 'MyProgram' for 'Arduino Mega w/ ATmega2560 (Mega 2560)' MyProgram.ino:18:1: error: 'p' does not name a type Error compiling But is I use the Person instance inside setup or loop functions it compiles find. void setup() { // initialize digital pin 13 as an output. Person p; p.age; } I got this: Compiling 'MyProgram' for 'Arduino Mega w/ ATmega2560 (Mega 2560)' Binary sketch size: 4,674 bytes (used 2% of a 253,952 byte maximum) (3.45 secs) Minimum Memory Usage: 428 bytes (5% of a 8192 byte maximum) What is the different? Why the instance only can be used into the blocks? I also declared a file with a simple class and then create a instance of it class outside the blocks and I got the same error. If I put the instance inside the blocks it works. So, any tips? arduino-mega variables class share|improve this question asked Jun 2 '15 at 0:19 Robert 11919 add a comment| 2 Answers 2 active oldest votes up vote 1 down vote accepted As you have already noticed, you cannot call methods of a class, nor access its properties, outside a "block" (as you call it). More specifically, you can only perform "programatical" operations from within a function. Anything outside a function (known as the global scope) is purely for declaration and initialization of variables and types, etc. Any class variables declared in the global scope have their constructor executed before the rest of the program (even before setup) gets run. However, setup is not the first function to be called at startup. Anything you put into a constructor has to take into account the fact that anything might be happening between the constructor being called and the object instance actually b