Error 2023 Excel Vba

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Excel Vba Erreur 2023

or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow vba cverr Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Evaluate() Function Returning Error 2023, however there is

Application.caller Error 2023

no error up vote 0 down vote favorite I am using the Evaluate() function to test a value for errors prior to placing into a cell. In my example below, this is returning Error 2023, However when I paste the string into a cell, it reads correctly with no error (will return exactly the value referenced in the external spreadsheet). The example is as follows: Evaluate("='H:\@Projects\@Dev[BudgetTracking_ProjectName_MSTR_FK_2.xlsm]Budget Estimate executeexcel4macro error 2023 (2)'!F44") excel vba function evaluate share|improve this question edited Jan 22 '15 at 5:49 L42 12.4k52143 asked Jan 22 '15 at 5:42 Y2kShea 104 If this is a followup question to Determine if formula will return #Ref! error then use of Evaluate where the formula you want to test refers to a closed workbook will not work. An alternative might be to use Application.DisplayAlerts = False and just write the formula to the cell then test for #Ref!. This will suppress to File Open dialog. (Remember to Application.DisplayAlerts = True after) –chris neilsen Jan 22 '15 at 6:53 That is a great approach, Chris. The function does work, but there is another handling tier of this thing that I need to work the logic out for and this suggestion I think will be really useful. Thank you –Y2kShea Jan 26 '15 at 2:09 add a comment| 1 Answer 1 active oldest votes up vote 0 down vote accepted The Error 2023 is the xlErrRef #REF!. The Evaluate function can't directly evaluate from closed workbooks. Open the H:\@Projects\@Dev\BudgetTracking_ProjectName_MSTR_FK_2.xlsm and Evaluate("='H:\@Projects\@Dev\[BudgetTracking_ProjectName_MSTR_FK_2.xlsm]Budget Estimate (2)'!F44") will work. Note the "\" behind the directory name "@Dev". But then of course Evaluate("='[BudgetTracking_ProjectNam

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Excel 2010 Vba Error 2023

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Vba Error 2023 Evaluate

more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us error 2032 Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like http://stackoverflow.com/questions/28081972/evaluate-function-returning-error-2023-however-there-is-no-error you, helping each other. Join them; it only takes a minute: Sign up VBA Error Handling: How to bypass line that has error and stops code? up vote 0 down vote favorite I have code that's function is to pull all loans that have "Fail" in a pass/fail column and copy criteria to another workbook. My issue http://stackoverflow.com/questions/27722297/vba-error-handling-how-to-bypass-line-that-has-error-and-stops-code is that the formula determining pass/fail requires a loan number to be in one of the criteria columns, otherwise it returns the value of "Error 2023". With my below code I get a type mismatch error because of the "error 2023". My initial thought is to use the "On Error Resume Next" so that if my value = Error 2023 it would go to the next line and bypass that error only pulling the fails......but I'm new to error handling and not sure exactly how to write this. Is this the right way to go about this issue? assignmentRow = 4 For x = 4 To lastRow Windows("POC Results.xlsm").Activate If Range("BE" & x).Value = "Fail" Then 'goes through workbook checking for "Fail" Range("B" & x, "F" & x).Copy 'copies first criteria and pastes Windows("Failed Audit Assigments.xlsm").Activate Sheets("POC").Range("B" & assignmentRow).PasteSpecial Paste:=xlPasteValues Windows("POC Results.xlsm").Activate Range("BF" & x).Copy 'copies 2nd criteria and pastes Windows("Failed Audit Assigments.xlsm").Activate Sheets("POC").Range("G" & assignmentRow).PasteSpecial Paste:=xlPasteValues assignmentRow = assignmentRow + 1 End If Next x excel-vba error-handling exc

Forums Excel Questions error 2023 Results 1 to 3 of 3 error 2023This is a discussion on error 2023 within the Excel Questions forums, part of the Question Forums category; http://www.mrexcel.com/forum/excel-questions/217130-error-2023-a.html when i'm running the following macro i get error 2023 what does that mean and more importantly how do i ... LinkBack LinkBack URL About LinkBacks Bookmark & Share Digg this Thread!Add Thread to del.icio.usBookmark in TechnoratiTweet this thread Thread Tools Show Printable Version Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Aug 2nd, 2006,05:17 PM #1 meave New Member Join Date error 2023 Aug 2006 Posts 4 error 2023 when i'm running the following macro i get error 2023 what does that mean and more importantly how do i fix it. macro: Code: Sub OneColumnRemoveBlanks() Dim MyColumn As Long, c As Range, i As Integer MyColumn = Selection.Column i = 0 For Each c In Selection If Len(c) > 0 Then Cells(c.Row - i, c.Column + 1) = c.Value vba error 2023 Else i = i + 1 End If Next c End Sub the line If Len(c) > 0 Then gives the error according to visual basics. if someone could help me with this and explain it in simple language (i can just only read macro and understand them, even this one i haven't made myself) i would be very gratefull.[/quote] Share Share this post on Digg Del.icio.us Technorati Twitter Reply With Quote Aug 3rd, 2006,01:28 PM #2 meave New Member Join Date Aug 2006 Posts 4 if have been trying various things today and i noticed that the same macro still works in an older version of my spreadsheet could anyone help me on how this could be solved i'll put. the following macro is excecuting the previous macro. the first is done correctly but somewhere between the first and the fourth it goes wrong. Code: Sub CreateItemValidation() ' ' CreateItemValidation Macro ' Macro recorded 5-8-2005 by Danny Batenburg ' ' Sheets("Equiped Items").Select Union(Range( _ "FL:FL,FN:FN,FP:FP,FR:FR,FT:FT,FV:FV,FX:FX,FZ:FZ,GB:GB,GD:GD,GF:GF,GH:GH,GJ:GJ,GL:GL,GN:GN,GP:GP,DN:DN,DB:DB,DD:DD,DF:DF,DH:DH,DJ:DJ,DL:DL,DN:DN,DP:DP,DR:DR,DT:DT,DV:DV,DX:DX,DZ:DZ,EB:EB,ED:ED" _ ), Range( _ "EF:EF,EH:EH,EJ:EJ,EL:EL,EN:EN,EP:EP,ER:ER,ET:ET,EV:EV,EX:EX,EZ:EZ,FB:FB,FD:FD,FF:FF,FH:FH,FJ:FJ" _ )).Select Selection.ClearContents Range("'Equiped Items'!DA2:DA2000").Select Application.Run _ "'Kopie van Kopie van Kansloos Sheet.xls'!OneColumnRemoveBlanks" Range("'Equiped Items'!DC2:DC2000").Select Application.Run _ "'Kopie van Kopie van Kansloos Sheet.xls'!OneColumnRemoveBlanks" Range("'Equiped Items'!DE2:DE2000").Sele