Excel Vba Error 2023 Evaluate

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Excel 2010 Vba Error 2023

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Vba Excel Error 2023

up Evaluate() Function Returning Error 2023, however there is no error up vote 0 down vote favorite I am using the Evaluate() function to test a value for errors prior to placing into a cell. In my example below, this is returning Error 2023, However when I paste the string into a cell, it reads correctly with no error (will return exactly error 2032 the value referenced in the external spreadsheet). The example is as follows: Evaluate("='H:\@Projects\@Dev[BudgetTracking_ProjectName_MSTR_FK_2.xlsm]Budget Estimate (2)'!F44") excel vba function evaluate share|improve this question edited Jan 22 '15 at 5:49 L42 12.4k52143 asked Jan 22 '15 at 5:42 Y2kShea 104 If this is a followup question to Determine if formula will return #Ref! error then use of Evaluate where the formula you want to test refers to a closed workbook will not work. An alternative might be to use Application.DisplayAlerts = False and just write the formula to the cell then test for #Ref!. This will suppress to File Open dialog. (Remember to Application.DisplayAlerts = True after) –chris neilsen Jan 22 '15 at 6:53 That is a great approach, Chris. The function does work, but there is another handling tier of this thing that I need to work the logic out for and this suggestion I think will be really useful. Thank you –Y2kShea Jan 26 '15 at 2:09 add a comment| 1 Answer 1 active oldest votes up vote 0 down vote accepted The Error 2023 is the xlErrRef #REF!. The Evaluate functio

Forums Excel Questions Error 2023 with EVALUATE Results 1 to 6 of 6 Error 2023 with EVALUATEThis is a discussion on Error 2023 with EVALUATE within the Excel Questions forums, part of the Question Forums category; ... LinkBack LinkBack URL About LinkBacks Bookmark & Share Digg this Thread!Add Thread to del.icio.usBookmark in TechnoratiTweet this thread Thread Tools Show Printable Version Display Linear Mode Switch to Hybrid http://stackoverflow.com/questions/28081972/evaluate-function-returning-error-2023-however-there-is-no-error Mode Switch to Threaded Mode Mar 3rd, 2007,01:07 PM #1 galileogali Board Regular Join Date Oct 2005 Location Quiroga, Argentine Posts 748 Error 2023 with EVALUATE I want to pass one Array Formula of the cell to VBA. I have got whole Numbers in Column “A: A”. For instance, the 1,...6,..8,.....17, exclude http://www.mrexcel.com/forum/excel-questions/250543-error-2023-evaluate.html the 7. I have defined Names: “rng” Dynamic range =Sheet1! $A$2: INDEX (Sheet1! $A: $A, MATCH (9E+307, Sheet1! $A: $A, 1), 0) and “rng1” =IF (rng= "", 0, rng) Test in VBA the following expression RESULT = Evaluate("MAX(IF(LARGE(rng1,ROW(INDIRECT(""1:""&(COUNT(rng1)-1))))-LARGE(rng1,ROW(INDIRECT(""2:""& COUNT(rng1))))>1,LARGE(rng1,ROW(INDIRECT(""2:""&COUNT(rng1))))))+1") ¿Why RESULT = Error 2023? THANKS Galileogali Share Share this post on Digg Del.icio.us Technorati Twitter Reply With Quote Mar 3rd, 2007,01:38 PM #2 Norie Board Regular Join Date Apr 2004 Location Stirling Posts 70,024 Does the formula work on the worksheet? Share Share this post on Digg Del.icio.us Technorati Twitter If posting code please use code tags. Reply With Quote Mar 3rd, 2007,01:45 PM #3 galileogali Board Regular Join Date Oct 2005 Location Quiroga, Argentine Posts 748 Yes. OFF COURSE, This formula WORKS. (CTRL+SHIFT+ENTER) Share Share this post on Digg Del.icio.us Technorati Twitter Reply With Quote Mar 3rd, 2007,02:58 PM #4 Norie Board Regular Join Date Apr 2004 Location Stirling Posts 70,024 I'm s

Search FlashChat Actuarial Discussion Preliminary Exams CAS/SOA Exams Cyberchat Around the World Suggestions Search Forums Show Threads Show Posts Tag Search Advanced Search Search http://www.actuarialoutpost.com/actuarial_discussion_forum/showthread.php?t=160251 Blogs Tag Search Advanced Search Go to Page... Thread Tools Display http://www.utteraccess.com/forum/lofiversion/index.php/t1983194.html Modes #1 03-03-2009, 10:56 AM spencerhs5 Member Join Date: Jan 2007 Posts: 1,371 Evaluate Function VBA Okay, so i just started messing around with the Evaluate function, thinking it might save me time from opening a whole mess of books to pull a few values and error 2023 then closing them. the following code line works just fine Evaluate("=Sum(MyRange)") 'Where MyRange is a defined Range in the book but if you try to use it to evaluate a link i get a type Mismatch error Evaluate("='C:[Book1.xlsx]Sheet1'!$M$34") Does not work however Any ideas? spencerhs5 View Public Profile Find all posts by spencerhs5 #2 03-03-2009, 11:43 AM dumples Member CAS vba error 2023 Join Date: Sep 2003 Posts: 1,223 Quote: Originally Posted by spencerhs5 Evaluate("='[Book1.xlsx]Sheet1'!$M$34") From what I can tell, you can only use evaluate on an open workbook, otherwise it throws "error 2023." Googling "VBA error 2023" didn't really tell me anything too helpful. Hope this helps. dumples View Public Profile Find all posts by dumples #3 03-03-2009, 12:01 PM JMO Carol Marler Join Date: Sep 2001 Location: Back home again in Indiana Studying for Nothing actuarial. Posts: 34,581 There's no way around it. Just include code to open the workbook, if necessary, and close it when you're done. __________________ Carol Marler, "Just My Opinion" Pluto is no longer a planet and I am no longer an actuary. Please take my opinions as non-actuarial. My latest favorite quotes, updated Oct 5, 2016. Spoiler: I should keep these two permanently. Quote: Originally Posted by rekrap JMO is right Quote: Originally Posted by campbell I agree with JMO. Quote: Originally Posted by ActSciMan Probability 0 and impossible are not the same thing. Quote: Originally Posted by whoanonstop Some people want the wo

and works fine. Any idea's?Im having to use this as the Hlookup with the full UNC path that ill be using comes out at greater than 255 characters.CODEFunction WeekLookup(Wk As Integer, Pth As String, RwNum As Integer)Wk = 8Pth = "'W:\FilePath\[File.xls]Sheet1'!$F$1:$BE$31"RwNum = 11 WeekLookup = Evaluate("HLookup(" & Wk & "," & Pth & "," & RwNum & ")")End FunctionThanks for any help DanielPineault Mar 1 2012, 12:08 PM I am by far no Excel expert, but since HLookup is a function it should not be in quotes when you call it, and in that sense there is no point to have all the extra " & either. Try something more along the lines of:CODEFunction WeekLookup(Wk As Integer, Pth As String, RwNum As Integer)Ok = 8Pth = "'W:\FilePath\[File.xls]Sheet1'!$F$1:$BE$31"RwNum = 11 WeekLookup = Evaluate(HLookup(Wk ,Pth, RwNum))End Function tmleafs17 Mar 2 2012, 04:10 AM tried that and it states "Hlookup" sub or function not defined Bob G Mar 2 2012, 07:16 AM you may want to try this. it is untested but should work. Basically, some worksheet functions are not directly available in VBA so you need to call them with the application object WeekLookup = Application.WorksheetFunction.HLookup(wk & ", ", & pth & ", " & rwnum ) This is a "lo-fi" version of UA. To view the full version with more information, formatting and images, please click here.