Parse Error At End Of Input C
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Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up “parse error at end of input”, but I'm sure my brackets are correct. (in C) up vote 0 down vote favorite I'm pretty sure my brackets are matched up correctly, but I'm getting the error "parse error at end of input" No matter how many or few brackets I attach to the end of this program. Since all of the Google results for this error say that the fix lies in the brackets, I'm at a loss for what else it could be. Could someone point out my silly little mistake for me? :) #include #include "/user/cse320/Projects/project06.support.h" #include "/user/cse320/Projects/project06.hardware.h" void execute() { unsigned long int IRdecode; IRdecode = IR; IRdecode >> 30; if ( IRdecode == 0 ) { unsigned int _reg = IR; unsigned int _imm = IR; _reg << 2; _reg >> 27; _imm << 9; write_reg_file( _reg, _imm ); } if ( IRdecode == 00000002 ) { unsigned int _op3 = IR; unsigned int _rd = IR; unsigned int _rs1 = IR; _op3 << 7; _op3 >> 26; _rd << 2; _rd >> 30; _rs1 << 13; _rs1 >> 27; if ( _op3 == 00000001 ){ //AND } if ( _op3 == 00000002 ){ //OR } if ( _op3 == 00000003 ){ //XOR } if ( _op3 == 00000005 ){ //ANDN } if ( _op3 == 00000006 ){ //ORN } if ( _op3 == 00000007 ){ //XNOR } } } c parsing curly-brackets share|improve this question asked Mar 25 '11 at 3:33 Megan Rose 18125 3 If you look at the syntax highlighting SO gave it, you should see the problem. –geekosaur Mar 25 '11 at 3:35 Oh gosh, you're totally right. I didn't even think about the comment lines eating my brackets. Lol, thank you! –Megan Rose Mar 25 '11 at 3:39 add a comment| 4 Answers 4 active oldest votes up vote 2 down vote accepted you are using //AND } for comment which will comment every thing in same line, results } to be commented. CODE: if ( _op3 == 00000001 ){ //AND } //here } will be commented. You should use like this if ( _op3 == 00000001 ){ //AND } //now OK OR if ( _op3 == 00000001 ){ /*A
Programming Boards C++ Programming Parse Error At End Of Input?!?!?!?!?! Getting started with C or C++ | C Tutorial | C++ Tutorial | C and C++ FAQ | Get a compiler | Fixes for common problems Thread: Parse Error At End Of Input?!?!?!?!?! Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 06-02-2002 #1 kas2002 View Profile View Forum Posts Visit Homepage Registered User Join Date May 2002 Posts 208 Parse Error At End Of Input?!?!?!?!?! What does that mean!!! I have saerch hign and low all throughout my code and found nuthing. I just cannot figure out why this is happening to me. Here is my code. Oh and http://stackoverflow.com/questions/5428260/parse-error-at-end-of-input-but-im-sure-my-brackets-are-correct-in-c it would be nice to also explain exactly what a parse error at end of input is because on other message boards people just give your awnsers and don't really help you to know why it is happening so u can fix it yourself next time. Code: #include #include char word[502]; int decimal[502]; void binary(); int main() { char word[502]; int decimal[502]; cout<<"\nPlease Input Some Text\n"; cin>>word; cout<<"\nThis Is Your Text In ASCII Decimals\n"; for(int a=0;a<502;a++) {decimal[a]=int(word[a]); cout<http://cboard.cprogramming.com/cplusplus-programming/18979-parse-error-end-input.html Text In Binary Numbers"; binary(); cout<<"\n\n Thats About It\n\n"; system("PAUSE"); return 0; } void binary() { char letter; int len, ascii, binary[8], total; len = strlen(word); /* get the number of characters in entry. */ /* this loop is executed for each letter in the string. */ for(int i = 0; i0) /* This while loop converts the ASCII # into binary, stores it backwards into the binary array. */ { /* To get the binary code one must take the decimal number in question, take it and divide it by two repeatedly, save the remainder (which will become the binary number), save the whole number, divide by two, and repeat the whole process until 0 is reached. This if-else statement serves this functionality, by getting the remainder of the ascii code, storing it in the array and then dividing the int ascii by two */ if((ascii%2)==0) { binary[total] = 0; ascii = ascii/2; total++; /* increasing by one each time will yeild the number of numbers in the array. */ } else { binary[total] = 1; ascii = ascii/2; total++; } } total--; /* due to data type factors, the program will actually add a 0 at the end of the array that is not supposed to be there, decrementing total will sol
Forums >Programming >C/C++ Help Syntax errors - Parse error at end of input Discuss Parse error at end of input in the C/C++ Help forum on Dev Articles. Parse error at end of input C/C++ Help forum discussing building and maintaining applications in C/C++. Find out http://forums.devarticles.com/c-c-help-52/parse-error-at-end-of-input-193307.html why these languages are the foundation on which other languages are built. Add This Thread To: Del.icio.us Digg Google Spurl Blink Furl Simpy Y! MyWeb « Previous Thread | Next Thread » Thread Tools Search this Thread Display Modes Dev Articles Community Forums Sponsor: #1 April 19th, 2009, 04:35 AM mister.box82 Registered User Join Date: Apr 2009 Posts: 1 Time spent error at in forums: 13 m 59 sec Reputation Power: 0 Syntax errors - Parse error at end of input Hi, I have a problem, I'm trying to write a program , [.c] , this prgram converts the capital letter in normal letter, but the program gives me these 2 error: in function main parse error at the end of input please help me..!!! this is the program: #include #include #include int main(void) { char testo[100]; int i; end of input printf("digitare il testo: "); fgets(testo, 100, stdin); for(i = 0; testo[i]; i++) { if (islower(testo[i])) testo[i] = toupper(testo[i]); else if (isupper(testo[i])) testo[i] = tolower(testo[i]); printf("testo convertito: %s\n", testo); return 0; mister.box82 View Public Profile View Extended RPG Stats Challenge This User To Battle Send a private message to mister.box82 Find all posts by mister.box82 Find all threads by mister.box82 Add mister.box82 to Your Buddy List #2 April 20th, 2009, 02:44 AM lampshade Registered User Join Date: Apr 2009 Posts: 3 Time spent in forums: 1 h 25 m 2 sec Reputation Power: 0 If you didnt already figure it out, your missing a closing curly brace '}' for the main routine. Code: #include #include #include #define ARRY_SZ 100 // avoiding varaible declaration int main( int argc, char **argv ) { char testo[ARRY_SZ] = {}; int i = 0; printf("digitare il testo: "); fgets(testo, ARRY_SZ, stdin); for i = 0; testo[i]; i++) { // if the for was without curly braces // this if would be the only statement effected. if (islower(testo[i])) testo[i] = toupper(testo[i]); else if (isupper(testo[i])) testo[i] = tolower(testo[i]); } printf("testo convertito: %s\n", testo); return 0; } lampshade View Public Profile View Extended RPG Stats Challenge This User To Battle Send a private message to lampshade Find all posts by lampshade Find all threads by lampshade Add lampshade to Your Buddy List Viewing: Dev Arti