Getjson Error Handling Jquery
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Jquery Getjson Example
Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it jquery ajax json example only takes a minute: Sign up Error handling in getJSON calls up vote 146 down vote favorite 33 How can you handle errors in a getJSON call? Im trying to reference a cross-domain script service using jsonp, how do
Getjson Fails
you register an error method? jquery cross-domain jsonp getjson share|improve this question edited Dec 18 '11 at 16:05 hippietrail 5,89645186 asked Nov 16 '09 at 5:20 Ajay 2,902144066 Seems to be a duplicate of How do I catch jQuery $.getJSON (or $.ajax with datatype set to 'jsonp') error when using JSONP? –hippietrail Dec 18 '11 at 16:04 Ajay, why not considering marking the correct answer? –Ionică Bizău Mar 19 '15 at 12:30 @IonicăBizău Marked getjson not working it now. I just lost track of this for a while. The top answer is not talking about JSONP. As pointed out by Ben Shelock, there is no supported error handler is what I believe.. –Ajay Mar 19 '15 at 21:15 add a comment| 9 Answers 9 active oldest votes up vote 6 down vote accepted Seems there is no error method from what I have read here. This answer offers a good explanation share|improve this answer answered Nov 16 '09 at 5:23 Ben Shelock 6,0461969112 add a comment| up vote 224 down vote OBS: I know I'm a little late to this post, but a friend just asked me this same question and sent me the link of this page. I wish it also can help someone else. $.getJSON() is a kind of abstraction of a regular ajax call where you would have to tell that you want a json encoded response. $.ajax({ url: url, dataType: 'json', data: data, success: callback }); You can handle errors in two ways: generically (by configuring your ajax calls before actually calling them) or specifically (with method chain). 'generic' would be something like: $.ajaxSetup({ "error":function() { alert("error"); } }); And the 'specific' way: $.getJSON("example.json", function() { alert("success"); }) .success(function() { alert("second success"); }) .error(function() { alert("error"); }) .complete(function() { alert("complete"); }); share|improve this answer answered Apr 5 '11 at 14:29 Luciano Costa 2,686298 if you use the .error() do
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Jquery Parse Json
Documentation jQuery.getJSON() Categories: Ajax > Shorthand Methods jQuery.getJSON( url [, data
Jquery Jsonp
] [, success ] )Returns: jqXHR Description: Load JSON-encoded data from the server using a json error handling best practices GET HTTP request. version added: 1.0jQuery.getJSON( url [, data ] [, success ] ) url Type: String A string containing the URL to which the request http://stackoverflow.com/questions/1740218/error-handling-in-getjson-calls is sent. data Type: PlainObject or String A plain object or string that is sent to the server with the request. success Type: Function( PlainObject data, String textStatus, jqXHR jqXHR ) A callback function that is executed if the request succeeds. This is a shorthand Ajax function, which is equivalent to: 1 2 http://api.jquery.com/jquery.getjson/ 3 4 5 6 $.ajax({ dataType: "json", url: url, data: data, success: success}); Data that is sent to the server is appended to the URL as a query string. If the value of the data parameter is a plain object, it is converted to a string and url-encoded before it is appended to the URL. Most implementations will specify a success handler: 1 2 3 4 5 6 7 8 9 10 11 $.getJSON( "ajax/test.json", function( data ) { var items = []; $.each( data, function( key, val ) { items.push( "", { "class": "my-new-list", html: items.join( "" ) }).appendTo( "body" );}); This example, of course, relies on the structure of the JSON file: 1 2 3 4 5 { "one": "Singular sensation", "two": https://recalll.co/app/?q=jquery%20-%20Error%20handling%20in%20getJSON%20calls structure is as follows (found on http://api.jqueri.com): $(selector).getJSON(url,data,success(data,status,xhr)) where they use the url http://nurelm.com/self-indulgent-code-jquery-getjson-with-error-handling/ var to provide a link to the JSON data, the datatosend as a place to add the "?callback=?" and other variables that have to be send to get the correct JSON data returned, and the success funcion as a function for processing the data. You can however add the status and xhr error handling variables in your success function. The status variable contains one of the following strings : "success", "notmodified", "error", "timeout", or "parsererror", and the xhr variable contains the returned XMLHttpRequest object (found on w3schools) $.getJSON(url, datatosend, function(data, status, xhr){ if (status == "success"){ //do something with the data }else if (status == "timeout"){ alert("Something is wrong with the connection"); }else if (status == "error" || status json error handling == "parsererror" ){ alert("An error occured"); }else{ alert("datatosend did not change"); } }); This way it is easy to keep track of timeouts and errors without having to implement a custom timeout tracker that is started once a request is done. jquery - Error handling in getJSON calls - Stack Overflow View More at http://stackoverflow.com/questions/1740218/error-handling-in-getj... .error(function(jqXHR, textStatus, errorThrown) { console.log("error " + textStatus); console.log("incoming Text " + jqXHR.responseText); }) Was this with cross-site JSONP or with same site JSON? Nice answer! Just a note about .error: It will deprecate in jQuery 1.8, so use .fail jquery - Error handling in getJSON calls - Stack Overflow View More at http://stackoverflow.com/questions/1740218/error-handling-in-getj... I did that and here is Luciano's updated code snippet: $.getJSON("example.json", function() { alert("success"); }) .done(function() { alert('getJSON request succeeded!'); }) .fail(function() { alert('getJSON request failed! '); }) .always(function() { alert('getJSON request ended!'); }); And with error description plus showing all json data as a string: If you don't like alerts, substitute them with console.log $.getJSON("example.json", function(data) { console.log(JSON.stringify(data)); }) .done(function() { console.log('getJSON request succeeded!'); }) .fail(function(jqXHR, textStatus, errorThrown) { console.log('getJSON request failed! ' + textStatus); }) .always(function() { console.log('getJSON request ended!'); }); jq
some back-end code. In general most of these requests originate and terminate within the same domain. The problem is that some of these requests occur outside the local domain and I don't have direct control of their availability. Additionally jQuery's getJSON for some reason doesn't include access to the error callback. The funny thing is getJSON is built off of jQuery's ajax which wraps JavaScripts XMLHttpRequest object and includes an event for complete and error status of the request. For some reason though these items were left off the getJSON function. So now you are saying to yourself, "boy this guy is picky", but in reality JSON is one of the few things that can be transfered across domains with AJAX. So here is my solution. It is a general wrapper for the jQuery ajax object. In the code below I have created a replacement to getJSON with one caveat aside from the fact it includes a way to pass a callback for handling errors. The AjaxWrapper class can be used to create custom jQuery AJAX commands. AjaxGet takes 4 parameters: The first two are required and the last two are the success and error callbacks. If you don't pass a function to either one of these parameters there is a default callback that will take its place.
/** * Asynchronous get with data that has backup default success and error functions * which utilize Alert.js to return the status of the JSON request. These functions * can be overridden for custom actions * @author Paul Scarrone(NuRelm) * @param url The URL to process the request against * @param data JSON encoded object which contains the request data * @param successfcn a function which takes data as a parameter * @param errorfcn a function which takes XMLHttpRequest, textStatus, errorThrown as parameters */ function AjaxGet(url, data, successfcn, errorfcn){ var AjaxInstance = new AjaxErrorHandler(); var success; var error; if(typeof(data) == "function"){ if(typeof(successfcn) == "function"){ errorfcn = successfcn; } //Was being updated out of order thanks kovshi successfcn = data; } /*Alert.CreateOneTimeUseDialog(url