Gcc Error At This Point In File
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account creation filtered due to spam. Bug43126 - "at this point in file" warnings are upside down Summary: "at this point in file" warnings are gcc option upside down Status: RESOLVED FIXED Alias: None Product: gcc Classification: Unclassified Component: c++ (show
Fpermissive
other bugs) Version: 4.4.1 Importance: P3 normal Target Milestone: --- Assignee: Manuel López-Ibáñez URL: Keywords: diagnostic Duplicates (1): 38468 (view as
Unrecognized Command Line Option
bug list) Depends on: Blocks: Reported: 2010-02-20 05:22 UTC by Glenn Maynard Modified: 2010-06-02 06:53 UTC (History) CC List: 3 users (show) gcc-bugs ian manu See Also: Host: Target: Build: Known to work:
Gcc Error Unrecognized Command Line Option
Known to fail: Last reconfirmed: 2010-02-20 15:56:39 Attachments Add an attachment (proposed patch, testcase, etc.) Note You need to log in before you can comment on or make changes to this bug. Description Glenn Maynard 2010-02-20 05:22:00 UTC These warnings have driven me insane for years: blah.cc:1: error: too many arguments to function ‘void a(int)’ blah.cc:7: error: at this point in file I always end up jumping to g++ line 1 in the file. I glance at the message and line number in the first line, and I'm jumping to that line number before my brain has really processed which error message it is. This is inherently something I can't learn to work around without deliberately slowing down my workflow (a mental pipeline stall?). The line number next to the error should be the one causing the error; any additional, related lines should come *after*. This is much better: blah.cc:7: error: too many arguments to function ‘void a(int)’ blah.cc:1: error: declared here This also makes it consistent with the C version of this error. Comment 1 Andrew Pinski 2010-02-20 06:25:29 UTC Confirmed. The C front-end just emits: t.c: In function ‘g’: t.c:4:3: error: too many arguments to function ‘f’ While the C++ front-end emits: t.c:1:5: error: too many arguments to function ‘int f(int)’ t.c:4:16: error: at this point in file Comment 2 Andrew Pinski 2010-02-20 06:27:30 UTC I should say the simple example was: int f(int); int g(int a, int b) { return f(a, b); } Comment 3 Glenn Maynard 2010-02-20 06:51:40 UTC ("4:16"? I havn't seen that before. I hope gcc isn't going to start outputting character offsets by default; that's a
risky or suggest there may have been an error. The following language-independent options do not enable specific warnings but control the kinds of diagnostics produced by GCC. -fsyntax-onlyCheck the make code for syntax errors, but don't do anything beyond that. -fmax-errors=nLimits the -std=c++11 maximum number of error messages to n, at which point GCC bails out rather than attempting to continue processing the source code. If n is 0 (the default), there is no limit on the number of error messages produced. If -Wfatal-errors is also specified, then -Wfatal-errors takes https://gcc.gnu.org/bugzilla/show_bug.cgi?id=43126 precedence over this option. -wInhibit all warning messages. -WerrorMake all warnings into errors. -Werror=Make the specified warning into an error. The specifier for a warning is appended; for example -Werror=switch turns the warnings controlled by -Wswitch into errors. This switch takes a negative form, to be used to negate -Werror for specific warnings; for example -Wno-error=switch makes -Wswitch https://gcc.gnu.org/onlinedocs/gcc/Warning-Options.html warnings not be errors, even when -Werror is in effect. The warning message for each controllable warning includes the option that controls the warning. That option can then be used with -Werror= and -Wno-error= as described above. (Printing of the option in the warning message can be disabled using the -fno-diagnostics-show-option flag.) Note that specifying -Werror=foo automatically implies -Wfoo. However, -Wno-error=foo does not imply anything. -Wfatal-errorsThis option causes the compiler to abort compilation on the first error occurred rather than trying to keep going and printing further error messages. You can request many specific warnings with options beginning with ‘-W’, for example -Wimplicit to request warnings on implicit declarations. Each of these specific warning options also has a negative form beginning ‘-Wno-’ to turn off warnings; for example, -Wno-implicit. This manual lists only one of the two forms, whichever is not the default. For further language-specific options also refer to C++ Dialect Options and Objective-C and Objective-C++ Dialect Options. Some options, such as -Wall and -Wextra, turn on other options, such as -Wunuse
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this http://stackoverflow.com/questions/25632957/gcc-error-that-wont-break-further-compilation site About Us Learn more about Stack Overflow the company Business Learn http://stackoverflow.com/questions/707920/gcc-compiler-error-redefinition-previously-defined more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up GCC gcc error #error that won't break further compilation up vote 1 down vote favorite I have several simple macros that exist in some files across a large project that includes a #error. They all follow this structure, more or less: #ifdef COMPFAIL #pragma message "Compilation Has Failed" #error #endif I want to set the project up so that, if COMPFAIL is defined, the #pragma within each unrecognized command line file occurs with compilation ultimately failing. I now understand that when #error is called, it halts compilation on the spot, not attempting to compile any of the other files defined in my Makefile and preventing all further #pragma calls from occurring. Is there a way to force the compiler to finish preprocessing across all files before failing? c++ gcc share|improve this question edited Sep 2 '14 at 22:14 asked Sep 2 '14 at 21:50 user2559503 11410 2 I think you;re looking for make -k or equivalent, not any feature of the compiler itself. –zwol Sep 2 '14 at 21:51 add a comment| 1 Answer 1 active oldest votes up vote 2 down vote A very simple test: #error foo #error bar Compiling this file with gcc produces the following results: t.c:2:2: error: #error foo #error foo t.c:3:2: error: #error bar #error bar It's obvious that #error does not completely stop the compilation of the file. If it were, only the first error would've been reported, and the compilation would've stopped. But, after the #error, the compiler keeps going, and continues to preprocess, and compile, the rest of t
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up GCC compiler error: “redefinition…previously defined” up vote 7 down vote favorite 3 I'm getting a lot of " redefinition of x....x previously defined here". Please what does this error means? c++ gcc compiler-construction share|improve this question asked Apr 2 '09 at 1:00 caesar add a comment| 3 Answers 3 active oldest votes up vote 20 down vote You need to limit each file from being included only once. You can do this in 2 ways. 1) At the top of your header files put: #pragma once Or 2) if your compiler doesn't support that, put at the top/end of your header files: #ifndef _MYFILE_H_ #define _MYFILE_H_ ... #endif Replace MYFILE with the name of your file, and replace ... with the contents of the header file. share|improve this answer edited Apr 2 '09 at 7:11 unwind 254k38332460 answered Apr 2 '09 at 1:18 Brian R. Bondy 198k82474572 1 I think that #pragma only works in VC++, not in gcc. The #define trick is portable. –Gorpik Apr 2 '09 at 7:19 supoprted by gcc and vc++ –Brian R. Bondy Apr 2 '09 at 10:29 Wikipedia says #pragma once is supported by VC++ and gcc en.wikipedia.org/wiki/Pragma_once . –Max Lybbert Apr 3 '09 at 20:48 #pragma works fine with gcc.. I'm using it at this very moment after I reading about it and it solved a ton of errors! –mmoment Sep 7 '12 at 14:13 add a comment| up vote 9 down vote The error means that there is a symbol that has been defined in one place