Bash End Script If Error
Contents |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about
Bash If Error Code
hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask bash if error exit Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other.
Exit Bash Shell
Join them; it only takes a minute: Sign up Automatic exit from bash shell script on error up vote 276 down vote favorite 48 I've been writing some shell script and I would find it useful if there was bash exit script from function the ability to halt the execution of said shell script if any of the commands failed. See below for an example: #!/bin/bash cd some_dir ./configure --some-flags make make install So in this case if the script can't change to the indicated directory then it would certainly not want to do a ./configure afterwards if it fails. Now I'm well aware that I could have an if check for each command (which I think is a hopeless solution), but bash exit function is there a global setting to make the script exit if one of the commands fails? bash shell exit share|improve this question edited Mar 29 '15 at 23:26 asked May 20 '10 at 4:21 radman 5,57462242 I did have a quick look for duplicates and couldn't find any. –radman May 20 '10 at 4:22 1 answer goes to Adam for the detail regarding set -e (which is exactly wanted). Also thanks to a_m0d for the info on traps (though not 100% relevant). –radman May 20 '10 at 5:07 add a comment| 7 Answers 7 active oldest votes up vote 440 down vote accepted Use the set -e builtin: #!/bin/bash set -e # Any subsequent(*) commands which fail will cause the shell script to exit immediately Alternatively, you can pass -e on the command line: bash -e my_script.sh You can also disable this behavior with set +e. (*) Note: The shell does not exit if the command that fails is part of the command list immediately following a while or until keyword, part of the test in an if statement, part of a && or || list, or if the command's return value is being inverted via ! (from man bash) share|improve this answer edited Jan 19 '15 at 16:52 Gilead 91211322 answered May 20 '10 at 4:36 Adam Rosenfield 241k66369493 1 Is this also a Bourne Shell builtin? –Tom
Ramey
The exit command terminates a script, just as in a C program. It can also return a value, which is available to the script's parent process.EveryExit Bash Mode
command returns an exit status (sometimes referred to as a return status or exit code). A successful command returns a 0, while an unsuccessful one returns a non-zero value
Bash Exit With Message
that usually can be interpreted as an error code. Well-behaved UNIX commands, programs, and utilities return a 0 exit code upon successful completion, though there are some exceptions.
Likewise, functions within a http://stackoverflow.com/questions/2870992/automatic-exit-from-bash-shell-script-on-error script and the script itself return an exit status. The last command executed in the function or script determines the exit status. Within a script, an exit nnn command may be used to deliver an nnn exit status to the shell (nnn must be an integer in the 0 - 255 range).When a script ends with an exit that http://tldp.org/LDP/abs/html/exit-status.html has no parameter, the exit status of the script is the exit status of the last command executed in the script (previous to the exit).#!/bin/bash COMMAND_1 . . . COMMAND_LAST # Will exit with status of last command. exitThe equivalent of a bare exit is exit $? or even just omitting the exit.#!/bin/bash COMMAND_1 . . . COMMAND_LAST # Will exit with status of last command. exit $?#!/bin/bash COMMAND1 . . . COMMAND_LAST # Will exit with status of last command.Bash Prompts About Writing Robust Bash Shell Scripts Many people hack together shell scripts quickly to do simple tasks, but these soon take on a life of their own. Unfortunately http://www.davidpashley.com/articles/writing-robust-shell-scripts/ shell scripts are full of subtle effects which result in scripts failing http://bencane.com/2014/09/02/understanding-exit-codes-and-how-to-use-them-in-bash-scripts/ in unusual ways. It's possible to write scripts which minimise these problems. In this article, I explain several techniques for writing robust bash scripts. Use set -u How often have you written a script that broke because a variable wasn't set? I know I have, many times. chroot=$1 if error ... rm -rf $chroot/usr/share/doc If you ran the script above and accidentally forgot to give a parameter, you would have just deleted all of your system documentation rather than making a smaller chroot. So what can you do about it? Fortunately bash provides you with set -u, which will exit your script if you try to use an uninitialised variable. You can bash if error also use the slightly more readable set -o nounset. david% bash /tmp/shrink-chroot.sh $chroot= david% bash -u /tmp/shrink-chroot.sh /tmp/shrink-chroot.sh: line 3: $1: unbound variable david% Use set -e Every script you write should include set -e at the top. This tells bash that it should exit the script if any statement returns a non-true return value. The benefit of using -e is that it prevents errors snowballing into serious issues when they could have been caught earlier. Again, for readability you may want to use set -o errexit. Using -e gives you error checking for free. If you forget to check something, bash will do it or you. Unfortunately it means you can't check $? as bash will never get to the checking code if it isn't zero. There are other constructs you could use: command if [ "$?"-ne 0]; then echo "command failed"; exit 1; fi could be replaced with command || { echo "command failed"; exit 1; } or if ! command; then echo "command failed"; exit 1; fi What if you have a command that returns non-zero or you are
exit codes, exit codes are important and this article describes how to use them in your scripts and understand them in general. Written by Benjamin Cane on 2014-09-02 14:45:00| 4 min read Sponsored by Lately I've been working on a lot of automation and monitoring projects, a big part of these projects are taking existing scripts and modifying them to be useful for automation and monitoring tools. One thing I have noticed is sometimes scripts use exit codes and sometimes they don't. It seems like exit codes are easy for poeple to forget, but they are an incredibly important part of any script. Especially if that script is used for the command line. What are exit codes? On Unix and Linux systems, programs can pass a value to their parent process while terminating. This value is referred to as an exit code or exit status. On POSIX systems the standard convention is for the program to pass 0 for successful executions and 1 or higher for failed executions. Why is this important? If you look at exit codes in the context of scripts written to be used for the command line the answer is very simple. Any script that is useful in some fashion will inevitably be either used in another script, or wrapped with a bash one liner. This becomes especially true if the script is used with automation tools like SaltStack or monitoring tools like Nagios, these programs will execute scripts and check the status code to determine whether that script was successful or not. On top of those reasons, exit codes exist within your scripts even if you don't define them. By not defining proper exit codes you could be falsely reporting successful executions which can cause issues depending on what the script does. What happens if I don't specify an exit code In Linux any script run from the command line has an exit code. With Bash scripts, if the exit code is not specified in the script itself the exit code used will be the exit code of the last command run. To help explain exit codes a little better we are going to use a quick sample script. Sample S