Percent Error Of Zinc
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Density Formula
Trending Now Philip Rivers Billy Bush Gabrielle Union Diane Kruger Shania Twain 2016 Crossovers Truman Capote Auto Insurance Quotes Samsung Galaxy Dating Sites Answers Best Answer: Actual/Theoretical(accepted..what you calculated.) X 100 So 6.8/7.14 X100= your answer. Source(s): Smitty Werbenjagermanjenson · 5 years ago 0 Thumbs up 0 Thumbs down Comment Add a comment Submit · just now Report Abuse Add your answer Find percent error of density of zinc? experimental value = 6.8 g/mL accepted value = 7.14 g/mL Find percent error Add your answer Source Submit Cancel Report Abuse I think this question violates the Community Guidelines Chat or rant, adult content, spam, insulting other members,show more I think this question violates the Terms of Service Harm to minors, violence or threats, harassment or privacy invasion, impersonation or misrepresentation, fraud or phishing, show more Additional Details If you believe your intellectual property has been infringed and would like to file a complaint, please see our Copyright/IP Policy Report Abuse Cancel Report Abuse I think this answer violates the Community Guidelines Cha
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Density Of Water
ads with us Chemistry Questions Tags Users Badges Unanswered Ask Question _ Chemistry Stack Exchange is slope formula a question and answer site for scientists, academics, teachers and students. Join them; it only takes a minute: Sign up Here's how it works: periodic table Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Percent Relative Error up vote 0 down vote favorite I was wondering if I calculated this Homework question right, given https://answers.yahoo.com/question/index?qid=20110908175953AABeM8v for all the options a) through d) , the answer was the same, -99% relative % error. I assume this is due to the fact that mathematically, the formula makes it so. But I am not very good at chemistry, and rather not make any mistakes early on that jeopardize me in the future. A loss of 0.4 mg of Zn occurs in the course of an analysis for that element. Calculate the percent relative error due to this loss http://chemistry.stackexchange.com/questions/36937/percent-relative-error if the weight of Zn in the sample is: a) 40 mg: 1% b) 175 mg: 0.2% c) 400 mg: 0.1% d) 600 mg: 0.07% My solution for a) is below, did I make any mistakes, and should all the answers be -99% relative error? homework analytical-chemistry share|improve this question edited Oct 2 '15 at 16:02 Todd Minehardt 5,74442133 asked Sep 5 '15 at 22:55 Ro Siv 209110 add a comment| 1 Answer 1 active oldest votes up vote 2 down vote accepted There is a problem with your calculation of relative error. A handy document detailing errors is from the Illinois State University: Absolute and Relative Error, that states that $$E_\mathrm r = \frac{\Delta x}{x}$$ Where: $E_\mathrm r$ is the relative error (using the notation you used in the your question). $\Delta x$ is the absolute error, which is 0.4 mg in the question. $x$ is the sample quantity. So, looking at your worked example (thank you for supplying this): $E_\mathrm r = \frac{0.4\ \mathrm{mg}}{40\ \mathrm{mg}} = 0.01 = 1\,\%$ Go from there to calculate the relative error of the remaining quantities. Remember that errors are rounded to one significant figure So, your second example is correct at 0.07%, because this is the 1 significant figure rounding of the calculated value of 0.066...% (Example 2 of the Victoria University guide Significant Figures is a further guide to that) share|improve this answer edited Sep 6 '15 at 0:31 answered
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