Python Socket Error Resource Temporarily Unavailable
Contents |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the python socket recv resource temporarily unavailable company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions errno 11 resource temporarily unavailable python Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million
Python Resource Temporarily Unavailable
programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Creating non-blocking socket in python up vote 1 down vote favorite I was trying to understand how non-blocking sockets work
Error: [errno 11] Resource Temporarily Unavailable Gunicorn
,so I wrote this simple server in python . import socket s=socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.bind(('127.0.0.1',1000)) s.listen(5) s.setblocking(0) while True: try: conn, addr = s.accept() print ('connection from',addr) data=conn.recv(100) print ('recived: ',data,len(data)) except: pass Then I tried to connect to this server from multiple instances of this client import socket s=socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect(('127.0.0.1',1000)) while True: continue But for some reason putting blocking to 0 or 1 dose not seem to have an effect and server's python socket errno 11 resource temporarily unavailable recv method always block the execution. So, dose creating non-blocking socket in python require more than just setting the blocking flag to 0. python sockets nonblocking share|improve this question asked Aug 21 '14 at 12:32 Gray 378 add a comment| 2 Answers 2 active oldest votes up vote 3 down vote accepted setblocking only affects the socket you use it on. So you have to add conn.setblocking(0) to see an effect: The recv will then return immediately if there is no data available. share|improve this answer edited Aug 21 '14 at 13:27 answered Aug 21 '14 at 12:37 Phillip 10.6k923 setblocking(0) does affect socket.accept() which will not block waiting for an incoming connection, but raise an exception. –mhawke Aug 21 '14 at 12:51 The documentation seems to be incomplete here, you are of course right. I've removed that comment from my answer. But there is an exception to this: If socket.settimeout is used, Python will still call select(2) before accept(2), i.e. wait at least until the timeout is reached. –Phillip Aug 21 '14 at 13:26 add a comment| up vote 0 down vote You just need to call setblocking(0) on the connected socket, i.e. conn. import socket s = socket.socket() s.bind(('127.0.0.1', 12345)) s.listen(5) s.setblocking(0) >>> conn, addr = s.accept() Traceback (most recent call last
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings
Eagain (resource Temporarily Unavailable)
and policies of this site About Us Learn more about Stack Overflow python socket non blocking recv the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags python non blocking socket Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only http://stackoverflow.com/questions/25426447/creating-non-blocking-socket-in-python takes a minute: Sign up What can cause a “Resource temporarily unavailable” on sock send() command up vote 28 down vote favorite 6 What can cause a Resource temporarily unavailable error on a socket send() command? The socket is setup as AF_UNIX, SOCK_STREAM. It works most of the time, but occasionally gets this error. The receiving end of the socket http://stackoverflow.com/questions/14370489/what-can-cause-a-resource-temporarily-unavailable-on-sock-send-command appears to be working properly. I know this isn't very detailed, but I'm just looking for general ideas. Thanks! c linux sockets unix share|improve this question edited Jan 17 '13 at 9:40 Ashwini Chaudhary 132k20199276 asked Jan 17 '13 at 0:49 giroy 73841634 Is this related? stackoverflow.com/questions/5737493/… –paddy Jan 17 '13 at 0:52 2 Are you setting your socket to O_NONBLOCK ? –Deepankar Bajpeyi Jan 17 '13 at 0:57 I don't think it is related to that post. My sockets are SOCK_STREAM which I believe are blocking which is what I want. –giroy Jan 17 '13 at 0:59 2 Whether a stream is blocking or non-blocking is independent of whether it's SOCK_STREAM or SOCK_DGRAM. The answer there is relevant. –Barmar Jan 17 '13 at 1:33 add a comment| 2 Answers 2 active oldest votes up vote 35 down vote accepted "Resource temporarily unavailable" is the error message corresponding to EAGAIN, which means that the operation would have blocked but nonblocking operation was requested. For send(), that could be due to any of: explicitly marking
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack http://stackoverflow.com/questions/17603002/python-receiving-data-through-sockets-errno-11-resource-temporarily-unavail Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Python: Receiving Data through Sockets - [Errno 11] Resource temporarily unavailable up vote 2 down vote favorite resource temporarily 2 Background I need to communicate with a Tektronix MSO 4104 from python. The communication takes place over the LAN using the vxi11 ethernet protocol and python's socket library. Situation Now this works fairly well; I can cconnect to the scope and I can send it any command I want (eg: