Access Runtime Error 2447
Contents |
be down. Please try the request again. Your cache administrator is webmaster. Generated Fri, 30 Sep 2016 01:18:08 GMT by s_hv1000 (squid/3.5.20)
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of
Ms Access Runtime Error 2105
this site About Us Learn more about Stack Overflow the company Business ms access runtime error 3061 Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask
Ms Access Runtime Error 2465
Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign http://answers.microsoft.com/en-us/msoffice/forum/msoffice_access-mso_winother/access-2010-error-2447-when-trying-to-access/b20c9cdb-2cd3-48a2-aa71-ee044a1691b3 up Access VBA Checkbox error 2447 up vote 0 down vote favorite Ok, I'm getting the error 2447 when trying to create a new record in my database. Here is the code that is have. 'This checks the record each time a record is changed to see if it needs to display the text boxes Private Sub Form_Current() If Me.SigCheck = 1 then http://stackoverflow.com/questions/19054138/access-vba-checkbox-error-2447 <--This is where I'm getting the error. SigSerialtxt.Visible = True SigSeriallbl.Visible = True SigAssettxt.Visible = True SigAssetlbl.Visible = True Else SigSerialtxt.Visible = False SigSeriallbl.Visible = False SigAssettxt.Visible = False SigAssetlbl.Visible = False End if End Sub I've tried to change the variable to True, as well as -1, but neither of the work. I'm lost as to what to use. access-vba share|improve this question asked Sep 27 '13 at 15:07 user1827407 61 1 Error 2447 is about "... an invalid use of the . (dot) or ! operator or invalid parentheses." So the problem is with Me.SigCheck, not what's on the right side of the = sign. What is Me.SigCheck? –HansUp Sep 27 '13 at 16:00 Me.SigCheck is a checkbox, I want the form to check each time a record is pulled up to see if value of the item is true. If it is true then display the textboxes. –user1827407 Sep 30 '13 at 18:55 Does this show you the checkbox value or does it throw an error?: MsgBox Me.SigCheck –HansUp Sep 30 '13 at 19:12 When I a
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn http://stackoverflow.com/questions/28689075/ms-access97-run-time-error-2447 more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, http://www.pcreview.co.uk/threads/run-time-error-2447-with-access-2003-for-2002-access-switchboard.1103920/ helping each other. Join them; it only takes a minute: Sign up MS Access97 Run Time Error 2447 up vote 0 down vote favorite Someone left a system using MS Access97 and I dont have any idea on runtime error how to use access97 since it is my first time using it. I installed a Microsoft Access97 to a new computer then try to open the system but it displays an error "Run Time Error 2447 There is an invalid use of the .(dot) or ! operator or invalid parenthesis". However the old computer can open the database without any error. I am really confused about this scenario. Can anyone help me? database ms-access runtime share|improve access runtime error this question asked Feb 24 '15 at 5:56 Ralph 63 add a comment| 1 Answer 1 active oldest votes up vote 0 down vote Open the code editor. Go to menu Tools, References and check that no reference is prefixed MISSING. If so, resolve it. In any case, go to the menu and select Compile and save all modules. If some ocx or third-party control is installed and used on the old computer, you must install these on the new computer as well. share|improve this answer answered Feb 25 '15 at 12:13 Gustav 12.3k21026 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service. Not the answer you're looking for? Browse other questions tagged database ms-access runtime or ask your own question. asked 1 year ago viewed 68 times active 1 year ago Related 0How to change a column's “Row Source” in Access table at run-time?1Access Runtime 2007 Ucase-Function fails, solution or help in error tracking needed1MS-Access run time error 20461Access VBA - Run-time error '3197'0Access, Compilation errors and runtime2Running a database in run time version brings up an error0FollowHyperLink R
Eric Kim via AccessMonster.com Guest Hi, I have read all the relative discussions not to ask you the same relavant question again, but I couldn't find it. I'd very much appreciate if you could help me with this. Our office has been using Access 2002 and one of our staff just got a new computer with MS Office 2003. When the staff tries to open the Acess (the first page is switchboard), a pop-up message(security warning) comes up that says "This file may not be safe if it contains code that was intended to harm your computer" - I don't want this if I can... Then, When I hit open button, The Run-Time Error 2447 message pops up saying "There is an invalid use of the dot or ! operator or invalid parentheses." When I hit "Debug" button, the yellow hight lighted area in VB is like this: If Forms ! frmAdmin.txtAdministrator.Value = "Yes" Then The rest of us can use the d/base with no problem with their 2002 Access version even with the same code. Only the ones with 2003 has it. What do you think is the problem ? I have spent about two days doing the reseach on the web, with no avail. I would really appreaicte if you could help me with this. -- Message posted via http://www.accessmonster.com Eric Kim via AccessMonster.com, Jan 25, 2005 #1 Advertisements Guest Guest For your firts problem, go to tools, macros, set security to low, and that should solve that. For the seconf problem, I'd go to the form the debugger is pinting you to and compare 2002 to 2003. See if it can be fixed in 2003 and what the difference is. It could be something very little, such as rebuilding parts of that form in design. I've had to do that between two users using the same version of Access. Don't ask.... "Eric Kim via AccessMonster.com" wrote: > Hi, > I have read all the relative discussions not to ask you the same relavant question again, but I couldn't find it. > > I'd very much appreciate if you could help me with this. > > Our office has been using Access 2002 and one of our staff just got a new computer with MS Office 2003. > > When the staff tries to open the Acess (the first page is switchboard), a pop-up message(security warning) comes up that says "This file may not be safe i