How To Debug A Runtime Error
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A Runtime Error Has Occurred Do You Wish To Debug
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The program should compile without any errors or warnings. Now, run the executable with some data: % total Enter numbers to sum below (separated by spaces). Enter 0 (zero) as the last number. 5 6 7 0 Segmentation fault You'll notice that the program
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produces a nice Segmentation fault. This calls for using debugging techniques! Debugging run-time errors can be done
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by using 2 general techniques: Technique 1: Narrow down where in the program the error occurs. Technique 2: Get more information about what is happening gdb in the program. One way to implement both of these techniques is to use cout to provide information while the program is running. Aside: Be careful, however, since cout output may not appear until endl is printed. In other words, if you https://support.microsoft.com/en-us/kb/822521 don't see the output of a particular cout statement during run-time, you can't tell if the program performed that statement, unless endl was used. If you do use endl, and you don't see the output, you may conclude the program never got that far. Alternatively, you can send output to cerr, whose output is printed immediately (cerr is where error messages are typically sent). Technique 1: Narrowing Down Location of Error We know we got as far as the first prompt ("Enter numbers..."), but not https://www.cs.bu.edu/teaching/cpp/debugging/with-cout/ as far as the last output line: cout << " is " << sum << endl; Note: We're not sure if it did the statements: cout << "The sum of "; PrintValues(values, howmany); Although both of those produce output, they don't use endl, so we can't tell if the crash occurred before or after them. That information narrows down the crash some. To narrow down the location of the problem even more, let's add 2 cout statements. Bring up the code in an editor and add some debugging statements: cout << "point A" << endl; do { // Read the next number. cin >> values[howmany]; // Increment the count. howmany++; // Should error check "howmany"! } while (values[howmany-1] != 0); float sum = SumValues(values, howmany); cout << "The sum of "; PrintValues(values, howmany); cout << "point B" << endl; (Don't forget the endls.) After editing, save the source code and then recompile the program: % g++ -o total sum2.cpp Now, run the executable again: % total Enter numbers to sum below (separated by spaces). Enter 0 (zero) as the last number. point A 5 6 7 0 Segmentation fault We see the point A output, but not the one for point B. This confirms our suspicion that the problem is between point A and point B. Now, we can narrow down the range by moving one (or both) of the couts. Let's move B above the call to PrintValues(): cout << "point A" << endl; do { // Read the n
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings http://stackoverflow.com/questions/440355/how-to-debug-a-visual-c-runtime-error and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation http://www.terryanderson.ca/debugging/run.html Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it runtime error only takes a minute: Sign up How to debug a Visual C++ Runtime Error up vote 4 down vote favorite 1 I am writing a C++ COM object in Visual Studio 2008 that is an Internet Explorer Browser Helper Object. Recently, when running in IE, IE has started frequently popping up a dialog titled "Microsoft Visual C++ Runtime Library" with an a runtime error error message "Runtime Error!" and going on to say that "The application has requested the Runtime to terminate it in an unusual way. Please contact the application's support team for more information." Unlike usual, this dialog only has an OK button but no debug button, so IE then terminates and I'm not left with so much as a stack trace or even a hint of what part of my code could have been so buggy. I'm not sure where in my code it is crashing. How does one troubleshoot a "Runtime error" problem? What are possible causes of a runtime error? (memory related bugs perhaps?) What sort of problems should I be checking my code for to attempt to eliminate this sort of crash? I need some ideas on how to troubleshoot this one, its a bit elusive. c++ visual-studio debugging share|improve this question asked Jan 13 '09 at 19:14 Jessica add a comment| 2 Answers 2 active oldest votes up vote 4 down vote When you see that dialog, start VS2008 with your COM object project. Then us
the execution of your program. There are fewer possible run-time errors than there are compile-time errors, but the procedure for debugging them is not always clear. This page suggests a general method of debugging any run-time errors you encounter. Sections on this page (click to jump to that section): Important Points to Keep in Mind How to Debug Your Code Examples: Null Pointer Exceptions Example: Array Index Out of Bounds Exceptions Important Points to Keep in Mind Debugging run-time errors in your code can be an extremely time-consuming process. However, there are a few points that you should first keep in mind when attempting to find where the problem is in your code. Java executes code in a strict order. This fact is probably something that is taught to you the very first time you see Java code, but it is important to keep in mind when debugging. The only time the flow of code execution will "jump" to another place is when you instruct it to do so. Things such as using a loop, an if statement, or calling another method will change which line of code is to be executed next, rather than Java executing the next line of code by default. For example, consider the following code: 01 this.numPeople++; 02 this.numRegistered++; 03 int age = this.person.getAge(); 04 if (age >= 16) 05 { this.person.setDrive(true); 06 } else 07 { this.person.setDrive(false); 08 } 09 //... The important thing to recognize here is that Java will call lines 1 through 3 in that order, but will not call line 4 directly after line 3. Rather, because line 3 calls another method, Java will call the first line of the getAge() method directly after reaching line 3 in the above code. When the getAge() method finishes, then execution will be returned to this code and line 4 will be executed. Similarly, when Java evaluates the if clause at line 4, either line 5 or line 7 will be executed next, followed by line 9. Recognizing the order in which lines of code are executed will be very valuable in debugging. A single line of code stopped the execution of your program. When a run-time error occurs, the Java compiler will tell you the last li