Access Run Time Error 424
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Run Time Error 424 Object Required Access 2010
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2003: Run-time error 424 (Object Required) This MSAccess tutorial explains how to fix the Run-time error '424': Object Required error in runtime error 424 object required vba access 2010 Access 2003 (with screenshots and step-by-step instructions). Question: In Microsoft Access 2003/XP/2000/97, I'm using VBA code to set a value on another form and I keep getting a "Run-time error '424': Object Required" error. https://support.microsoft.com/en-us/kb/163475 I can't seem to figure out why it won't work. The object that I'm referencing is valid and it should work. What am I doing wrong? Answer: The problem isn't your code, it's that the Visual Basic editor does not recognize your form. In fact, the Visual Basic editor will not recognize your form until you've invoked the Code Builder (for your form or any object on your form) https://www.techonthenet.com/access/questions/obj_required.php at least once. Let's look at an example. In our database, we've created two forms - one called form1 and another called form2. We've invoked the Code Builder on form2. When we take a look at the Visual Basic editor, we can see that form2 exists, but we can't see form1. To fix this problem, we'll open form1 in design view. Next, display the properties for the Form object. Click on the button (with the three dots) on the "On Open" event for the form. When the Choose Builder window appears, select Code Builder and click on the OK button. Now when you return to the Visual Basic editor, form1 would appear in the list. You can actually fix this error by invoking the Code Builder on any event in the form (or any one of the objects on the form). We've just chosen the form's "On Open" event for demonstration purposes. Now when you run your VBA code, the "Object required" error should no longer appear. Share this page: Advertisement Back to top Home | About Us | Contact Us | Testimonials | Donate While using this site, you agree to have read and accepted our Terms of Service and Privacy Policy. We use advertisem
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers http://stackoverflow.com/questions/27125876/runtime-error-424-in-vba-access or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Runtime error 424 in VBA Access up vote 0 down vote favorite Dim rst1 As DAO.Recordset Dim rst2 As DAO.Recordset Set rst1 = CurrentDb.OpenRecordset("Table1", 2) Set rst2 = CurrentDb.OpenRecordset("Table2", 2) Dim strName As String If time error Not (rst1.EOF And rst1.BOF) Then rst1.MoveFirst Do Until rst1.EOF rst1.Edit strName = rst1![Name] rst2.FindFirst ("[Name] = '" & strName & "'") If rst2.NoMatch Then If rst1![Accepted] Is Not Null Then 'here is the line causing error ... 'more code going on So, above is an excerpt from my code. I simplified it as much as possible without changing context. The situation is as follows: I have two tables and want to check whether a person from Table1 is already present run time error in Table2. If that's the case then just ignore it. Whereas if it's not, then I want to check another condition in Table1 (if DateTime field [Accepted] is not NULL) and if it is satisfied to proceed with processing that person's data. However, even though I am able to get the rst1![Name] properly, when I get into the inner if I get the 424 runtime error: Object required. Any ideas how to overcome this? vba ms-access access-vba share|improve this question asked Nov 25 '14 at 11:46 pkrysiak 107110 add a comment| 1 Answer 1 active oldest votes up vote 0 down vote accepted The second If-statement should read If Not IsNull(rst1![Accepted]) Then The Is-operator is used to compare object references, thus the error message. share|improve this answer answered Nov 25 '14 at 11:48 paulroho 928718 Works like a charm, thanks a lot! –pkrysiak Nov 25 '14 at 11:51 Please accept the answer. Thx. –paulroho Nov 25 '14 at 11:53 I can only after at least 10 minutes pass since posting. Tried already. –pkrysiak Nov 25 '14 at 11:54 Ah, I see. Thx. –paulroho Nov 25 '14 at 11:55 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By postin