Access Vba Runtime Error 3219
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Access Vba Runtime Error 2498
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Access Vba Runtime Error 91
down vote favorite I try to write a query in my Access Project but this runtime error occures in the line, where SQL query is. This is my code: Private Sub Befehl80_Click() Dim rst As DAO.Recordset Set rst = CurrentDb.OpenRecordset("SELECT DISTINCT tb_KonzeptDaten.DFCC, tb_KonzeptDaten.OBD_Code AS Konzept_Obd,tb_KonzeptDaten.DFC INTO Test_Table FROM tb_KonzeptDaten", dbOpenDynaset) Me.txtDs = rst.RecordCount End Sub Would you please tell me how can I solve this problem and access vba runtime error 3075 why this error occures? vba ms-access access-vba share|improve this question asked Sep 4 '12 at 8:59 Kabi 2432716 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote accepted The sql is an action query, it creates a table. You cannot open a recordset from an action query. If you want to run the action query, you can say: Set db=CurrentDB ssql="SELECT DISTINCT tb_KonzeptDaten.DFCC, " _ & "tb_KonzeptDaten.OBD_Code AS Konzept_Obd,tb_KonzeptDaten.DFC " _ & "INTO Test_Table FROM tb_KonzeptDaten" db.Execute ssql, dbFailOnerror RecordsUpdated=db.RecordsAffected share|improve this answer answered Sep 4 '12 at 9:01 Fionnuala 77k665110 and what should I use instead? –Kabi Sep 4 '12 at 9:04 1 I have added notes on running an action query, but I am not quite sure what you want to do. –Fionnuala Sep 4 '12 at 9:05 Thank you Remou , you answerd my question –Kabi Sep 4 '12 at 9:21 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting
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Access Vba Runtime Error 3141
may have to register before you can post: click the access vba runtime error 6 overflow register link above to proceed. To start viewing messages, select the forum that you want runtime error 3073 access vba to visit from the selection below. Results 1 to 7 of 7 Thread: Error 3219 Invalid Operation Tweet Thread Tools Show Printable Version Subscribe to http://stackoverflow.com/questions/12260032/error-3219-invalid-operation this Thread… Search Thread Advanced Search Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 06-08-07,11:15 #1 KevCB226 View Profile View Forum Posts Registered User Join Date Sep 2005 Posts 240 Unanswered: Error 3219 Invalid Operation Hi Folks, I require your expertise and vast knowledge to sort http://www.dbforums.com/showthread.php?1619171-Error-3219-Invalid-Operation out my problem. I keep getting the run-time error 3219: Invalid Operation when trying to open a recordset based on QueryDefs. This is my code (the red text is where the error occurs): Code: Public Function MailMergeCriteria() Set QDef = CurrentDb.QueryDefs("qryMailMerge") QDef.Parameters("[Forms]![frmMailMerge]![txtTown]").Value = [Forms]![frmMailMerge]![txtTown] QDef.Parameters("[Forms]![frmMailMerge]![txtCounty]").Value = [Forms]![frmMailMerge]![txtCounty] QDef.Parameters("[Forms]![frmMailMerge]![txtPCode]").Value = [Forms]![frmMailMerge]![txtPCode] QDef.Parameters("[Forms]![frmMailMerge]![cmboBArea]").Value = [Forms]![frmMailMerge]![cmboBArea] QDef.Parameters("[Forms]![frmMailMerge]![cmboLetterName]").Value = [Forms]![frmMailMerge]![cmboLetterName] Set rs = QDef.OpenRecordset If rs.EOF Then MsgBox "No data found. Please check the criteria.", vbOKOnly, "RECEPE" Else 'Turn off warning messages DoCmd.SetWarnings False 'Run Mail Merge query DoCmd.OpenQuery "qryMailMerge", , acAdd 'If cmboLetterName.Value = "Train2GainOpenDayLetter" Then 'DoCmd.OpenQuery "qryOpenDay", , acAdd 'End If Set rs1 = CurrentDb().OpenRecordset("tblMailMerge", dbOpenDynaset) CurrentDb.Execute ("UPDATE tblMailMerge SET LetterBody ='" & Me!txtLetter & "'") 'Turn warnings back on DoCmd.SetWarnings True MailMergeIt (CurrentProject.path & "\Letters\T2G New Year Letter.doc") End If End Function Before I forget the rs, rs1 and QDef variables are assigned in general declarations, incase anyone was wond
soon) Ruby (coming soon) Getting Started Code Samples Resources Patterns and Practices App Registration Tool Events Podcasts Training API Sandbox Videos Documentation Office Add-ins Office Add-in Availability Office Add-ins Changelog Microsoft Graph API Office 365 Connectors Office 365 https://social.msdn.microsoft.com/Forums/office/en-US/d402a8d2-0771-458c-b57e-09e2d6f0c536/trying-to-open-a-linked-table-whats-going-on?forum=accessdev REST APIs SharePoint Add-ins Office UI Fabric Submit to the Office Store All Documentation https://www.yammer.com/ http://feeds.feedburner.com/office/fmNx Ask a question Quick access Forums home Browse forums users FAQ Search related threads Remove From My Forums Answered by: trying to open a linked table.... what's going on? Microsoft Office for Developers > Access for Developers Question 0 Sign in to vote run-time errors: 3219 and 3251! Trying to open a linked table in time error order to directly access some records. What am I doing wrong? dim db as dao.database dim rst asdao.Recordset Set db = CurrentDb() Set rsT = db.OpenRecordset(stLnkTblName) ' ,dbOpenTable) rst.Index = "PrimaryKey" - err 3251is raised here error3219is raised when I try to openwith 'dbOpenTable Monday, May 06, 2013 7:02 PM Reply | Quote Answers 0 Sign in to vote Hi all, Thanks for your help and consideration. I don't access vba runtime know why, or remember exactly the circumstance, under which FindFirst bombed, could have been a typo, however I abandoned that approach and rewrote the code to use the Seek method - that approach seemed more straightforwards to me.But Iwas having a hard time with it, probably because this was the first time I used it. But it's all good now. The problem was trying to OpenTable and do Seek method on a linked table and ACCESS wasnt having it. So I found another approach: Dim db As dao.Database Dim rsT As dao.RecordsetSet db = OpenDatabase(Mid(DBEngine(0)(0).TableDefs(stT1).Connect, 11)) Set rsT = db.OpenRecordset(stT1) ' directly opens the database containing the linked table and createsa recordset of Type 1(dbOpenTable) ' while the traditional: db=CurrentDB; set rst=db.OpenRecordset(stT1) 'creates a recordset of type 2 and you can'tdo Seek onType 2 rsT.Index = "PrimaryKey" rsT.Seek "=", lngKey If rsT.NoMatch Then 'not found 'skip Else rsT.Edit ~~~~ etc. - Cheers! Proposed as answer by Dummy yoyoModerator Wednesday, May 08, 2013 1:34 PM Marked as answer by Dummy yoyoModerator Tuesday, May 21, 2013 11:45 AM Tuesday, May 07, 2013 9:22 PM Reply | Quote All replies 0 Sign in to vote You can not open a linked table as a Table type recordset. The common alternative is to