Microsoft Access Runtime Error 91
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Runtime Error 91 Windows 7
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Object Variable Or With Block Variable Not Set Vba
you, helping each other. Join them; it only takes a minute: Sign up VBA ACCESS error 91 object variable or with block variable not set up vote 1 down vote favorite In a form, when pressing a https://support.microsoft.com/en-us/kb/327245 button called "asignar", I want to insert values to an existing table called "movimientos" Private Sub ASIGNAR_Click() Dim db As Database Dim rs As DAO.Recordset Set rs = db.OpenRecordset("MOVIMIENTOS") rs.AddNew rs("ESTATUSDOC").Value = "Blah" rs("FOLIOFED").Value = "Blah" rs("NOMBREDOC").Value = "Blah" rs("PREL").Value = "Blah" rs("CURP").Value = "Blah" rs.Update End Sub When I press run it keep showing error: Error 91 object variable or with block variable not set vba ms-access share|improve this question edited Jul 7 '15 http://stackoverflow.com/questions/31274060/vba-access-error-91-object-variable-or-with-block-variable-not-set at 16:37 Newd 2,01111028 asked Jul 7 '15 at 16:14 Adan Lopez 84 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted I think your syntax is a little off, your code should look like this: Private Sub ASIGNAR_Click() Dim db As DAO.Database Dim rs As DAO.Recordset Set db = CurrentDb Set rs = db.OpenRecordset("MOVIMIENTOS", dbOpenDynaset, dbAppendOnly) rs.AddNew rs("ESTATUSDOC").Value = "Blah" rs("FOLIOFED").Value = "Blah" rs("NOMBREDOC").Value = "Blah" rs("PREL").Value = "Blah" rs("CURP").Value = "Blah" rs.Update rs.Close Set rs = Nothing Set db = Nothing End Sub The issue likes like is primarily the way that you were declaring and setting your db variable. I have also adjusted the OpenRecordset to match what you are doing. share|improve this answer edited Jul 8 '15 at 12:11 answered Jul 7 '15 at 16:23 Newd 2,01111028 All good, though don't forget to close opened recordsets rs.Close and clean your memory with Set rs = Nothing and Set db = Nothing –Matt Hall Jul 7 '15 at 22:23 @MattHall Thanks for spotting that. –Newd Jul 8 '15 at 12:11 add a comment| up vote 0 down vote Changing Set rs = db.OpenRecordset("MOVIMIENTOS") to Set rs = CurrentDB.OpenRecordset("MOVIMIENTOS") should fix it as well. You can then lose the Dim db As Database share|improve this answer answered Jul 7 '15 at 16:
+ Ask a Question Need help? Post your question and get tips & solutions from a community of 418,589 IT Pros & Developers. It's quick & https://bytes.com/topic/access/answers/506689-run-time-error-91-object-variable-block-variable-not-set easy. Run-time error 91 Object Variable or With block variable not set P: n/a https://www.youtube.com/watch?v=kWT2YfSHpfM Richard Hollenbeck I've marked the line in this subroutine where I've been getting this error. It may be something stupid but I've been staring at this error trying to fix it for over an hour. I'm pretty sure the table and field names and controls are all named correctly, and the control referred to time error in the errant code is open, and it has data in it. Private Sub cmdAddIngredientToRecipe_Click() ' Get RecipeID for future action query Dim recipeID As Long Dim dbGetRecipeID As DAO.Database Dim rsGetRecipeID As DAO.Recordset Dim StrSQL As String Set dbGetRecipeID = CurrentDb() StrSQL = "SELECT tblRecipes.lngRecipeID FROM tblRecipes WHERE (((tblRecipes.lngRecipeID)= " & [Forms]![frmRecipes]![lngRecipeID] & "));" Set rsGetRecipeID = dbGetRecipeID.OpenRecordset(StrSQL, dbOpenDynaset) recipeID = rsGetRecipeID.Fields(0) Set rsGetRecipeID = Nothing time error 91 Set dbGetRecipeID = Nothing ' This works fine to this point ' Get IngredientID for future action query Dim IngredientID As Long Dim dbGetIngredientID As DAO.Database Dim rsGetIngredientID As DAO.Recordset 'I'm filling variables to use in an append query down later in this subroutine. StrSQL = "SELECT tblIngredients.lngIngredientID FROM tblIngredients WHERE tblIngredients.IngredientName = '" & cboIngredientName & "'" 'IngredientName is a text field. ' The next line is flagged as a problem. I get a run-time error 91" Object Variable ' or with block variable not set. I'm predicting something is wrong with my SQL statament on the previous line. Set rsGetIngredientID = dbGetIngredientID.OpenRecordset(StrSQL, dbOpenDynaset) IngredientID = rsGetIngredientID.Fields(0) Set rsGetRecipeID = Nothing Set dbGetRecipeID = Nothing MsgBox IngredientID 'just to test my code this far. End Sub Jun 29 '06 #1 Post Reply Share this Question 3 Replies P: n/a John Mishefske Richard Hollenbeck wrote: I've marked the line in this subroutine where I've been getting this error. It may be something stupid but I've been staring at this error trying to fix it for over an hour. I'm pretty sure the table and field names and controls are all named correctly, and the control referred to in the errant
Επιλέξτε τη γλώσσα σας. Κλείσιμο Μάθετε περισσότερα View this message in English Το YouTube εμφανίζεται στα Ελληνικά. Μπορείτε να αλλάξετε αυτή την προτίμηση παρακάτω. Learn more You're viewing YouTube in Greek. You can change this preference below. Κλείσιμο Ναι, θέλω να τη κρατήσω Αναίρεση Κλείσιμο Αυτό το βίντεο δεν είναι διαθέσιμο. Ουρά παρακολούθησηςΟυράΟυρά παρακολούθησηςΟυρά Κατάργηση όλωνΑποσύνδεση Φόρτωση... Ουρά παρακολούθησης Ουρά __count__/__total__ VBA Run-time Error '91' Object-variable or With block variable not set EverydayVBA ΕγγραφήΕγγραφήκατεΚατάργηση εγγραφής774774 Φόρτωση... Φόρτωση... Σε λειτουργία... Προσθήκη σε... Θέλετε να το δείτε ξανά αργότερα; Συνδεθείτε για να προσθέσετε το βίντεο σε playlist. Σύνδεση Κοινή χρήση Περισσότερα Αναφορά Θέλετε να αναφέρετε το βίντεο; Συνδεθείτε για να αναφέρετε ακατάλληλο περιεχόμενο. Σύνδεση Μεταγραφή Στατιστικά στοιχεία 11.812 προβολές 8 Σας αρέσει αυτό το βίντεο; Συνδεθείτε για να μετρήσει η άποψή σας. Σύνδεση 9 0 Δεν σας αρέσει αυτό το βίντεο; Συνδεθείτε για να μετρήσει η άποψή σας. Σύνδεση 1 Φόρτωση... Φόρτωση... Μεταγραφή Δεν ήταν δυνατή η φόρτωση της διαδραστικής μεταγραφής. Φόρτωση... Φόρτωση... Η δυνατότητα αξιολόγησης είναι διαθέσιμη όταν το βίντεο είναι ενοικιασμένο. Αυτή