Ms Access Run Time Error 424
Contents |
MariaDB PostgreSQL SQLite MS Office Excel Access Word Web Development HTML CSS Color Picker Languages C Language More ASCII Table Linux UNIX Java Clipart Techie Humor Advertisement Access Topics Combo Boxes Constants Database Date/Time Forms Functions Modules/VBA Queries Question/Answer runtime error 424 object required vba access 2010 Reports Security Shortcuts Standards Subforms Switchboard Tables Text boxes MS Access 2003: Run-time error vba runtime error 424 object required userform 424 (Object Required) This MSAccess tutorial explains how to fix the Run-time error '424': Object Required error in Access 2003 (with screenshots
Run Time Error 424 Object Required Access 2010
and step-by-step instructions). Question: In Microsoft Access 2003/XP/2000/97, I'm using VBA code to set a value on another form and I keep getting a "Run-time error '424': Object Required" error. I can't seem to figure out
Runtime Error 424 Object Required Excel 2013
why it won't work. The object that I'm referencing is valid and it should work. What am I doing wrong? Answer: The problem isn't your code, it's that the Visual Basic editor does not recognize your form. In fact, the Visual Basic editor will not recognize your form until you've invoked the Code Builder (for your form or any object on your form) at least once. Let's look at an example. In run-time error 424 object required vba our database, we've created two forms - one called form1 and another called form2. We've invoked the Code Builder on form2. When we take a look at the Visual Basic editor, we can see that form2 exists, but we can't see form1. To fix this problem, we'll open form1 in design view. Next, display the properties for the Form object. Click on the button (with the three dots) on the "On Open" event for the form. When the Choose Builder window appears, select Code Builder and click on the OK button. Now when you return to the Visual Basic editor, form1 would appear in the list. You can actually fix this error by invoking the Code Builder on any event in the form (or any one of the objects on the form). We've just chosen the form's "On Open" event for demonstration purposes. Now when you run your VBA code, the "Object required" error should no longer appear. Share this page: Advertisement Back to top Home | About Us | Contact Us | Testimonials | Donate While using this site, you agree to have read and accepted our Terms of Service and Privacy Policy. We use advertisements to support this website and fund the development of new content. Copyright © 2003-2016 TechOnTheNet.com. All rights reserved.
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings
Runtime Error 424 Object Required Vb6
and policies of this site About Us Learn more about Stack Overflow compile error object required vba the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation run time error 424 object required excel macro Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it https://www.techonthenet.com/access/questions/obj_required.php only takes a minute: Sign up Runtime error 424 in VBA Access up vote 0 down vote favorite Dim rst1 As DAO.Recordset Dim rst2 As DAO.Recordset Set rst1 = CurrentDb.OpenRecordset("Table1", 2) Set rst2 = CurrentDb.OpenRecordset("Table2", 2) Dim strName As String If Not (rst1.EOF And rst1.BOF) Then rst1.MoveFirst Do Until rst1.EOF rst1.Edit strName = rst1![Name] rst2.FindFirst ("[Name] = '" & strName http://stackoverflow.com/questions/27125876/runtime-error-424-in-vba-access & "'") If rst2.NoMatch Then If rst1![Accepted] Is Not Null Then 'here is the line causing error ... 'more code going on So, above is an excerpt from my code. I simplified it as much as possible without changing context. The situation is as follows: I have two tables and want to check whether a person from Table1 is already present in Table2. If that's the case then just ignore it. Whereas if it's not, then I want to check another condition in Table1 (if DateTime field [Accepted] is not NULL) and if it is satisfied to proceed with processing that person's data. However, even though I am able to get the rst1![Name] properly, when I get into the inner if I get the 424 runtime error: Object required. Any ideas how to overcome this? vba ms-access access-vba share|improve this question asked Nov 25 '14 at 11:46 pkrysiak 107110 add a comment| 1 Answer 1 active oldest votes up vote 0 down vote accepted The second If-statement should read If Not IsNull(rst1![Accepted]) Then The Is-operator is used to
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more http://stackoverflow.com/questions/33669014/object-required-error-424-ms-access-2010 about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Object Required - error 424 MS ACCESS 2010 up vote 1 down time error vote favorite I'm really new at VBA but I have this same code in another database, and now I've just copied the code and paste in another database but I get this Object Required error in the last line. The code is bigger but I've just stopped on the line where I get the error. Dim frm As Form, ctl As Control Dim varItm As Variant Dim stgMO, stgPID, time error 424 stMail, stgMailCC As String Dim Question As Long Dim OutApp, OutMail As Object Set frm = Forms!Overview Set ctl = frm!cl_onboarding stgMO = ctl.Column(7) stgPID = ctl.Column(2) stgMail = ctl.Column(8) stgMailCC = ctl.Column(9) Question = MsgBox("Do you want to send an e-mail containing the codes for this Agent?", vbYesNo, "Send e-mail") If Question = vbYes Then Set OutApp = Outlook.Application object access-vba required share|improve this question asked Nov 12 '15 at 10:14 Joao Alves 61 What happens if you change Set OutApp = Outlook.Application to Set OutApp = CreateObject("Outlook.Application") –HansUp Nov 12 '15 at 20:20 add a comment| 2 Answers 2 active oldest votes up vote 0 down vote you have dim stMail as a variable but then you use stgMail. just check your spelling. You also use dim question as long, this confuses me a bit because I thought long meant an integer (there are min and max values but I cant remember). share|improve this answer edited Nov 12 '15 at 14:56 answered Nov 12 '15 at 14:50 LiamH 1,1831526 Well spotted! @joao: please add Option Explicit to the top of your module. This doesn't cause the Object Required error though. It will cause other problems down the road. -- L