Ms Access Runtime Error 91
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How To Fix Runtime Error 91
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Run-time Error '91' In Excel Macro
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Object Variable Or With Block Variable Not Set Access 2010
with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow object variable or with block variable not set vba is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up VBA ACCESS error 91 object variable or with block variable not set up https://support.microsoft.com/en-us/kb/327245 vote 1 down vote favorite In a form, when pressing a button called "asignar", I want to insert values to an existing table called "movimientos" Private Sub ASIGNAR_Click() Dim db As Database Dim rs As DAO.Recordset Set rs = db.OpenRecordset("MOVIMIENTOS") rs.AddNew rs("ESTATUSDOC").Value = "Blah" rs("FOLIOFED").Value = "Blah" rs("NOMBREDOC").Value = "Blah" rs("PREL").Value = "Blah" rs("CURP").Value = "Blah" rs.Update End Sub When I press run it keep showing error: Error 91 http://stackoverflow.com/questions/31274060/vba-access-error-91-object-variable-or-with-block-variable-not-set object variable or with block variable not set vba ms-access share|improve this question edited Jul 7 '15 at 16:37 Newd 2,01111028 asked Jul 7 '15 at 16:14 Adan Lopez 84 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote accepted I think your syntax is a little off, your code should look like this: Private Sub ASIGNAR_Click() Dim db As DAO.Database Dim rs As DAO.Recordset Set db = CurrentDb Set rs = db.OpenRecordset("MOVIMIENTOS", dbOpenDynaset, dbAppendOnly) rs.AddNew rs("ESTATUSDOC").Value = "Blah" rs("FOLIOFED").Value = "Blah" rs("NOMBREDOC").Value = "Blah" rs("PREL").Value = "Blah" rs("CURP").Value = "Blah" rs.Update rs.Close Set rs = Nothing Set db = Nothing End Sub The issue likes like is primarily the way that you were declaring and setting your db variable. I have also adjusted the OpenRecordset to match what you are doing. share|improve this answer edited Jul 8 '15 at 12:11 answered Jul 7 '15 at 16:23 Newd 2,01111028 All good, though don't forget to close opened recordsets rs.Close and clean your memory with Set rs = Nothing and Set db = Nothing –Matt Hall Jul 7 '15 at 22:23 @MattHall Thanks for spotting that. –Newd Jul 8 '15 at 12:11 add a comment| up vote 0 d
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About http://stackoverflow.com/questions/33308649/run-time-error-91-vba-access Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack https://www.experts-exchange.com/questions/28200381/MS-Access-Error-91-Object-Variable-or-With-block-variable-not-set.html Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Run-time error '91' vba-access up vote 1 time error down vote favorite Hey my program checks for a zip file and copies it to another directory. However I stumbled upon "Run time error '91' object variable or With block variable not set" on oApp when I compiled it. Sub UnZip(Fname As Variant) Dim oApp As Object Dim FileNameFolder As Variant FileNameFolder = "P:\" Set oApp = CreateObject("Shell.Application") oApp.Namespace(FileNameFolder).CopyHere oApp.Namespace(Fname).items End Sub What's the problem? I'm time error 91 using MS access 2010 vba access-vba share|improve this question edited Oct 23 '15 at 17:58 MatthewD 4,7834931 asked Oct 23 '15 at 17:57 Kenny Nguyen 666 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote .Copyhere works on folder objects. Sub UnZip(Fname As Variant) dim objShell dim objFolder set objShell = CreateObject("shell.application") set objFolder = objShell.NameSpace("P:") If not objFolder is nothing then objFolder.CopyHere(Fname) End If End Sub Fname must include both path and filename with extension. share|improve this answer edited Oct 23 '15 at 18:09 answered Oct 23 '15 at 18:03 MatthewD 4,7834931 In my case, I got my Fname to be a FolderItem. However when I run objFolder.CopyHere(Fname), I get the same error "'91' object variable or With block variable not set" –Kenny Nguyen Oct 26 '15 at 20:20 Fname should be passed to the unzip sub as a string. –MatthewD Oct 26 '15 at 20:28 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email
for Help Receive Real-Time Help Create a Freelance Project Hire for a Full Time Job Ways to Get Help Ask a Question Ask for Help Receive Real-Time Help Create a Freelance Project Hire for a Full Time Job Ways to Get Help Expand Search Submit Close Search Login Join Today Products BackProducts Gigs Live Careers Vendor Services Groups Website Testing Store Headlines Experts Exchange > Questions > MS Access Error 91 "Object Variable or With block variable not set" Want to Advertise Here? Solved MS Access Error 91 "Object Variable or With block variable not set" Posted on 2013-07-31 MS Access 1 Verified Solution 5 Comments 1,408 Views Last Modified: 2013-09-26 Hello, I seem to have a problem with Error 91 in my Access Application. The error only occurs after a first error happens. i.e., User gets an Error (doesn't seem to matter what error), after user clicks ok on the Messgaebox my error handling provides, they keep using the application (or sometimes let it sit idle) in a different spot as to not receive the same error again. After so long (if user left application idle) or when user starts doing something else, the Error 91 "Object Variable or with block variable not set" occurs. Can anyone shed some light as to why i get this error? Any help is appreciated. Thanks, rcimasi 0 Question by:rcimasi Facebook Twitter LinkedIn Google LVL 61 Active 1 day ago Best Solution bymbizup << they are reset i.e., integer to 0, String to ""? or am i off with that >> I believe that's correct - they reinitialize to whatever the default value is for that data type (0 for numeric, "" for Go to Solution 5 Comments LVL 61 Overall: Level 61 MS Access 60 Message Active 1 day ago Expert Comment by:mbizup2013-07-31 Do you have any recordset objects or other object variables defined as Global or Public? Global variables lose their values when errors occur in your application.... which may cause error 91 if they are then used elsewhere. Just a guess.. without seeing your database, it's hard to say. 0 LVL 61 Overall: Level 61 MS Access 60 Message Active 1 day ago Expert Comment by:mbizup2013-07-31 Can you post a line of code that gets highlighted by the debugger when this error occurs? 0 Message Active 1 day ago Author Comment by:rcimasi2013-07-31 Thanks for the response. In reference to your first post, I do not have any public/global OBJECT variables. I do however have a fair amount of Public/Global variables, mainly type String or Integer. When you say glob