C Error Too Few Arguments To Function
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Error Too Few Arguments To Function ‘ndo_dflt_bridge_getlink’
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4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up too few arguments to function and can't be used as a function-— beginning C up vote 2 down vote favorite Hi i am a beginner, and I have this homework for my beginning C class. I error too few arguments to function ‘vfs_rename’ keep getting errors for the program I wrote particularly with my function. Here's my program: #include
Programming Boards C Programming Too few arguments error. Calling a function from within a function? Getting started with C or error too few arguments to function ‘exit’ C++ | C Tutorial | C++ Tutorial | C and C++ FAQ too few arguments to function exit | Get a compiler | Fixes for common problems Thread: Too few arguments error. Calling a function from too few arguments to function calloc within a function? Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 10-23-2012 #1 tmac619619 View http://stackoverflow.com/questions/6038713/too-few-arguments-to-function-and-cant-be-used-as-a-function-beginning-c Profile View Forum Posts Registered User Join Date Oct 2012 Posts 158 Too few arguments error. Calling a function from within a function? Code: double calc_baking_time(char bread_type, char loaf, char manual); int main() { } void instructions_white_single_manual() { printf("Primary kneading: 15 mins\n"); printf("Primary rising: 60 mins\n"); printf("Secondary kneading: 18 mins\n"); printf("Secondary rising: 20 mins\n"); printf("Loaf shaping: 2 seconds\n"); printf("You should remove http://cboard.cprogramming.com/c-programming/151656-too-few-arguments-error-calling-function-within-function.html the dough for manual baking.\n"); calc_baking_time(char bread_type, char loaf, char manual); Basically im trying to call another function from within my instructions_white_single_bake, but i keep getting "expected expression before char" error Last edited by tmac619619; 10-23-2012 at 02:32 PM. 10-23-2012 #2 AndiPersti View Profile View Forum Posts Registered User Join Date May 2012 Posts 1,066 Here Code: double calc_baking_time(char bread_type, char loaf, char manual); you declare your function to take three arguments. Here Code: calc_baking_time(); you call it without any arguments. What do you not understand when the compiler tells you that you use "too few arguments"? Bye, Andreas 10-23-2012 #3 tmac619619 View Profile View Forum Posts Registered User Join Date Oct 2012 Posts 158 Originally Posted by AndiPersti Here Code: double calc_baking_time(char bread_type, char loaf, char manual); you declare your function to take three arguments. Here Code: calc_baking_time(); you call it without any arguments. What do you not understand when the compiler tells you that you use "too few arguments"? Bye, Andreas 0.0. i updated the OP. Thanks for catching my mistake 10-23-2012 #4 Matticus View Profile View Foru
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void display_members(Member member_array[], int& amountofmembers) { assert (amountofmembers > 0); string gender_and_paid; cout << "Surname \t Forename \t Street+housenr \t Postcode \t City \t M/F \t Paid" << "____________________________________________________________________________"; for (int counter=0; counter < amountofmembers; counter++) { if (member_array[counter].gender == Male) { gender_and_paid = "M"; } else { gender_and_paid = "F"; } if (member_array[counter].paid) { gender_and_paid += "yes"; } else { gender_and_paid += "No"; } cout << member_array[counter].surname << " "<< member_array[counter].forename << " \t" << member_array[counter].street_name << " \t" << member_array[counter].postcode << " \t" << member_array[counter].city_name << "\t" << member_array[counter].year_of_birth << " \t"; } } 1
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case 1 : display_members(); Nov 22, 2011 at 12:23am UTC Moschops (7061) I just created this void No, you created a function. But it gives the following error: too few arguments to function You're calling it incorrectly. You must feed it two parameters when you call it. How many are you passing in at the minute? Let's see: display_members(); Zero. How many does it want? void display_members(Member member_array[], int& amountofmembers) Two. Last edited on Nov 22, 2011 at 12:24am UTC Nov 24, 2011 at 7:38pm UTC Aramil of Elix