Hide Undefined Index Error Php
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Undefined Variable Php
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How To Solve Undefined Index Error In Php
helping each other. Join them; it only takes a minute: Sign up PHP: “Notice: Undefined variable” and “Notice: Undefined index” up vote 550 down vote favorite 131 I am running a PHP script, and keep getting errors like: Notice: Undefined variable: my_variable_name in C:\wamp\www\mypath\index.php on line 10 or Notice: Undefined index: my_index C:\wamp\www\mypath\index.php on line 11 Line 10 undefined index error in php post and 11 looks like this: echo "My variable value is: " . $my_variable_name; echo "My index value is: " . $my_array["my_index"]; What do these errors mean? Why do they appear all of a sudden? I used to use this script for years and I've never had any problem. What do I need to do to fix them? This is a General Reference question for people to link to as duplicate, instead of having to explain the issue over and over again. I feel this is necessary because most real-world answers on this issue are very specific. Related Meta discussion: What can be done about repetitive questions? Do “reference questions” make sense? php arrays variables warnings undefined-index share|improve this question edited Jul 27 at 4:29 community wiki 20 revs, 13 users 36%Pekka 웃 2 possible duplicate of Reference - What does this error mean in PHP? –meagar♦ Oct 8 '13 at 15:25 it's just a notice to ensure that you use it right and it's not a misspell
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About Us Learn more about Stack Overflow the company Business Learn more about how to remove undefined variable error in php hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss undefined index $_get Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Undefined Index Error http://stackoverflow.com/questions/4261133/php-notice-undefined-variable-and-notice-undefined-index Reporting in WAMP and PHP up vote 2 down vote favorite I'm using wamp to develop a php application. My problem is that everytime I call a variable that sometimes happens to not have a value, I get an error that says it's an undefined index. Is there a way to change the error reporting to not display this error? I have to use isset http://stackoverflow.com/questions/7226875/undefined-index-error-reporting-in-wamp-and-php to determine if it's set or not before I output the variable, but I don't want to have to do this. There are areas of my application that make this method inefficient. php wamp error-reporting share|improve this question asked Aug 29 '11 at 6:33 ShoeLace1291 86752039 You do realize that every warning PHP generates (even if it isn't shown) incurs a performance penalty? Talk about inefficient... –Jani Hartikainen Aug 29 '11 at 6:36 add a comment| 5 Answers 5 active oldest votes up vote 3 down vote If you don't want to change error_reporting level you should check, is variable exists, before using it. You may use if(isset($var)) for it. You may add some function, to not write it always. Example: function getPost($name,$default=null){ return isset($_POST[$name])?$_POST[$name]:$default; } Usage: getPost('id'); getPost('name','Not Logged In'); share|improve this answer edited Aug 29 '11 at 7:42 answered Aug 29 '11 at 7:28 RiaD 24.1k54086 add a comment| up vote 1 down vote You can just turn off the mechanism in php.ini. This thread would help you. http://www.wampserver.com/phorum/read.php?2,70609,70700 But it generally its better to take care of undefined variables as they might save you some run time tr
i remove this "Notice: Undefined index: qid in e:\inetpub\wwwroot\ ry\ew.php on line https://www.sitepoint.com/community/t/how-can-i-remove-notice-from-my-php-pages/1774 3 Notice: Undefined index: B1 in e:\inetpub\wwwroot\ ry\ew.php on line 4 Notice: Undefined index: S1 in e:\inetpub\wwwroot\ ry\ew.php on line 5"what is this ?Is this error or warnning?Plz help me.my code is as follows:
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markl999 2004-11-01 07:00:53 UTC #2 $qid = empty($_POST['qid']) ? '' undefined index error : $_POST['qid']; $submit = empty($_POST['B1']) ? '' : $_POST['B1']; $text = empty($_POST['S1']) ? '' : $_POST['S1']; The above is just a short way of doing: if(empty($_POST['qid'])){ $qid = ''; } else { $qid = $_POST['qid']; } astericks 2004-11-01 07:11:52 UTC #3 at the top of the parse, set the following: error_reporting(E_PARSE); Note: this will only allow parse errors to be shown. devised 2004-11-01 07:11:53 UTC #4 You could also turn off notices in the error reporting if you have access to php.ini: ; - Show all errors, except for notices;error_reporting = E_ALL & ~E_NOTICE Tim_Rogovets 2004-11-01 07:13:10 UTC #5 Also you can add '@' to the start of any operator to make php silent when performing the current operation. No errors, warnings, notices would be output.I.E.: @$qid= $_POST['qid']; ujjwal 2004-11-01 07:18:14 UTC #6 thank you markl999 system 2014-10-08 00:30:56 UTC #7 Home Categories FAQ/Guidelines Terms of Service Privacy Policy Powered by Discourse, best viewed with JavaScript enabled Shop Versioning Reference Articles Premium