How To Ignore Undefined Variable Error In Php
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Notice Undefined Index Php
Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, undefined index error in php helping each other. Join them; it only takes a minute: Sign up How to ignore undefined variable error in PHP up vote 2 down vote favorite 2 I recently setup a new web server and I'm getting undefined how to solve undefined index error in php variable error. If I use variables without initializing, it gives me an error. The source code did not change. Only the LAMP environment did. How would you solve this problem? Thanks php linux share|improve this question asked Feb 21 '11 at 1:21 webnat0 1,13831735 2 Need to shut off/lower the error checking either in the php.ini or using error_reporting -- though you should be defining your variables before using them. ;p –Brad Christie Feb 21
Undefined Index Error In Php Post
'11 at 1:23 Duplicate: stackoverflow.com/questions/4084296/… –Orbling Feb 21 '11 at 1:28 add a comment| 3 Answers 3 active oldest votes up vote 6 down vote accepted Well... You should define all your variables, those warnings are there for a reason, to make you code better. Undefined variables can easily lead to typo errors in variable names. You can change the *error_reporting* level, above E_NOTICE to get rid of that, but it is highly unadvisable. share|improve this answer answered Feb 21 '11 at 1:25 Orbling 15.8k33856 add a comment| up vote 3 down vote You can set notices to not show. error_reporting(E_ALL & ~E_NOTICE) You should be developing with error_reporting(E_ALL | E_STRICT) share|improve this answer answered Feb 21 '11 at 1:24 Spechal 1,18741229 add a comment| up vote 1 down vote you can change your error_reporting as people said, but if you want keep the default error_reporting configuration. you may use @ operator. e.g: @$post share|improve this answer answered Nov 13 '15 at 14:41 antoniputra 6381517 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service. Not the answer
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Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a http://stackoverflow.com/questions/5061432/how-to-ignore-undefined-variable-error-in-php minute: Sign up PHP: “Notice: Undefined variable” and “Notice: Undefined index” up vote 550 down vote favorite 131 I am running a PHP script, and keep getting errors like: Notice: Undefined variable: my_variable_name in C:\wamp\www\mypath\index.php on line 10 or Notice: Undefined index: my_index C:\wamp\www\mypath\index.php on line 11 Line 10 and 11 looks like this: echo "My variable value is: " . http://stackoverflow.com/questions/4261133/php-notice-undefined-variable-and-notice-undefined-index $my_variable_name; echo "My index value is: " . $my_array["my_index"]; What do these errors mean? Why do they appear all of a sudden? I used to use this script for years and I've never had any problem. What do I need to do to fix them? This is a General Reference question for people to link to as duplicate, instead of having to explain the issue over and over again. I feel this is necessary because most real-world answers on this issue are very specific. Related Meta discussion: What can be done about repetitive questions? Do “reference questions” make sense? php arrays variables warnings undefined-index share|improve this question edited Jul 27 at 4:29 community wiki 20 revs, 13 users 36%Pekka 웃 2 possible duplicate of Reference - What does this error mean in PHP? –meagar♦ Oct 8 '13 at 15:25 it's just a notice to ensure that you use it right and it's not a misspell or something... –Amir Surnay Oct 30 '13 at 7:12 the variable might not have been initialized. Are you initializing the variable from
are ignored. jstewmc November 2011 Hi guys, I downloaded and installed FuelPHP 1.1-rc1 tonight, and it's awesome. My only problem is that I can't turn the http://fuelphp.com/forums/discussion/5829 notices off! I have several variables in my template file that don't always have a value, so I don't pass them. For example, I have a variable $body_classname that I use when I need it, and don't pass it when I don't need it...
PHP has never really complained about it, but FuelPHP is displaying notices on undefined index my page... [b]Notice![/b] ErrorException [ NOTICE ]: Undefined variable "body_classname" [b]APPPATH/views/template.php @ line 49[/b] I know it's undefined, I didn't pass it in. Don't worry about it Fuel, just get on with it. I tried changing the 'errors' options in fuel/app/config/config.php (line 51). I changed 'throttle' to 0, no difference. I changed 'notices' to false, no difference. I changed the 'continue_on' array error in php to an empty array, no difference. The notices remain. I thought maybe the config file was being cached magically somewhere somehow (I don't have caching enabled), but when I change line 43 to default to production environment, the notices dissappear. // old, defaults to development 43. 'environment' => (isset($_SERVER['FUEL_ENV']) ? $_SERVER['FUEL_ENV'] : Fuel::DEVELOPMENT), // new, defaults to production 43. 'environment' => (isset($_SERVER['FUEL_ENV']) ? $_SERVER['FUEL_ENV'] : Fuel::PRODUCTION), Am I missing something, or is this an issue? Thanks! Harro Verton November 2011 Imho that is a very bad programming practice. Either always pass a value, or check if the value exists before using it. The reason for seeing these now is that FuelPHP in development mode enables all error messages. In your previous setup you'd probably filtered notices. Not a good idea, because your logfiles will still overflow with these messages, and your application is slower because of all the error handling, jstewmc November 2011 Thanks Wan, you pointed me in the right direction. I usually use conditional statements, but even those got notices: // try a compact tertiary