Access 2007 If Error
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Applies To: Access 2016, Access 2013, Access 2010, Access 2007, Access 2010 Developer, Access 2007 Developer, Access 2013 Developer, Less Applies To: Access
Access 2007 If Statement
2016 , Access 2013 , Access 2010 , Access 2007 access 2007 if statement in query criteria , Access 2010 Developer , Access 2007 Developer , Access 2013 Developer , More... Which version access 2007 if then do I have? More... Returns a Boolean value indicating whether an expression> is an error value. Syntax IsError ( expression ) The required expressionargument can be
Access 2007 If Then Else
any valid expression. Remarks Error values are created by converting real numbers to error values using the CVErr function. The IsError function is used to determine if a numeric expression represents an error. IsError returns True if the expression argument indicates an error; otherwise, it returns False. Example Note: Examples that follow demonstrate the
If Function In Access 2007
use of this function in a Visual Basic for Applications (VBA) module. For more information about working with VBA, select Developer Reference in the drop-down list next to Search and enter one or more terms in the search box. This example uses the IsError function to check if a numeric expression is an error value. The CVErr function is used to return an Error Variant from a user-defined function. Assume UserFunction is a user-defined function procedure that returns an error value; for example, a return value assigned with the statement UserFunction = CVErr(32767), where 32767 is a user-defined number.
Dim ReturnVal, MyCheckShare Was this information helpful? Yes No Great! Any other feedback? How can we improve it? Send No thanks Thank you for your feedback! × English (United States) Contact Us Privacy & Cookies Terms of use & sale Trademarks Accessibility Legal © 2016 Microsoft
ReturnVal = UserFunction()
MyCheck = IsError(ReturnVal) ' Returns True.
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If Condition In Access 2007
the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation iferror 2007 Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it https://support.office.com/en-us/article/IsError-Function-40a89200-138b-4e60-b254-34aea51b2e6b only takes a minute: Sign up iif (Iserror ()) function still returning #error up vote 5 down vote favorite I have the following function that creates a column in my query: MTD: IIf(IsError(FormatNumber([62xx]![F40])),0,FormatNumber([62xx]![F40])) This is linked to an Excel file and where people put numbers and text in the same column (F40 in this example). I need to know if the http://stackoverflow.com/questions/22670418/iif-iserror-function-still-returning-error thing I am looking at is a number or text. If it's text I want a zero, if it is a number I want the number. I know that when I use FormatNumber([C107_62xx]![F40]) on a text line I get an error. I would assume when I get an error, then my iif formula above would convert that to a zero and the world would rejoice. For some reason I am still getting a #error even with my iif statement. What am I doing wrong? I have also tried using the IsNumeric function but I still get #NUM! errors that come through. function ms-access ms-access-2010 share|improve this question edited Mar 26 '14 at 19:16 HansUp 79.1k114371 asked Mar 26 '14 at 18:49 Nigel 2041211 add a comment| 1 Answer 1 active oldest votes up vote 5 down vote accepted IsError does not do what you think it does. From the help topic, it "Returns a Boolean value indicating whether an expression is an error value." Not whether the expression triggers an error, but whether the expression is an error value
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