Division By 0 Error Php
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack php division by zero error Overflow the company Business Learn more about hiring developers or posting ads with us php division by zero exception Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a perl division by zero community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Division by zero error up vote 3 down vote favorite 2 I have this code throwing
Sql Division By Zero
up the error: I have tried adding this line: if ($res === 0) { echo "not eligible"; } but it still gives the error. any ideas? php how to solve division by zero in php division divide-by-zero share|improve this question edited Oct 18 '13 at 18:38 Kamiccolo 2,93111732 asked Oct 18 '13 at 18:29 Seth-77 871213 can you indent your code! –Jason OOO Oct 18 '13 at 18:30 sorry, its the way its written in the script! –Seth-77 Oct 18 '13 at 18:37 add a comment| 5 Answers 5 active oldest votes up vote 7 down vote accepted You'd want to check $val2 before the division occurs: share|improve this answer answered Oct 18 '13 at 18:34 Chris Rasco 2,10011018 add a comment| up vote 1 down vote if($val2!=0){ //Do it }else{ //Don't } share|improve this answer answered Oct 18 '13 at 18:30 undone 6,20232756 add a comment| up vote 1 down vote You have the following in your code: $val2 = count($allcontent); If the $allcontent array is empty, then the value of $val2 will be 0, and you will essentially be doing: $res = ( $val1 / 0) * 100; As expected, this will cause PHP
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Division By Zero In Wordpress
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Warning Division By Zero In Woocommerce
just like you, helping each other. Join them; it only takes a minute: Sign up PHP, How to catch a division by zero? up vote 18 down vote favorite 2 I have a large mathematical expression that http://stackoverflow.com/questions/19456652/division-by-zero-error has to be created dynamically. For example, once I have parsed "something" the result will be a string like: "$foo+$bar/$baz";. So, for calculating the result of that expression I'm using the eval function... something like this: eval("\$result = $expresion;"); echo "The result is: $result"; The problem here is that sometimes I get errors that says there was a division by zero, and I don't know how to catch that Exception. I have tried things http://stackoverflow.com/questions/3071067/php-how-to-catch-a-division-by-zero like: eval("try{\$result = $expresion;}catch(Exception \$e){\$result = 0;}"); echo "The result is: $result"; Or: try{ eval("\$result = $expresion;"); } catch(Exception $e){ $result = 0; } echo "The result is: $result"; But it does not work. So, how can I avoid that my application crashes when there is a division by zero? Edit: First, I want to clarify something: the expression is built dynamically, so I can't just eval if the denominator is zero. So... with regards to the Mark Baker's comment, let me give you an example. My parser could build something like this: "$foo + $bar * ( $baz / ( $foz - $bak ) )" The parser build the string step by step without worrying about the value of the vars... so in this case if $foz == $bak there's in fact a division by zero: $baz / ( 0 ). On the other hand as Pete suggested, I tried: But it does not print anything. php exception divide-by-zero share|improve this question edited Mar 13 '14 at 19:01 Eric Leschinski 46.3k23221190 asked Jun 18 '10 at 15:41 Cristian 137k44297236 1 Can you check if $expression is dividing by zero beforehand? –Anthony Forloney Jun 18 '
dividing with has been set to zero (this number is called the divisor).The variable you're dividing with has been set to null.The variable does not exist. http://thisinterestsme.com/php-warning-division-zero/ i.e. It has not been set.Example code that will reproduce the https://www.sitepoint.com/community/t/division-by-zero-problem-in-php/64165 error:PHP $var = 0; echo 12 / $var;12$var = 0;echo 12 / $var;If you run the code above, you'll be faced with the following error: Warning: Division by zero. This is because our variable $var has been set to 0.Fortunately, this common warning can be avoided division by by carrying out some very basic checking. To avoid this type of error, you can wrap your division arithmetic inside an IF statement, like so:PHP $var = 0; if($var > 0){ echo 12 / $var; }1234$var = 0;if($var > 0){echo 12 / $var;}The code above is pretty simple. Basically, we make sure that the variable (in this division by zero case, our divisor) is greater than 0 before we attempt our division calculation.PS: It is important to note that this will not prevent your script from executing. In other languages, division by zero can lead to an exception that essentially kills the program. Comments comments3SHARESFacebookTwitterRelated posts:Slow MySQLi connection Creating a "what's hot" algorithm with PHP and MySQL PHP: Error handling with cURL Avoiding undefined index / offset errors in PHP This entry was posted in Code, PHP Tutorials by ThisInterestsMe. Post navigation ← Parking The Bus - Mourinho FIFA 15 Tactics Searching between dates in MySQL. → Search Search for: Recent Posts How to set the cruise control on a Vauxhall / Opel Insignia. PHP: Cache SQL results on file system. Convert EURO to GBP (Sterling) using PHP Move a file with PHP. PHP: Get last day of month. MySQL: SELECT all records from today using PHP. CategoriesAbandoned WebsitesCall of DutyCodeData DownloadsDayZFantasy FootballFootballFunnyGamingIrelandJavaScriptMySQLNostalgiaPeople of the InternetPHP TutorialsProgramming HumorRantSEO / WebmasterTips & TricksTwitter TrendsUncategorizedVideosWexfordWexford News Toolbox Premier League Fixtures Difficulty
field as the user types in. everytime I type an entry on the input field I keep getting an error message: Warning division by Zero in. The culprit in the code is this part: if(strlen($queryString) > 0) { and while ($row = mysql_fetch_array($result)). The php code below is that part that checks that the user types an entry and then performs the look up: Any idea how to solve the issue? thanks in advance 0) { $sql = 'SELECT * FROM my table WHERE destination LIKE '%$queryString%' ' ; $result = mysql_query($sql); while ($row = mysql_fetch_array($result)) {