Division By Zero In Access Error
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Ms Access Division By Zero Error
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Microsoft Access Division By Zero Error
boxes MS Access 2003: Handling Divide by Zero errors in queries This MSAccess tutorial explains how to handle divide by zero errors in queries in Access 2003
Division By Zero Error In Teradata
(with screenshots and step-by-step instructions). See solution in other versions of Access: Access 2007 Access 2003 Question: In Microsoft Access 2003/XP/2000/97, I'm trying to write a formula in a query as follows: [Price]/[Quantity] Most of the times this formula works, but in some cases the [Quantity] field is zero so when the formula divides division by zero error java zero by zero, the result comes up as #Error. Is there a way I can tell Access, if dividing by zero, the result is zero? Answer: You can use the iif function in your Access query to handle these cases. We'll demonstrate how to do this with the example below. In this example, we've used the iif function to return 0 if the [Quantity] is 0. Otherwise, it would return the value of [Price] divided by [Quantity]. This is achieved with the following formula: IIf([Quantity]=0,0,[Price]/[Quantity]) Now, your Access query should no longer return an error when a [Quantity] of 0 is encountered. Share this page: Advertisement Back to top Home | About Us | Contact Us | Testimonials | Donate While using this site, you agree to have read and accepted our Terms of Service and Privacy Policy. We use advertisements to support this website and fund the development of new content. Copyright © 2003-2016 TechOnTheNet.com. All rights reserved.
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Post your question and get tips & solutions from a community of 418,497 IT Pros & Developers. It's quick & easy. Divide by Zero on Report (#Num!) P: 74 ollyb303 Hi, I have created a report in my Access https://bytes.com/topic/access/answers/755413-divide-zero-report-num db which has two columns - I'll call them Number1 and Number2. I have added a textbox to calculate a percentage from these two numbers =([Number1]/[Number2]) with the format property set as percentage. My problem. Sometimes the number in Number2 is http://p2p.wrox.com/book-beginning-access-2003-vba/33759-iif-statement-division-zero-error.html a zero, which means the result of the expression is invalid and gives me "#Num!" - I understand why this is happening, but I wondered if there was a way around it. What I would like to happen is that division by when it is trying to divide by zero, the #Num! is substituted for a blank space or a zero. This is purely cosmetic as I would like my report to look neater. Any help gratefully received. Thanks, Olly Jan 4 '08 #1 Post Reply Share this Question 9 Replies Expert Mod 15k+ P: 29,922 NeoPa Try setting the result to : Expand|Select|Wrap|Line Numbers =IIf([Number2]=0,[Number1],[Number1]/[Number2]) Jan 4 '08 #2 reply P: 74 ollyb303 Perfect! Thanks so much, this works a treat. Jan 4 division by zero '08 #3 reply Expert Mod 15k+ P: 29,922 NeoPa No worries Olly. Just pleased it helped :) Jan 4 '08 #4 reply Expert 2.5K+ P: 3,532 missinglinq Or, for those who find iif() confusing, and it can be, especially if nested 12 times, as some are wont to do: = [Number1] / Nz([Number2], 1) Linq ;0)> Jan 5 '08 #5 reply Expert Mod 15k+ P: 29,922 NeoPa Good point Linq (in fact that's how I would tend do it myself). I wasn't sure without checking if Nz() was available as a formula within a control though. Jan 5 '08 #6 reply Expert 2.5K+ P: 3,532 missinglinq Actually, Ade, if you think about it, if one Access function would work in a Control Source, the other would, but in point of fact both of our codes were lacking! Mine took care of the problem if Number2 was Null, and yours took care of the problem if Number2 = 0, but neither took care of both possibilities! So I modified yours! =IIf([Number2]= 0 or IsNull([Number2]),[Number1],[Number1]/[Number2]) Linq ;0)> Jan 5 '08 #7 reply Expert Mod 15k+ P: 29,922 NeoPa Actually, Ade, if you think about it, if one Access function would work in a Control Source, the other would, Actually, Nz() is "special" in this respect. I can't remember the finer details of exactly where I've found this (may even be in Excel rather than Access) but there certainly is somewhere where Nz() is no
Unanswered Topics Wrox Programmer Forums > Microsoft Office > Access and Access VBA > BOOK: Beginning Access 2003 VBA IIf Statement "division by zero" error User Name Remember Me? Password Reminder Password Register Register | FAQ | Members List | Calendar | Today's Posts | Search BOOK: Beginning Access 2003 VBA This is the forum to discuss the Wrox book Beginning Access 2003 VBA by Denise M. Gosnell; ISBN: 9780764556593 Read more about Beginning Access 2003 VBA or buy the book from your favorite retailer Download the code for Beginning Access 2003 VBA Search Forums Show Threads Show Posts Advanced Search Find All Thanked Posts Go to Page... Welcome to the p2p.wrox.com Forums. You are currently viewing the BOOK: Beginning Access 2003 VBA section of the Wrox Programmer to Programmer discussions. This is a community of tens of thousands of software programmers and website developers including Wrox book authors and readers. As a guest, you can read any forum posting. By joining today you can post your own programming questions, respond to other developers’ questions, and eliminate the ads that are displayed to guests. Registration is fast, simple and absolutely free . Thread Tools Display Modes #1 (permalink) September 27th, 2005, 10:54 AM Corey Friend of Wrox Join Date: Sep 2005 Location: , , USA. Posts: 106 Thanks: 0 Thanked 0 Times in 0 Posts IIf Statement "division by zero" error I am getting a division by zero error when trying to run a query in Microsoft access 2003. Is there an easy work around this error? Maybe an iif statement? Thanks Corey #2 (permalink) September 28th, 2005, 06:03 AM SteveH Registered User Join Date: Sep 2005 Location: , , . Posts: 3 Thanks: 0 Thanked 0 Times in 0 Posts Corey, The IIF (Built-In) function in Access won't give you the results you are looking for. If you try to use the function, it will generate an #Error as well. To resolve this issue I created a function. Here's the code: Function DivideByZero(Numerator As Double, Denominator As Double) As Double Dim dblResults As Double If Numerator = 0 Or Denominator = 0 Then dblResults = 0 Else dblResults = Numerator / Denominator End If DivideByZero = dblResults End Function The state