Microsoft Access Error Message Division By Zero
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Social Groups Pictures & Albums Members List Calendar Search Forums Show Threads Show Posts Tag Search Advanced Search Find All Thanked Posts Go to Page... Thread Tools Rate Thread Display Modes 07-20-2009, 12:04 PM #1 rkrause Newly Registered User Join Date: Sep 2007 access 2010 division by zero Posts: 343 Thanks: 0 Thanked 0 Times in 0 Posts Divide by Zero ERROR - HELP!!!
Iserror Access
I have a report Where my detail row is already summed up from my query. So example on of my fields is called SumOfGeneral_Repair. Ok so access if error then 0 in my report footer i have all my detail rows summed up again. I also have a textbox that is counting the rows that do not have a zero. So what i have in my report footer for formula is: =Sum([SumOfGeneral_Repair])/[text39] How access #num error would i incorparate that formula so i can forget the divide by zero error? rkrause View Public Profile Find More Posts by rkrause 07-20-2009, 12:09 PM #2 pbaldy Wino Moderator Join Date: Aug 2003 Location: Nevada, USA Posts: 28,915 Thanks: 6 Thanked 3,234 Times in 3,180 Posts Re: Divide by Zero ERROR - HELP!!! You can test in an IIf() and only do the division if it's greater than zero. __________________ Paul Microsoft Access MVP To view links
Access Iferror Function
or images in signatures your post count must be 10 or greater. You currently have 0 posts. pbaldy View Public Profile Find More Posts by pbaldy 07-20-2009, 12:25 PM #3 rkrause Newly Registered User Join Date: Sep 2007 Posts: 343 Thanks: 0 Thanked 0 Times in 0 Posts Re: Divide by Zero ERROR - HELP!!! OK So how would i do that in my formula that i posted? rkrause View Public Profile Find More Posts by rkrause 07-20-2009, 12:58 PM #4 MSAccessRookie AWF VIP Join Date: May 2008 Location: Central NJ, USA Posts: 3,428 Thanks: 13 Thanked 127 Times in 122 Posts Re: Divide by Zero ERROR - HELP!!! Quote: Originally Posted by rkrause OK So how would i do that in my formula that i posted? The Syntax of IIf() is IIf( Do not remove or your scheduled tasks will cease to function 0, BEGIN TEMPLATE: ad_footer_end 9, BEGIN TEMPLATE: ad_footer_end 8) __________________ No one is expected to know everything and we can all learn from each other if we try. This forum is about taking the next step (or perhaps the next two steps) toward becoming a better Access programmer, and the AWF Forum Members will help you on your journey.To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts. MSAccessRookie View Public Profile Find More Posts by MSAccessRookie 07-
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Unanswered Topics Wrox Programmer Forums > Microsoft Office > Access and Access VBA > BOOK: Beginning Access 2003 VBA IIf Statement "division by zero" error User Name Remember Me? Password Reminder Password Register Register | FAQ | Members List | Calendar | Today's Posts | Search BOOK: Beginning Access 2003 VBA This is the forum to discuss the Wrox book Beginning Access 2003 VBA by Denise M. Gosnell; ISBN: 9780764556593 Read more about Beginning Access 2003 VBA or buy the book from your favorite retailer Download the code for Beginning Access 2003 VBA Search Forums Show Threads Show Posts Advanced Search Find All Thanked Posts Go to Page... Welcome to the p2p.wrox.com Forums. You are currently viewing the BOOK: Beginning Access 2003 VBA section of the Wrox Programmer to Programmer discussions. This is a community of tens of thousands of software programmers and website developers including Wrox book authors and readers. As a guest, you can read any forum posting. By joining today you can post your own programming questions, respond to other developers’ questions, and eliminate the ads that are displayed to guests. Registration is fast, simple and absolutely free . Thread Tools Display Modes #1 (permalink) September 27th, 2005, 10:54 AM Corey Friend of Wrox Join Date: Sep 2005 Location: , , USA. Posts: 106 Thanks: 0 Thanked 0 Times in 0 Posts IIf Statement "division by zero" error I am getting a division by zero error when trying to run a query in Microsoft access 2003. Is there an easy work around this error? Maybe an iif statement? Thanks Corey #2 (permalink) September 28th, 2005, 06:03 AM SteveH Registered User Join Date: Sep 2005 Location: , , . Posts: 3 Thanks: 0 Thanked 0 Times in 0 Posts Corey, The IIF (Built-In) function in Access won't give you the results you are looking for. If you try to use the function, it will generat