Error 1064 Create View
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0 down vote favorite I hate to have to ask people on the internet to syntax check a fairly simple MySQL view but I can't work out what's wrong with the syntax. I've tried everything I can think of and I just keep getting the 1064 error with no specific error message. The tblProjectClient table has Foreign keys to tblClient and tblProject. The purpose of this view is error 1064 sqlstate 42000 to get a complete list of Clients, with a column for how many projects they currently have associated with them. If i don't use the UNION part, I get an empty list when there are no ProjectClient records. Does anyone have any ideas? Cheers. CREATE VIEW viewClientList AS ( select tblClient.strName AS 'Name', (select count(*) from tblProjectClient where (tblProjectClient.intClientID = tblClient.intClientID)) AS 'Projects', tblClient.intClientID AS 'ID' from (tblClient join tblProjectClient)) union select tblClient.strName as 'Name', '0' as 'Projects', tblClient.intClientID as 'ID' from tblClient where (not(tblClient.intClientID in(select intClientID as 'ID' from tblClient JOIN tblProjectClient))); mysql share|improve this question edited Apr 24 '13 at 1:37 Jocelyn 7,40742242 asked Oct 27 '12 at 14:06 user1709291 2113 add a comment| 2 Answers 2 active oldest votes up vote 0 down vote Escape column names with ` not '. share|improve this answer answered Oct 27 '12 at 14:09 Peter Kiss 7,94911336 add a comment| up vote 0 down vote Thanks for the help, but I found a simpler solution that works. For anyone else who wants to do something similar here's the query: CREATE VIEW viewClientList AS ( SELECT tblClient.strName AS 'Name', COUNT(tblProjectClient.intProjectID) AS 'Projects', tblClient.intClientID AS 'ID' FROM tblClient LEFT JOIN tblProjectClient ON tblClient.intClientID
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Error 1064 Sqlstate 42000 (er_parse_error)
ERROR 1064 (42000) Posted by: r.brandenburg () Date: December 06, 2005 12:11PM error 1064 you have an error in your sql syntax I am having trouble creating a simple view. The following is the transcript from my entries. I am error 1064 mysql workbench unable to do anything with views from the documentation (CREATE, SHOW, etc). The CREATE table and INSERT works fine, but the view is not working. Any suggestions? TIA. mysql> http://stackoverflow.com/questions/13100883/mysql-error-1064-create-view-syntax use gracarcom; Database changed mysql> CREATE TABLE t (qty INT, price INT); Query OK, 0 rows affected (0.05 sec) mysql> INSERT INTO t VALUES(3,50); Query OK, 1 row affected (0.00 sec) mysql> CREATE VIEW v AS SELECT qty,price,qty*price as val from t; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your http://forums.mysql.com/read.php?100,58245,58245 MySQL server version for the right syntax to use near 'VIEW v AS SELECT qty,price,qty*price as val from t' at line 1 mysql> CREATE VIEW v AS SELECT qty,price,qty*price AS value FROM t; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VIEW v AS SELECT qty,price,qty*price AS value FROM t' at line 1 mysql> CREATE VIEW v AS SELECT qty, price, qty*price AS value FROM t; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VIEW v AS SELECT qty, price, qty*price AS value FROM t' at line 1 mysql> SHOW CREATE VIEW V; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'VIEW V' at line 1 Edited 2 time(s). Last edit at 12/06/2005 01:13PM by r.brandenburg. Navigate:Previous Message&
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$name = $_POST['name']; $message = $_POST['message']; $user = 'user'; $password = 'Login'; $host = 'localhost:3036'; $browser = $_SERVER['HTTP_USER_AGENT']; $ip = $_SERVER["REMOTE_ADDR"]; date_default_timezone_set('UTC+1'); $date = date("Y-m-d"); $time = date("H:i:s"); $connect = mysql_connect($host, $user, $password); if (! $connect) { $error = mysql_error(); print "Sorry, could n