Errno 8 Exec Format Error Subprocess
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack oserror: [errno 8] exec format error selenium Overflow the company Business Learn more about hiring developers or posting ads with us Stack errno 8 exec format error ansible Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community enoexec of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up OSError: [Errno 8] Exec format error up vote 5 down vote favorite 3 I am having hard call shell script from python time parsing the arguments to subprocess.Popen. I am trying to execute a script on my Unix server. The script syntax when running on shell prompt is as follows: /usr/local/bin/script hostname =
Python Subprocess No Such File Or Directory
work. And when I use shell=False, I get OSError: [Errno 8] Exec format error python subprocess share|improve this question edited Dec 28 '14 at 9:27 J.F. Sebastian 180k41337489 asked Dec 22 '14 at 16:34 user3477108 46114 Wild guess: try 'hostname = actual server name' instead of 'hostname = ', 'actual server name' –Kevin Dec 22 '14 at 16:43 Based on how you say you run it at the prompt, it looks like hostname is one argument and = is a separate argument, which is quite strange. Are you sure there are spaces around =? –Bryan Oakley Dec 22 '14 at 16:45 hi Bryan, yes there has to be space. Script accepts key=value type argument. –user3477108 Dec 22 '14 at 17:13 @user3477108 - that's puzzling, you say there has to be a space but then give a "key=value" example that doesn't have a space. Of course, since your command line example has a space, we know that key = value should be 3 arguments to Popen as insti shows. –tdelaney Dec 22 '14 at 17:47 Thanks. I wrote a little wrapper script around my original script to disregard space around "=" The wrapper script runs fine. –user3477108 Dec 22 '14 at 18:11 | sh
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About Us Learn more about Stack Overflow the company Business Learn more about bash cannot execute binary file hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss cannot execute binary file exec format error Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Python subprocess Exec http://stackoverflow.com/questions/27606653/oserror-errno-8-exec-format-error format error up vote 1 down vote favorite Sorry if this question is dumb. I am using python subprocess statement to call a .bat file in Ubuntu (Natty 11.04), however, I got error messages: Traceback (most recent call last): File "pfam_picloud.py", line 40, in
here for a quick overview of the site Help Center http://stackoverflow.com/questions/21558789/python-cgi-script-oserror-errno-8-exec-format-error Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x exec format Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Python CGI Script: OSError: [Errno 8] Exec format error up vote 2 down vote favorite When I send exec format error http://localhost:8888/cgi-bin/peoplecgi.py?action=Fetch&key=sue (sue is a valid key in the shelve) to the cgi script below I get the following (also I'm on OSX with Python 3.3). Any ideas what is going wrong? 127.0.0.1 - - [04/Feb/2014 10:38:41] "GET /cgi-bin/peoplecgi.py?action=Fetch&key=sue HTTP/1.1" 200 - Traceback (most recent call last): File "/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/http/server.py", line 1131, in run_cgi os.execve(scriptfile, args, env) OSError: [Errno 8] Exec format error: '/Users/rich/Google Drive/Code/Python/PP4E/Preview/cgi-bin/peoplecgi.py' 127.0.0.1 - - [04/Feb/2014 10:38:41] CGI script exit status 0x7f00 I am working out of O'Reilly's Programming Python 4th Edition. This is question is based off example 1-33. weberver.py: import os, sys from http.server import HTTPServer, CGIHTTPRequestHandler webdir = '/Users/rich/Google Drive/Code/Python/PP4E/Preview/' port = 8888 os.chdir(webdir) srvraddr = ("", port) srvrobj = HTTPServer(srvraddr, CGIHTTPRequestHandler) srvrobj.serve_forever() peoplecgi.py import cgi, shelve, sys, os shelvename = 'class-shelve' fieldnames = ('name', 'age', 'job', 'pay') form = cgi.FieldStorage() print('Content-type: text/html') sys.path.insert(0, os.getcwd()) replyhtml=""" <