#1075 Error Mysql
Contents |
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring mysql error 1005 developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question
Mysql Error 1075 Innodb
x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; mysql error 1064 it only takes a minute: Sign up Mysql Error: #1075 up vote 2 down vote favorite SQL query: ALTER TABLE `blog` CHANGE `id` `id` BIGINT NOT NULL AUTO_INCREMENT MySQL said: #1075 - Incorrect table definition; there can be only
Mysql Error Code 1075
one auto column and it must be defined as a key I am trying to create a blog, and I got the code done. Now, I need to make the id auto increase, but I get this error. Why am I getting this? mysql sql mysql-error-1075 share|improve this question edited Dec 19 '12 at 23:44 OMG Ponies 198k36356415 asked Dec 19 '12 at 23:33 user1888406 1214 add a comment| 2 Answers 2 active oldest votes up vote 6 down mysql error 1075 incorrect table definition vote MySQL is returning that error (most likely) because there is no unique index defined on the id column. (MySQL requires that there be a unique index. The other possibility, which you would have already figured out, is that there can be only one column defined as AUTO_INCREMENT within the table.) To get that column to be an AUTO_INCREMENT, you can add either a UNIQUE constraint or a PRIMARY KEY constraint on the id column. For example: ALTER TABLE `blog` ADD CONSTRAINT `blog_ux` UNIQUE (`id`) ; (Note that this statement will return an error if any duplicate values exist for the id column.) Alternatively, you can make the id column the PRIMARY KEY of the table (if the table doesn't already have a PRIMARY KEY constraint defined). ALTER TABLE `blog` ADD PRIMARY KEY (`id`) ; (Note that this statement will return an error if any duplicate value exist for the id column, OR if there are any NULL values stored in that column, of if there is already a PRIMARY KEY constraint defined on the table.) share|improve this answer edited Dec 19 '12 at 23:58 answered Dec 19 '12 at 23:42 spencer7593 60k74871 add a comment| up vote 4 down vote MySQL requires you to make auto increment column the primary key of a table. Add the primary key constraint at the end ALTER TABLE `blog` MODIFY COLUMN `id` BIGINT NOT NULL AUTO_INCREMENT primary key
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring
#1089 Error In Mysql
developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question
Phpmyadmin Define Primary Key
x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; 1089 mysql error it only takes a minute: Sign up ERROR 1075: Incorrect table definition; there can be only one auto column and it must be defined as a key up vote 0 down vote favorite I try to "alter Table" I http://stackoverflow.com/questions/13963002/mysql-error-1075 need one more AI field, not key... "List" ID INT(11):PK Not Null AutoIn.. Name VARCHAR UserID INT(11):FK Not Null edit BOOL and now i need one more field "sortpos" as AI. I try it with MySQL Workbench ALTER TABLE `**mydb**`.`List` ADD COLUMN `sortpos` INT(11) NOT NULL AUTO_INCREMENT AFTER `edit`; Can u help me? Thx mysql sql mysql-workbench alter-table share|improve this question asked Mar 12 '14 at 21:32 Akdes 917 as the error says, it must be part of http://stackoverflow.com/questions/22364316/error-1075-incorrect-table-definition-there-can-be-only-one-auto-column-and-it the pkey. see also stackoverflow.com/questions/5416548/… –koriander Mar 12 '14 at 22:48 but I need sortpos individually, like id too, so auto increment. Is there the possibility to clone id in sortpos, default as example? –Akdes Mar 12 '14 at 23:53 some explanation is missing, why do you need two fields which have exactly the same value? –koriander Mar 13 '14 at 7:31 i need one more fields to sort the output, i need an unique key to switch –Akdes Mar 13 '14 at 20:40 I don't follow, you already have a unique key, ID. What do you mean "to switch"? switch what? can you post the query? –koriander Mar 13 '14 at 21:32 | show 2 more comments 2 Answers 2 active oldest votes up vote 0 down vote You can't get better error message than this one. You already have ID defined as Auto Increment in your table. Now you are trying to add another field sortpos as auto increment which is not allowed. One table can only have one auto increment which must be defined as primary key. Remove AUTO_INCREMENT from the alter statement and create a trigger to increment the new column. share|improve this answer answered Mar 12 '14 at 23:26 Riz 843513 can u help me to create some trigger: by insert copy id to sortpos –Akdes Mar 12 '14 at 23:56
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the http://stackoverflow.com/questions/34759703/1075-mysql-error company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions https://bugs.mysql.com/bug.php?id=45987 Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up #1075 MySQL Error up vote 0 down vote favorite So i am just a beginner in all this php stuff. I mysql error know just the basics, and when i setting up the settings for my new table, I met the problem #1075. Before, i created one, almost similar to this one, and i don't see the differenc. Can you say me where is the problem and explain what is happening? CREATE TABLE `try`.`testing` ( `id` INT NOT NULL AUTO_INCREMENT , `date` DATE NOT NULL , `text_1` TEXT CHARACTER SET utf8 COLLATE utf8_general_ci NOT NULL , mysql error 1075 `text_2` TEXT CHARACTER SET utf8 COLLATE utf8_general_ci NOT NULL ) ENGINE = MyISAM; here is the code of my SQL Preview. I use phpMyAdmin, obviously. Please, help me. Thank, you) mysql sql mysql-error-1075 share|improve this question edited Jan 27 at 4:59 Isaac Bennetch 4,8421821 asked Jan 13 at 6:20 Godje 325 add a comment| 4 Answers 4 active oldest votes up vote 1 down vote accepted Try this CREATE TABLE `testing` ( `id` INT NOT NULL AUTO_INCREMENT, `date` DATE NOT NULL, `text_1` TEXT CHARACTER SET utf8 COLLATE utf8_general_ci NOT NULL, `text_2` TEXT CHARACTER SET utf8 COLLATE utf8_general_ci NOT NULL, PRIMARY KEY (`id`) ) ENGINE = MYISAM ; share|improve this answer answered Jan 13 at 6:27 PravinS 2,3633920 Thank, you! Works well, but can you explain what you did? What was the problem. –Godje Jan 13 at 6:31 for AUTO_INCREMENT column we mush have key, so I have set it as primary key –PravinS Jan 13 at 6:35 add a comment| up vote 1 down vote You have to declare your AUTO_INCREMENT field as a primary key or a key. So you have to add PRIMARY KEY (id) or KEY (id) to your CREATE TABLE statement: CREATE TABLE `try`.`testing` ( `id` INT NOT NULL AUTO_INCREMENT, `date` DATE NOT NULL , `text_1` TEXT CHARACTER SET utf8 COLLA
Updates: Status: Closed Impact on me: None Category:MySQL Server: Documentation Severity:S3 (Non-critical) Version:5.1.36-community OS:Microsoft Windows (XP Pro) Assigned to: Paul Dubois Tags: 1075, 42000, auto_increment, error, reference Triage: Needs Triage: D4 (Minor) View Add Comment Files Developer Edit Submission View Progress Log Contributions [7 Jul 2009 4:15] Ender Li Description: In http://dev.mysql.com/doc/refman/5.1/en/example-auto-increment.html, there is a sample code : CREATE TABLE animals ( grp ENUM('fish','mammal','bird') NOT NULL, id MEDIUMINT NOT NULL AUTO_INCREMENT, name CHAR(30) NOT NULL, PRIMARY KEY (grp,id) ); INSERT INTO animals (grp,name) VALUES ('mammal','dog'),('mammal','cat'), ('bird','penguin'),('fish','lax'),('mammal','whale'), ('bird','ostrich'); SELECT * FROM animals ORDER BY grp,id; When I try to "CREATE TABLE animals", I get "ERROR 1075 (42000): Incorrect table definition; there can be only one auto column and it must be def ined as a key". How to repeat: mysql> use test Database changed mysql> show tables; +----------------+ | Tables_in_test | +----------------+ | 321321 | | person | | shirt | | shop | | t1 | +----------------+ 5 rows in set (0.13 sec) mysql> CREATE TABLE animals ( -> grp ENUM('fish','mammal','bird') NOT NULL, -> id MEDIUMINT NOT NULL AUTO_INCREMENT, -> name CHAR(30) NOT NULL, -> PRIMARY KEY (grp,id) -> ); ERROR 1075 (42000): Incorrect table definition; there can be only one auto column and it must be def ined as a key mysql> Suggested fix: Maybe Server error, maybe docs error... Please just fix or modify one of them. [7 Jul 2009 5:48] Valerii Kravchuk Thank you for the problem report. Actually, this is not a server bug, just a difference between MyISAM (assumed as default by that manual page) and InnoDB storage engine documented elsewhere (http://dev.mysql.com/doc/refman/5.1/en/innodb-auto-increment-handling.html). You (and me) have InnoDB as a default storage engine instead. Look: mysql> CREATE TABLE animals ( -> grp ENUM('fish','mammal','bird') NOT NULL, -> id MEDIUMINT NOT NULL AUTO_INCREMENT, -> name CHAR(30) NOT NULL, -> PRIMARY KEY (grp,id) -> ); ERROR 1075 (42000): Incorrect table definition; there can be only one auto colum n and it must be defined as a key mysql> CREATE TABLE animals ( -> grp ENUM('fish','mammal','bird') NOT NULL, -> id MEDIUMINT NOT NULL AUTO_INCREMENT, -> name CHAR(30) NOT NULL, -> PRIMARY KEY