Python Timeout Error
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a try statement with an except clause that mentions a particular class, that clause also handles any exception classes
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derived from that class (but not exception classes from which it is python custom exception derived). Two exception classes that are not related via subclassing are never equivalent, even if they have the
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same name. The built-in exceptions listed below can be generated by the interpreter or built-in functions. Except where mentioned, they have an "associated value" indicating the detailed cause of python filenotfounderror the error. This may be a string or a tuple of several items of information (e.g., an error code and a string explaining the code). The associated value is usually passed as arguments to the exception class's constructor. User code can raise built-in exceptions. This can be used to test an exception handler or to report an error python exception message condition "just like" the situation in which the interpreter raises the same exception; but beware that there is nothing to prevent user code from raising an inappropriate error. The built-in exception classes can be subclassed to define new exceptions; programmers are encouraged to derive new exceptions from the Exception class or one of its subclasses, and not from BaseException. More information on defining exceptions is available in the Python Tutorial under User-defined Exceptions. When raising (or re-raising) an exception in an except or finally clause __context__ is automatically set to the last exception caught; if the new exception is not handled the traceback that is eventually displayed will include the originating exception(s) and the final exception. When raising a new exception (rather than using a bare raise to re-raise the exception currently being handled), the implicit exception context can be supplemented with an explicit cause by using from with raise: raise new_exc from original_exc The expression following from must be an exception or No
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Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: https://docs.python.org/3/library/exceptions.html Sign up Handling urllib2's timeout? - Python up vote 46 down vote favorite 21 I'm using the timeout parameter within the urllib2's urlopen. urllib2.urlopen('http://www.example.org', timeout=1) How do I tell Python that if the timeout expires a custom error should be raised? Any ideas? python timeout urllib2 urllib share|improve this question asked Apr 26 '10 at 10:03 RadiantHex 7,7532297206 1 Note: timeout http://stackoverflow.com/questions/2712524/handling-urllib2s-timeout-python parameter doesn't limit neither the total connection time nor total read (response) time. –J.F. Sebastian Dec 5 '15 at 17:37 add a comment| 2 Answers 2 active oldest votes up vote 77 down vote accepted There are very few cases where you want to use except:. Doing this captures any exception, which can be hard to debug, and it captures exceptions including SystemExit and KeyboardInterupt, which can make your program annoying to use.. At the very simplest, you would catch urllib2.URLError: try: urllib2.urlopen("http://example.com", timeout = 1) except urllib2.URLError, e: raise MyException("There was an error: %r" % e) The following should capture the specific error raised when the connection times out: import urllib2 import socket class MyException(Exception): pass try: urllib2.urlopen("http://example.com", timeout = 1) except urllib2.URLError, e: # For Python 2.6 if isinstance(e.reason, socket.timeout): raise MyException("There was an error: %r" % e) else: # reraise the original error raise except socket.timeout, e: # For Python 2.7 raise MyException("There was an error: %r" % e) share|improve this answer edited May 14 '13 at 13:33 answered Apr 26 '10 at 10:30 dbr 93.3k46225295 4 This will n
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more http://stackoverflow.com/questions/2281850/timeout-function-if-it-takes-too-long-to-finish about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack https://github.com/python-telegram-bot/python-telegram-bot/issues/364 Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Timeout function if it takes too long to finish [duplicate] up python exception vote 79 down vote favorite 51 This question already has an answer here: Timeout on a function call 11 answers I have a shell script that loops through a text file containing URL:s that I want to visit and take screenshots of. All this is done and simple. The script initializes a class that when run creates a screenshot of each site in the list. Some sites take a python timeout error very, very long time to load, and some might not be loaded at all. So I want to wrap the screengrabber-function in a timeout script, making the function return False if it couldn't finish within 10 seconds. I'm content with the simplest solution possible, maybe setting a asynchronous timer that will return False after 10 seconds no matter what actually happens inside the function? python share|improve this question edited Aug 5 '15 at 3:13 Aaron Hall 57.1k19144146 asked Feb 17 '10 at 15:21 Christoffer 4,761103468 marked as duplicate by J.F. Sebastianpython Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed. Feb 14 '15 at 11:08 This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question. I have a reply here for this question. –piro Feb 17 '10 at 16:02 add a comment| 2 Answers 2 active oldest votes up vote 135 down vote accepted The process for timing out an operations is described in the documentation for signal. The basic idea is to use signal handlers to set an alarm for some time interval and raise an exception once
Sign in Pricing Blog Support Search GitHub This repository Watch 126 Star 1,469 Fork 337 python-telegram-bot/python-telegram-bot Code Issues 18 Pull requests 8 Projects 3 Wiki Pulse Graphs New issue Read Timeout Error #364 Open sochix opened this Issue Aug 3, 2016 · 3 comments Projects None yet Labels question Milestone No milestone Assignees No one assigned 3 participants sochix commented Aug 3, 2016 • edited Steps to reproduce Add several jobs to a queue, which will wait >15 mins and then send message Wait till message will send Get an ReadTimeoutError Expected behaviour Should send a message Actual behaviour Get ReadTimeoutException: urllib3.connectionpool - WARNING - Retrying (Retry(total=2, connect=None, read=None, redirect=None)) after connection broken by 'ReadTimeoutError("HTTPSConnectionPool(host='api.telegram.org', port=443): Read timed out. (read timeout=