Python Unsupported Error
Contents |
This module never needs to be imported explicitly: the exceptions are provided in the built-in namespace as well as the exceptions module. For class exceptions, in a try statement with
Python Custom Exception
an except clause that mentions a particular class, that clause also handles any exception classes derived python exception message from that class (but not exception classes from which it is derived). Two exception classes that are not related via subclassing are never equivalent, even if they python valueerror example have the same name. The built-in exceptions listed below can be generated by the interpreter or built-in functions. Except where mentioned, they have an "associated value" indicating the detailed cause of the error. This may be a string or a tuple containing several items of information (e.g., an error code and a string explaining the
Python Exception Class Methods
code). The associated value is the second argument to the raise statement. If the exception class is derived from the standard root class BaseException, the associated value is present as the exception instance's args attribute. User code can raise built-in exceptions. This can be used to test an exception handler or to report an error condition "just like" the situation in which the interpreter raises the same exception; but beware that there is nothing to prevent user code from raising an inappropriate error. The built-in exception classes can be subclassed to define new exceptions; programmers are encouraged to derive new exceptions from the Exception class or one of its subclasses, and not from BaseException. More information on defining exceptions is available in the Python Tutorial under User-defined Exceptions. The following exceptions are only used as base classes for other exceptions. exception BaseException¶ The base class for all built-in exceptions. It is not meant to be directly inherited by user-d
navigation, search Contents 1 Introduction 2 Bugs - Human Errors 3 Exceptions - Limitations of the Code 4 Endless Errors Introduction[edit] If you haven't seen them before, you're not trying hard enough. What are they? python 3 exceptions Errors. Exceptions. Problems. Know what I'm talking about? I got it with this program: python errno Code Example 1 - buggy program def menu(list, question): for entry in list: print 1 + list.index(entry), print ") " + entry
Assertionerror Python
return raw_input(question) - 1 # running the function # remember what the backslash does answer = menu(['A','B','C','D','E','F','H','I'],\ 'Which letter is your favourite? ') print 'You picked answer ' + (answer + 1) This is just https://docs.python.org/2/library/exceptions.html an example of the menu program we made earlier. Appears perfectly fine to me. At least until when I first tried it. Run the program, and what happens? Bugs - Human Errors[edit] The most common problems with your code are of your own doing. Sad, but true. What do we see when we try to run our crippled program? Code Example 2 - error message Traceback (most recent call last): https://en.wikibooks.org/wiki/A_Beginner's_Python_Tutorial/Exception_Handling File "/home/steven/errortest.py", line 10, in -toplevel- answer = menu(< I'll snip it here >) File "/home/steven/errortest.py", line 6, in menu return raw_input(question) - 1 TypeError: unsupported operand type(s) for -: 'str' and 'int' Say what? What Python is trying to tell you (but struggling to find a good word for it) is that you can't join a string of letters and a number into one string of text. Let's go through the error message and have a look at how it tells us that: File "/home/steven/errortest.py", line 10, in -toplevel- tells us a couple of things. File "/home/steven/errortest.py" tells us which file the error occured in. This is useful if you use lots of modules that refer to each other. line 10, in -toplevel- tells us that it is in line # 10 of the file, and in the top level (that is, no indentation). answer = menu(['A','B','C','D','E','F','H','I'],'Which letter is your favourite? ') duplicates the code where the error is. Since this line calls a function, the next two lines describe where in the function the error occured. TypeError: unsupported operand type(s) for -: 'str' and 'int' tells you the error. In this case, it is a 'TypeError', where you tried to subtract incompatible variables. There are multiple file an
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about http://stackoverflow.com/questions/19204513/python-error-unsupported-operand-types-for-int-and-str hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. http://stackoverflow.com/questions/24110282/python-error-unsupported-operand-types-for-int-and-nonetype Join them; it only takes a minute: Sign up Python error unsupported operand type(s) for +: 'int' and 'str' up vote 0 down vote favorite here is my code: def naame(value, suit): if suit == ("D"): suit == ("Dimnd") python exception return (value + " of " +suit) So I think where the problem lies is when I add '+' too it... but still I have no idea on how to go about doing this... I still fairly new at python. Please help me python if-statement return-value share|improve this question asked Oct 6 '13 at 1:36 user2829744 113 1 so is "value" supposed to be an int? if so, you want to pass in str(value) –Joe Oct 6 python unsupported error '13 at 1:37 1 The line suit == "Dimnd" should be suit = "Dimnd". == test equality, it does not do assignment. –SethMMorton Oct 6 '13 at 1:57 Also, in Python, putting extra parentheses where they aren't needed is usually considered bad style. A reader will waste time trying to figure out what you were trying to do (create a tuple? override operator precedence? call a function?), and maybe even come to the wrong conclusion (e.g., write an irrelevant and unhelpful answer like "If you want that to be a tuple, you have to write ("Dimnd", )"). Just write if suit == "D":, suit = "Dimnd", and return value + " of " + suit. –abarnert Oct 6 '13 at 2:16 add a comment| 1 Answer 1 active oldest votes up vote 4 down vote That error (properly called a TypeError) can only be generated if value is an integer. Furthermore, in Python, you cannot put integers and strings together with +. To fix your problem, make value a string: return (str(value) + " of " + suit) By putting value in str(), it is converted to its string representation. See an example below: >>> a = 1 >>> type(a)
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Python Error: unsupported operand type(s) for +: 'int' and 'NoneType' up vote 0 down vote favorite I don't understand this error OR what it means. I will paste my code underneath, but I don't think it is really relevant; I just want to understand this error. It's just a bit of code to add up the letters in all numbers 1 - 1000 (inclusive) def number_translator(x): if x == 1: return 3 elif x == 2: return 3 elif x == 3: return 5 elif x == 4: return 4 elif x == 5: return 4 elif x == 6: return 3 elif x == 7: return 5 elif x == 8: return 5 elif x == 9: return 4 elif x == 10: return 3 elif x == 11: return 6 elif x == 12: return 6 elif x == 14: return 8 elif x == 15: return 7 elif x == 16: return 7 elif x == 17: return 9 elif x == 18: return 8 elif x == 19: return 8 elif x == 20: return 6 elif x == 30: return 6 elif x == 40: return 5 elif x == 50: return 5 elif x == 60: return 5 elif x == 70: return 7 elif x == 80: return 6 elif x == 90: return 6 count = 0 for element in range(1, 1001): if element < 21: count += number_translator(element) # for numbers 1 - 20 elif 20 < element < 100: count += number_translator(int(str(element)[0]) * 10) + number_translator(int(str(element)[1])) # for numbers 21 through 100 elif element % 100 == 0 and element != 1000: count += number_translator(int(str(element)[0])) + 7 # for numbers divisible by 100, but not 1000 elif element == 1000: count += 11 # just for 1000 elif element % 100 < 20: count += number_translator(int(str(element)[0])) + 10 + number_translator(int(str(element)[1:3])) # now I add in numbers like 101 - 120, 201 - 220, etc. else: count += number_translator(int(str(element)[0])) + 10 + number_translator