Python Socket Error Address Already In Use
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Return Getattr(self._sock,name)(*args) Socket.error: [errno 98] Address Already In Use
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Socket 'address Already In Use'
like you, helping each other. Join them; it only takes a minute: Sign up Python [Errno 98] Address already in use up vote 53 down vote favorite 26 In my Python socket program, I sometimes need to interrupt it with ctrl-c. When I do this, it does close the connection using socket.close() however when I try python close socket to reopen it I have to wait what seems like a minute before I can connect again. How does one correctly close a socket? Or is this intended? python sockets connection errno share|improve this question edited Feb 10 '14 at 0:49 Benjamin Gruenbaum 123k41271351 asked Dec 16 '10 at 22:24 skylerl 1,09992443 add a comment| 3 Answers 3 active oldest votes up vote 76 down vote accepted Yes, it is intended. Here you can read detailed explanation. It is possible to override this behavior by setting SO_REUSEADDR option on a socket. For example: sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) share|improve this answer answered Dec 16 '10 at 22:33 Bartosz 3,5201815 add a comment| up vote 7 down vote If you use a TCPServer, UDPServer or their subclasses in the SocketServer module, you can set this class variable (before instanciating a server): SocketServer.TCPServer.allow_reuse_address = True (via SocketServer.ThreadingTCPServer - Cannot bind to address after program restart ) This causes the init (constructor) to: if self.allow_reuse_address: self.socket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) share|improve this answer edi
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Python Socketserver Address Already In Use
you might have Meta Discuss the workings and policies of this python unbind socket site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers socket address already in use c or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a http://stackoverflow.com/questions/4465959/python-errno-98-address-already-in-use community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Socket error: Address already in use up vote 2 down vote favorite 4 I have a CherryPy script that I frequently run to start a server. Today I was having to start and stop http://stackoverflow.com/questions/29217502/socket-error-address-already-in-use it a few times to fix some bugs in a config file, and I guess the socket didn't close all the way because when I tried to start it up again I got this issue: [23/Mar/2015:14:08:00] ENGINE Listening for SIGHUP. [23/Mar/2015:14:08:00] ENGINE Listening for SIGTERM. [23/Mar/2015:14:08:00] ENGINE Listening for SIGUSR1. [23/Mar/2015:14:08:00] ENGINE Bus STARTING CherryPy Checker: The Application mounted at '' has an empty config. [23/Mar/2015:14:08:00] ENGINE Started monitor thread 'Autoreloader'. [23/Mar/2015:14:08:00] ENGINE Started monitor thread '_TimeoutMonitor'. [23/Mar/2015:14:08:00] ENGINE Error in HTTP server: shutting down Traceback (most recent call last): File "/home/andrew/virtualenvs/mikernels/lib/python2.7/site-packages/cherrypy/process/servers.py", line 188, in _start_http_thread self.httpserver.start() File "/home/andrew/virtualenvs/mikernels/lib/python2.7/site-packages/cherrypy/wsgiserver/wsgiserver2.py", line 1848, in start raise socket.error(msg) error: No socket could be created I edited CherryPy's wsgiserver2.py to see the details of the socket.error and error.strerror was 98 (98, 'Address already in use') Address already in use Meanwhile my socket is constructed as: af = 2 socktype = 1 proto = 6 canonname = '' sa = ('0.0.0.0', 2112) self.bind(a
here for a quick overview of the site Help Center Detailed answers to any questions http://stackoverflow.com/questions/7703797/need-to-close-python-socket-find-the-current-running-server-on-my-dev-environm you might have Meta Discuss the workings and policies of http://stackoverflow.com/questions/14765351/python-socket-error-address-in-use this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is address already a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Need to close python socket / Find the current running server on my dev environment up vote 20 down vote favorite 19 I'm trying to learn python (using the Flask micro-framework) and address already in I am confused because somewhere in my code i'm keeping the server open I believe. I spin up my server with 'python app.py' and then close it however.... it still lives! I'm not sure how this is possible but i must have done something wrong with a connection. There are two questions here really. First: How can I find the active connection/socket and close it Second: Is there a way I can diagnose what is having an open connection, my hunch is that sqlLite is not closing as it is the last thing I implemented. This is a one file application (minus a config file and static content) so I can post the code if required. Error generated (Folder locations changed): /Development/flask_projects/test_email/env/bin/python /Development/flask_projects/test_email/app.py * Running on http://127.0.0.1:5000/ Traceback (most recent call last): File "Development/flask_projects/test_email/app.py", line 58, in
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 6.2 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Python - Socket Error, Address In Use up vote 1 down vote favorite I'm currently attempting to setup a SiriServer (that's beside the point) on Xubuntu 12.10 x64, when I run the server python returns error socket.error: [Errno 98] Address already in use. The server by default is attempting to run on port 443, which unfortunetly is required in order for this application to work. To double check if anything is running on port 443, I execute the following: lsof -i :443 There's no results, unless I have something like Chrome or Firefox open, which I end up closing. Here's the full return from attempting to run the server application. dustin@dustin-xubuntu:~/Applications/SiriServer$ sudo python siriServer.py CRITICAL load_plugins Failed loading plugin due to missing module: 'Wordnik library not found. Please install wordnik library! e.g. sudo easy_install wordnik' INFO