Division By Zero Error Java
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Java Zero Division Exception
about Stack Overflow the company Business Learn more about hiring developers or posting ads can you divide by zero in java with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow divide by 0 exception in java is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up How does Java handle division by zero? [duplicate] up vote 16 down
Java Division By Zero Exception Handling
vote favorite 1 This question already has an answer here: In java, “5/0” statement doesn't fire SIGFPE signal on my Linux machine, why? 6 answers Does it simply check if divisor is different from zero every time there is division done (even in JIT-ed code)? I mean how VM manages to throw an exception without being previously killed by the OS? java divide-by-zero share|improve this question asked Jan 21
Division By Zero Error In Access
'14 at 21:27 mrpyo 1,01311330 marked as duplicate by Raedwald, Eric Leschinski, Kevin Panko, Lego Stormtroopr, iandotkelly Jan 22 '14 at 2:43 This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question. What do you mean by "previously killed"? –Oliver Charlesworth Jan 21 '14 at 21:29 One word: Zombies!! –Hot Licks Jan 21 '14 at 21:29 1 The OS won't kill the VM for a divide-by-zero. The VM will terminate if such an exception is not catched. –Stefano Sanfilippo Jan 21 '14 at 21:30 1 Division by zero is caught at hardware level and results in interrupt being called with usually leads OS to stopping the process (I'm asking how it is caught internally in VM implementation not language itself)... –mrpyo Jan 21 '14 at 21:32 2 @StefanoSanfilippo yeah the OS doesn't kill anything but the VM commits suicide ;-) –ITroubs Jan 21 '14 at 21:33 | show 7 more comments 4 Answers 4 active oldest votes up vote 30 down vote accepted In an Unix environment, in which division-by-zero is signalled via SIGFPE, the JVM will have installed a signal handler which
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Division By Zero Error In Access Report
ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack division by zero error in sql Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up try-catch for division by zero up vote 13 down vote favorite http://stackoverflow.com/questions/21269461/how-does-java-handle-division-by-zero 1 I am a java newbie, my question is about try-catch blocks on a simple division by zero example. You see the first line of try? If I cast any of those two variables to the double the program does not recognize the catch block. In my opinion, whether I cast or not only the catch block must be executed. What is wrong on this code? Thanks. public static http://stackoverflow.com/questions/2259190/try-catch-for-division-by-zero void main(String[] args) { int pay=8,payda=0; try { double result=pay/(double)payda; // if I cast any of the two variables, program does not recognize the catch block, why is it so? System.out.println(result); System.out.println("inside-try"); } catch (Exception e) { System.out.println("division by zero exception"); System.out.println("inside-catch"); } } java try-catch divide-by-zero share|improve this question edited Oct 1 '12 at 9:46 Aziz Shaikh 11.5k73753 asked Feb 13 '10 at 21:50 Firat 66113 add a comment| 7 Answers 7 active oldest votes up vote 22 down vote Divide by zero is valid for floating point numbers. 1/0 yields Infinity. (-1)/0 yields -Infinity. 0/0 yields NaN. These "numbers" are properly defined in IEEE 754. Integer division by zero, on the other hand, throws because one cannot represent infinity as an int. share|improve this answer answered Feb 13 '10 at 21:54 kennytm 317k60751812 If floating point division cannot throw an exception, then the try / catch should be removed and error codes used instead. –Hamish Grubijan Feb 14 '10 at 2:30 1 I don't think int throws because it can't represent infinity. 1/0 is simply meaningless, and that's why it throws. Floating point, on the other hand, did some hand-waving and said "it should be infinity". –GManNickG Feb
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Method java.lang Class ArithmeticException java.lang.Object java.lang.Throwable java.lang.Exception java.lang.RuntimeException java.lang.ArithmeticException All Implemented Interfaces: Serializable public class ArithmeticException extends RuntimeException Thrown when an exceptional arithmetic condition has occurred. For example, an integer "divide by zero" throws an instance of this class. ArithmeticException objects may be constructed by the virtual machine as if suppression were disabled and/or the stack trace was not writable. Since: JDK1.0 See Also:Serialized Form Constructor Summary Constructors Constructor and Description ArithmeticException() Constructs an ArithmeticException with no detail message. ArithmeticException(Strings) Constructs an ArithmeticException with the specified detail message. Method Summary Methods inherited from classjava.lang.Throwable addSuppressed, fillInStackTrace, getCause, getLocalizedMessage, getMessage, getStackTrace, getSuppressed, initCause, printStackTrace, printStackTrace, printStackTrace,