Duplicate Entry Error Php
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Mysql Duplicate Entry Error Code
a minute: Sign up Handle error for duplicate entries - PHP MySQL up vote 20 down vote favorite 2 I have a PHP form which enters data into my MySQL database. My primary key is one of the user-entered values.
Codeigniter Duplicate Entry Error
When the user enters a value that already exists in the table, the MySQL error "Duplicate entry 'entered value' for key 1" is returned. Instead of that error, I would like to alert the user that they need to enter a different value. Just an echoed message or something. I guess my question comes down to: how to turn a specific MySQL error into a PHP message Thanks edit: nickf's answer below is nice, but is there any way to discern between duplicate entry error in xml bursting specific errors? php mysql error-handling share|improve this question edited Jun 30 '10 at 6:39 asked Jun 30 '10 at 6:09 RobHardgood 103116 add a comment| 3 Answers 3 active oldest votes up vote 31 down vote accepted To check for this specific error, you need to find the error code. It is 1062 for duplicate key. Then use the result from errno() to compare with: mysql_query('INSERT INTO ...'); if (mysql_errno() == 1062) { print 'no way!'; } A note on programming style You should always seek to avoid the use of magic numbers (I know, I was the one to introduce it in this answer). Instead, you could assign the known error code (1062) to a constant (e.g. MYSQL_CODE_DUPLICATE_KEY). This will make your code easier to maintain as the condition in the if statement is still readable in a few months when the meaning of 1062 has faded from memory :) share|improve this answer edited Jun 30 '10 at 7:14 answered Jun 30 '10 at 6:47 jensgram 22.7k25675 1 Yeah, that's a good point. This didn't work though... are you sure 1022 is the right error code? I'll start looking too. Thanks –RobHardgood Jun 30 '10 at 7:10 Ah, it's 1062, cf. dev.mysql.com/doc/refman/5.1/en/… . Will edit answer. –jensgram Jun 30 '10 at 7:12 Yeah, I just found that too :D I plugged it in and it worked perfectly. Thanks jensgram, just the solution I was looking
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Error 1062 Duplicate Entry
Business Learn more about hiring developers or posting ads with us Stack Overflow Questions error 1062 duplicate entry 'innodb' for key 'primary' Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million error 1062 duplicate entry '1' for key 'primary' programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Why do I get a duplicate entry error when there is no duplicate entry? up vote 0 down vote favorite I'm http://stackoverflow.com/questions/3146838/handle-error-for-duplicate-entries-php-mysql getting the following error: Duplicate entry 'ahamzaoui_v2' for key 'Username' in /opt/lampp/htdocs/webEchange/SiteWeb_V5/dupliquerCompte2.php on line 135 when running a php script. I've tried it many times but I don't know why I'm getting this error. Here is the code around line 135: $sql = "UPDATE utilisateur SET Username = '" . mysql_real_escape_string($infos['Username']) . "2', MotDePasse = '" . mysql_real_escape_string($infos['MotDePasse']) . "2' WHERE Matricule = " . $infos['Matricule']; line 135 -> if(mysql_query($sql)) as you can see, http://stackoverflow.com/questions/4262665/why-do-i-get-a-duplicate-entry-error-when-there-is-no-duplicate-entry I'm trying to append a 2 to the existing value for Username. Here is what I don't understand. If I go have a look at the utilisateur table, I can't find any entry with the value ahamzaoui_v2.Then I try running the script, and I get the error! The funny thing is, after the script has run (and reported an error), the value is changed! I now have ahamzaoui_v2 instead of ahamzaoui_v. The problem is that the REST of the script is not executed so I only get a part of what I want (a small part). Apart from a SELECT statement, this is the first query I run, so I really can't see how there can be a duplicate entry, espectially since I just checked for that before. upon reading this thread, I tryed running check table utilisateur, but it revealed no errors whatsoever.. btw, if I run the script many times in a row, I always get the error, and the username ends up with a whole lot of 2's appended to it (ahamzaoui_v222) php mysql duplicates share|improve this question asked Nov 24 '10 at 1:18 Shawn 3,44594475 add a comment| 2 Answers 2 active oldest votes up vote 2 down vote Aside from a corrupted database or key index there's only one other thing I can th
Gherkin Git Go Groovy Haml Handlebars Haskell HTML HTTP Ini iOS Jade Java Javascript jQuery JSON Julia Keyman LaTeX https://codedump.io/share/dhdw7IYpWWcd/1/how-to-show-php-duplicate-entry-error-message-on-current-page Linux Less LOLCODE Makefile Markdown MATLAB MySQL NASM Node.js NSIS Objective-C Pascal Perl PHP PHP Extras PowerShell Python R React JSX reST (reStructuredText) Rip Ruby Rust SAS Sass (Sass) Sass (Scss) Scala Scheme Smalltalk Smarty SQL Stylus Swift Twig TypeScript Vb.net VHDL Wiki markup YAML Other Search Anonymous - 10 months ago 138x PHP duplicate entry Question How to show PHP Duplicate Entry error message on current page I am creating a signup form for a website I am developing. I am using PHP to insert the form into my database. I have the useremail set as a Unique Key in my database. When I type in an email that duplicate entry error already exists in my database it brings me to a blank page with this error message: Duplicate entry '' for key 'email_2' How can I get this message to show up above the form, without clearing the form? In the code the "SERVER ERROR" and "BOTH FIELDS MUST BE COMPLETE" text is showing up in the correct place. How can I make the Duplicate entry error show up in the same way? Here is the PHP code I currently have. Please note I am successfully connecting to my database, but did not include the code here. $firstName = $_POST['firstname'];
$lastName = $_POST['lastname'];
$useremail = $_POST['useremail'];
$password = $_POST['password'];
$gender = $_POST['gender'];
$birthday = $_POST['birthday'];
$sqlDate = date('Y-m-d');
if ( $firstName!=''&&$lastName!=''&&$useremail!=''&&$password!=''&&$gender!=''&&$birthday!='')
{
$sql = "INSERT INTO user (fname, lname, email, password, gender, birthday) VALUES ('$firstName', '$lastName', '$useremail', '$password', '$gender', '$birthday')";
$res = mysql_query($sql) or die(mysql_error());
if($res)