Error 1062 Sql State
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Sql Error 1062 Sqlstate 23000 Duplicate Entry
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Mysql Error 1062 Duplicate Entry For Key Primary
Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. sqlstate 23000 integrity constraint violation 1062 duplicate entry for key primary Join them; it only takes a minute: Sign up SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry '1922-1' for key 'IDX_STOCK_PRODUCT' up vote 6 down vote favorite 2 While creating product, at the last step after retrieving for a time, Magento gives following error-: SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry '1922-1' for key 'IDX_STOCK_PRODUCT' What I am doing mysql error 1062 duplicate entry '0' for key 'primary' is, by capturing product id, I am putting it's entry in custom table. I have connected to Magento database externally. Surprisingly data is inserted in both Magento's base table & also in Custom table but why it is giving me that error after product saving...? I cleared cache, browser cookies. Also remove /var/cache, /var/session. still giving error. Can anybody suggest a solution? magento constraints mysql-error-1062 duplicates share|improve this question edited Dec 29 '12 at 16:21 Kate Gregory 16.1k74378 asked Apr 6 '12 at 13:20 Prat 19911127 This error means you're using the same primary key value twice in the same table. There is already a product with the ID of 1922-1 in IDX_STOCK_PRODUCT, and a query is trying to save a new record with that ID again. –mrlee Apr 6 '12 at 13:31 Whats the solution then? –Prat Apr 6 '12 at 13:35 Don't save data with a duplicate ID, basically. Without any code samples relevant to this error, that's the best solution you're going to get. &nda
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Magento Sqlstate[23000]: Integrity Constraint Violation: 1062 Duplicate Entry
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Error 1062 23000 Duplicate Entry For Key Primary
Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only http://stackoverflow.com/questions/10044062/sqlstate23000-integrity-constraint-violation-1062-duplicate-entry-1922-1-f takes a minute: Sign up Error Code: 1062. Duplicate entry '1' for key 'PRIMARY' up vote 9 down vote favorite 5 I have a problem on this error message, when i try this: INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`, `data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, `telefono`, `mail`, `web`, `Nome-paese`, `Comune`) VALUES (1, 'Viale Cogel ', '120', '2012-05-21', '2012-09-30', '08:00', '23:30', '461801243', 'informazioni@bolzano.it', http://stackoverflow.com/questions/14628269/error-code-1062-duplicate-entry-1-for-key-primary 'Bolzanoturismo.it', 'Bolzano', 'BZ') Error Code: 1062. Duplicate entry '1' for key 'PRIMARY' I haven't auto_increment data, PLEASE HELP me! This is the table related, UFFICIO-INFORMAZIONI CREATE TABLE IF NOT EXISTS `PROGETTO`.`UFFICIO-INFORMAZIONI` ( `ID` INT(11) NOT NULL , `viale` VARCHAR(45) NULL , `num_civico` VARCHAR(5) NULL , `data_apertura` DATE NULL , `data_chiusura` DATE NULL , `orario_apertura` TIME NULL , `orario_chiusura` TIME NULL , `telefono` VARCHAR(15) NULL , `mail` VARCHAR(100) NULL , `web` VARCHAR(100) NULL , `Nome-paese` VARCHAR(45) NOT NULL , `Comune` CHAR(2) NOT NULL , PRIMARY KEY (`ID`) , INDEX `Nome_paese` (`Nome-paese` ASC) , INDEX `Comune` (`Comune` ASC) , CONSTRAINT `Nome_paese` FOREIGN KEY (`Nome-paese` ) REFERENCES `PROGETTO`.`PAESE` (`Nome-paese` ) ON DELETE NO ACTION ON UPDATE CASCADE, CONSTRAINT `Comune` FOREIGN KEY (`Comune` ) REFERENCES `PROGETTO`.`PAESE` (`Comune` ) ON DELETE NO ACTION ON UPDATE CASCADE) ENGINE = InnoDB INSERT INTO INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`, `data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, `telefono`, `mail`, `web`, `Nome-paese`, `Comune`) VALUES (1, 'Viale Cogel ', '120', '2012-05-21', '2012-09-30', '08:00', '23:30', '461801243', 'informazioni@bolzano.it', 'Bolzanoturismo.it', 'Bolzano', 'BZ'); INSERT INTO `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`, `data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, `telefono`, `mail`, `web`, `Nome-
here for a quick overview of the site Help Center Detailed answers to any questions you http://stackoverflow.com/questions/19359120/integrity-constraint-violation-1062-duplicate-entry-1-for-key-primary might have Meta Discuss the workings and policies of this https://dev.mysql.com/doc/refman/5.5/en/error-messages-server.html site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community duplicate entry of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Integrity constraint violation: 1062 Duplicate entry '1' for key 'PRIMARY' up vote 4 down vote favorite 1 I have a databse problem where i get Integrity constraint violation: 1062. I tried some things on my 1062 duplicate entry own but it didtn work so now i am asking you guys to see if you people can help me out. elseif($action == 'add') { if($_POST['create'] == true) { $title = $_POST['txtTitle']; $txtParentCategorie = $_POST['txtParentCategorie']; $txtContent = $_POST['txtContent']; if($txtParentCategorie == "niks") { $txtParentCategorie = NULL; $chkParent = 1; $order_count = countQuery("SELECT categorieID FROM prod_categorie WHERE parentID=?",array(1)); $order = $order_count + 1; } else { $chkParent = null; $order_count = countQuery("SELECT categorieID FROM prod_categorie WHERE parentID is not NULL"); $order = $order_count + 1; } Query("INSERT INTO prod_categorie (categorieID, parentID) VALUES (?, ?)", array($chkParent, $txtParentCategorie)); $inserted_id = getLastInsertId(); Query("INSERT INTO tekst (tabel, kolom, item_id, tekst, taalID) VALUES(?, ?, ?, ?, ?)", array('prod_categorie', 'categoriename', $inserted_id, $title, $lang)); Query("INSERT INTO tekst (tabel, kolom, item_id, tekst, taalID) VALUES(?, ?, ?, ?, ?)", array('prod_categorie', 'content', $inserted_id, $txtContent, $lang)); $languages = selectQuery("SELECT taalID FROM taal WHERE taalID!=?",array($lang)); } when i run this the first INSERT INTO doesnt fill in any data and giving this error
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