Error Duplicate Entry For Key 1 On Query
Contents |
to my surprise occurred on a slave database. error 'Duplicate entry '2355476' for key 1' on query ' INSERT INTO logs (DateStamp) VALUES (NOW()) You might be wondering how a slave database could have a duplicate entry while the master and other slaves are running just fine? mysql error duplicate entry for key Some say that there could be an entry where it was written in the slave and then
Mysql Error Duplicate Entry For Key 'primary'
written again so the duplicate error occurred. Others say that if myisamchk was run in the master, it removed some entries and tries to create error 1062 duplicate entry for key those entries again. The slave then attempts to write the same entry, but since myisamchk was not executed on the slave, the entry exists hence the duplication error. But luckily, found myself a solution to fix the replication error: mysql> set sql_slave_skip_counter duplicate entry 0 for key 1 = 1;
Query OK, 0 rows affected (0.01 sec) mysql> slave start;
Query OK, 0 rows affected (0.00 sec) This will skip the error and continue on with the replication. Do not forget to start the slave process afterwards. Related PostsStrict Standards: date() [function.date] Error (2)Sudo error: Sorry, you must have a tty to run sudo (1)How to Fix PECL PHP Error: /bin/sh: bad interpreter: Permission denied (2)John Dvorak: The Sun-MySQL Deal Stinks (1)Sun Microsystems To Acquire MySQL for $1B (0) 3
Duplicate Entry For Key Primary Auto Increment
Comments to "Tip: MySQL Replication Error: Duplicate Entry for Key" Ratheesh January 7, 2010 at 6:57 pm I'm having the similar problem but its very often. I was more curios what would be root cause and how to resolve it once in for all. A stable solution that can solve the problem forever any ideas or anybody ?? Uma July 27, 2010 at 2:54 pm But any idea why in first place does this occur?? We face this error many times, we know the solution to skip the tran. But we need the reason as to why do we face this on slave, when all is fine on the master? mandm August 3, 2010 at 10:38 pm i had to do this set global sql_slave_skip_counter = 1; since it is a global variable but what does this setting actually do internally to the entire replication process Post comment Click here to cancel reply. Name (required) Mail (will not be published) (required) Website Comment Notify me of followup comments via e-mail Follow me on Twitter! Got Plurk? Follow on Plurk instead. Search PinoyTux Subscribe to Email Feeds Enter Email Address: Blog Lounge Contact Me Disclosure Policy PinoyTux Archives Popular Posts Tips for Keeping Your Cloud Secure Cebu Pacific Sucks Howto: Install yum On RHEL 4 Recent Posts Vim: How to Copy Multiple Lines Required Packages for Oracle 11gR2 on Red Hat Enterprise Linux 6 How Replace Space with Newl
log in tour help Tour Start here for a quick overview of the site Help duplicate entry for key 'primary' sql=insert into Center Detailed answers to any questions you might have Meta duplicate entry for key 'group_key' Discuss the workings and policies of this site About Us Learn more about Stack Overflow
Duplicate Entry For Key Unique
the company Business Learn more about hiring developers or posting ads with us Database Administrators Questions Tags Users Badges Unanswered Ask Question _ Database http://www.pinoytux.com/linux/tip-mysql-replication-error-duplicate-entry-for-key Administrators Stack Exchange is a question and answer site for database professionals who wish to improve their database skills and learn from others in the community. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The http://dba.stackexchange.com/questions/68317/master-master-replication-duplicate-key best answers are voted up and rise to the top Master-Master Replication Duplicate Key up vote 1 down vote favorite 1 I have set two servers master-master replication mysql , i manage to set successfully but the problem is the duplicate key i got MASTER 1 Configuration /etc/my.cnf [mysqld] server-id=1 bind-address = 0.0.0.0 log_bin = /var/log/mysql/bin.log log-slave-updates log_bin-index = /var/log/mysql/bin.index log_error = /var/log/mysql/error.log relay_log = /var/log/mysql/relay.log relay-log-info-file = /var/log/mysql/relay.info relay-log-index = /var/log/mysql/relay.index binlog_do_db=database_name replicate-do-db = database_name auto-increment-increment = 10 auto-increment-offset = 1 innodb_file_per_table=1 open_files_limit=7306 mysql> show slave status\G *************************** 1. row *************************** Slave_IO_State: Waiting for master to send event Master_Host: 10.0.0.1 Master_User: database_name Master_Port: 3306 Connect_Retry: 60 Master_Log_File: bin.000021 Read_Master_Log_Pos: 8385119 Relay_Log_File: relay.000019 Relay_Log_Pos: 79533 Relay_Master_Log_File: bin.000021 Slave_IO_Running: Yes Slave_SQL_Running: No Replicate_Do_DB: database_name Replicate_Ignore_DB: Replicate_Do_Table: Replicate_Ignore_Table: Replicate_Wild_Do_Table: Replicate_Wild_Ignore_Table: Last_Errno: 1062 Last_Error: Error 'Duplicate entry '19882' for key 'PRIMARY'' on query. Default database: 'database_name'. Q
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack http://stackoverflow.com/questions/7025153/duplicate-entry-2147483647-for-key-1 Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a http://mysql.wingtiplabs.com/documentation/reprv7zv/repair-replication community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Duplicate entry '2147483647' for key 1 up vote 11 down vote favorite 1 Strange problem duplicate entry I can't seem to get my head around. I have a table in a MySQL database with the following structure... CREATE TABLE IF NOT EXISTS `tblbaseprices` ( `base_id` bigint(11) NOT NULL auto_increment, `base_size` int(10) NOT NULL default '0', `base_label` varchar(250) default NULL, `base_price_1a` float default NULL, `base_price_2a` float default NULL, `base_price_3a` float default NULL, `base_price_1b` float default NULL, `base_price_2b` float default NULL, `base_price_3b` float default NULL, `site_id` int(11) default NULL, PRIMARY duplicate entry for KEY (`base_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=134 ; The last base_id I have in there is 132. I assume a couple of records have been deleted to auto_increment is set to 134, as you can see about. I am trying to run the following SQL statement, and when I do, I get the error "Duplicate entry '2147483647' for key 1". INSERT INTO tblbaseprices (site_id, base_size, base_price_1a, base_price_2a, base_price_3a, base_price_4a) VALUES ('', '', '', '', '', '') Does anybody have any ideas? Many thanks! mysql share|improve this question asked Aug 11 '11 at 11:36 Doyley 791115 Any reason why you inseret empty strings into float/int columns? –Jacob Aug 11 '11 at 11:40 2 What is base_price_4a? I don't see it in your create table. –sapht Aug 11 '11 at 11:44 1 @sapht It can be the reason of error. –Devart Aug 11 '11 at 11:48 add a comment| 10 Answers 10 active oldest votes up vote 3 down vote accepted With you code I got this error - Unknown column 'base_price_4a' in 'field list'. It means that you are trying to insert into another table (maybe in another schema), and that table has primary key INT and AUTO_INCREMENT=2147483647. share|improve this answer answered Aug 11 '11 at
from the master's binary log into its own relay log, then applies events from its relay log to its own live database. There is no feedback mechanism from the slave to the master if applying events to the slave's database causes an unrecoverable error; the slave stops replicating and waits for help from an administrator. This procedure will solve a data corruption problem that halts a master-master replication. Specifically, we'll handle a primary key collision. The table important.stuff has a typical AUTO_INCREMENT primary key. Both servers in this master-master replication accept INSERTs to the same table. Because MySQL replication is asynchronous, it is possible for both masters to write a new row that uses the same primary key. When these new rows replicate, the receiving master will have a duplicate key on a column that must be unique, and replication will stop in both directions. There is no substitute for experience. You replicate data because it's important. Treat your important data right, and get concrete experience with replication in our hands-on course. What's in the course? StepsTest Replication from A to BAt the beginning of this lesson, replication should be working correctly. Log in to a.example.com From A, insert a new record in the important.stuff table. a ~ $ mysql -u root mysql> INSERT INTO important.stuff SET details='Gift from A to B'; Query OK, 1 row affected (0.03 sec)Log in to b.example.com Now on B, check that the record has replicated. b ~ $ mysql -u root mysql> SELECT * FROM important.stuff ORDER BY id DESC LIMIT 1\G *************************** 1. row *************************** id: 7 details: Gift from A to B happened: 2013-03-27 04:09:40 1 rows in set (0.00 sec)After this step is completed:INSERT a new record on A in the table important.stuffWithin 1 second, that record is replicated to BTest Replication from the B to ANow test that changes to B also replicate to A. Still on B, insert a new record in the important.stuff table. mysql> INSERT INTO important.stuff SET details='Gift from B to A'; Query OK, 1 row affected (0.03 sec) mysql>Now on A, check that the record has replicated. mysql> SELECT * FROM important.stuff ORDER BY id DESC LIMIT 1\G *************************** 1. row *************************** id: 9 details: Gift from B to A happened: 2013-03-27 04:09:40 1 rows in set (0.00 sec)After this step is completed:INSERT a new record on B in the tab