Duplicate Error Sql
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Sql Duplicate Key Error
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Mysql Error 1062 Duplicate Entry For Key Primary
who wish to improve their database skills and learn from others in the community. Join them; it only takes a minute: Sign up Here's how it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top How to avoid a “duplicate key” error? up vote
Ignore Duplicate Key Sql Server
4 down vote favorite This statement: INSERT INTO deleteme SELECT #t.id, 'test' FROM #t LEFT JOIN deleteme ON deleteme.id = #t.id WHERE deleteme.id IS NULL; ...will fail with a primary key violation in the concurrent scenario (i.e. when inserting the same key that is absent in deleteme from several threads at the same time) with the default transaction isolation level of READ COMMITTED: Error: Violation of PRIMARY KEY constraint 'PK_DeleteMe'. Cannot insert duplicate key in object 'dbo.deleteme'. What is the best way to prevent that? The table looks something like this: CREATE TABLE [dbo].[DeleteMe]( [id] [uniqueidentifier] NOT NULL, [Value] [varchar](max) NULL, CONSTRAINT [PK_DeleteMe] PRIMARY KEY ([id] ASC)); Update From comments: Why do you have multiple sessions, which can obviously pull the same id from somewhere, using the same permanent table without having some kind of session key to tell them apart? Even without a duplicate error, how are you going to know which rows belong to which session? This is a store
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Mysql Duplicate Entry For Key Primary
of this site About Us Learn more about Stack Overflow the company Business Learn more about cannot insert duplicate key in object the duplicate key value is (1) hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow http://dba.stackexchange.com/questions/111754/how-to-avoid-a-duplicate-key-error is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up Error Code: 1062. Duplicate entry '1' for key 'PRIMARY' up vote 9 down vote favorite 5 I have a problem on this error message, when i try this: INSERT INTO http://stackoverflow.com/questions/14628269/error-code-1062-duplicate-entry-1-for-key-primary `PROGETTO`.`UFFICIO-INFORMAZIONI` (`ID`, `viale`, `num_civico`, `data_apertura`, `data_chiusura`, `orario_apertura`, `orario_chiusura`, `telefono`, `mail`, `web`, `Nome-paese`, `Comune`) VALUES (1, 'Viale Cogel ', '120', '2012-05-21', '2012-09-30', '08:00', '23:30', '461801243', 'informazioni@bolzano.it', 'Bolzanoturismo.it', 'Bolzano', 'BZ') Error Code: 1062. Duplicate entry '1' for key 'PRIMARY' I haven't auto_increment data, PLEASE HELP me! This is the table related, UFFICIO-INFORMAZIONI CREATE TABLE IF NOT EXISTS `PROGETTO`.`UFFICIO-INFORMAZIONI` ( `ID` INT(11) NOT NULL , `viale` VARCHAR(45) NULL , `num_civico` VARCHAR(5) NULL , `data_apertura` DATE NULL , `data_chiusura` DATE NULL , `orario_apertura` TIME NULL , `orario_chiusura` TIME NULL , `telefono` VARCHAR(15) NULL , `mail` VARCHAR(100) NULL , `web` VARCHAR(100) NULL , `Nome-paese` VARCHAR(45) NOT NULL , `Comune` CHAR(2) NOT NULL , PRIMARY KEY (`ID`) , INDEX `Nome_paese` (`Nome-paese` ASC) , INDEX `Comune` (`Comune` ASC) , CONSTRAINT `Nome_paese` FOREIGN KEY (`Nome-paese` ) REFERENCES `PROGETTO`.`PAESE` (`Nome-paese` ) ON DELETE NO ACTION ON UPDATE CASCADE, CONSTRAINT `Comune` FOREIGN KEY (`Comune` ) REFERENCES `PROGETTO`.`PAESE` (`Comune` ) ON DELETE NO ACTION ON UPDA
Joomla templatesPricingcheck best valuesHelpneed help? get it hereBlogworth readingNewsJoomla TemplatesWeb Development 0Cart Empty Cart 0 Product(s) You are here: Home / Blog / Joomla Templates / https://www.joomla-monster.com/blog/joomla-templates/solution-for-1602-duplicate-sql-entry-error-while-updating-to-joomla-3-6 Solution for: 1602 Duplicate sql entry error while updating to Joomla 3.6. Solution for: 1602 Duplicate sql entry error while updating to Joomla 3.6. Details 02 https://github.com/phpmyadmin/phpmyadmin/issues/11727 August 2016 Written by Artur Kaczmarek 0.00 (0 votes) In this tutorial I would like to show you how to solve most common issue that may duplicate entry appear when updating to Joomla 3.6. The same problem appeared while we had been in the middle of our templates update so we created a script that helped us a lot. Now we want to share it with you. The database fix script has been tested on over 80 Joomla! installations on sql error duplicate our servers.1062 Duplicate entry '802' for key 'PRIMARY' SQL=INSERT INTO `#__extensions` (`extension_id`, `name`, `type`, `element`, `folder`, `client_id`, `enabled`, `access`, `protected`, `manifest_cache`, `params`, `custom_data`, `system_data`, `checked_out`, `checked_out_time`, `ordering`, `state`) VALUES (802, 'English (United Kingdom)', 'package', 'pkg_en-GB', '', 0, 1, 1, 1, '', '', '', '', 0, '0000-00-00 00:00:00', 0, 0);What happened?In short, one of your plugins uses the extension ID 802 which should be used only by Joomla! core plugins. For some reason the SQL AUTO_INCREMENT 10000 on #__extensions table does not work. All IDs below 10000 are reserved for Joomla! and 3rd party (additonal) plugins should NOT use them.How to solve this issue?That's quite easy with our script. But at first, remember to make backup of your Joomla! installation. You can use for example Akeeba Backup extension for this purpose. You will find package at Joomla Extensions Directory1. Create backup of your site!!!2. Download archivefix script(2 KB).3.Unizp package (do NOT install it via Extensi
Sign in Pricing Blog Support Search GitHub This repository Watch 163 Star 1,867 Fork 1,085 phpmyadmin/phpmyadmin Code Issues 184 Pull requests 13 Projects 0 Wiki Pulse Graphs New issue SQL duplicate entry error trying to INSERT in designer_settings table #11727 Closed jesucarr opened this Issue Dec 7, 2015 · 47 comments Projects None yet Labels bug Milestone 4.5.4 Assignees devenbansod 4 participants jesucarr commented Dec 7, 2015 I'm getting this error when going to the Designer page: #1062 - Duplicate entry 'myuser' for key 'PRIMARY' The SQL that is trying to execute is: INSERT INTO `phpmyadmin`.`pma__designer_settings` (username, settings_data) VALUES('myuser', '{"relation_lines":"true"}'); In the table settings there is already one row with that username, and the setting {"snap_to_grid":"off"} As the table has the username as primary key, I guess the query should try to UPDATE and add the new setting value, instead of trying to INSERT. When I try to add settings to the pma__userconfig table, it works as expected. I'm using version 4.5.2 and PHP 5.6.16 nijel added the bug label Dec 8, 2015 phpMyAdmin member devenbansod commented Dec 18, 2015 Actually it should and was meant to UPDATE only and the code was originally written to do update. Can you reproduce this on our demo server ? Or may be try deleting the row for the user manually first and then open up designer, change some settings (so that a row is inserted) into the pma__designersettings table, close the designer and open it again to change a few more settings and check if you can reproduce the issue ? Also, could anyone confirm if they can also reproduce this issue ? lem9 commented Dec 18, 2015 Cannot reproduce. To debug this, we need some tracing from you. In libraries/pmd_common.php, function PMA_saveDesignerSetting(), the decision to UPDATE or INSERT is based on the results of a SELECT. Please tell us the content of $orig_data_query and $orig_data. jesucarr commented Dec 18, 2015 $orig_data_query = SELECT settings_data FROM `phpmyadmin`.`pma__designer_settings` WHERE username = 'myuser'; $orig_data = It seems that $orig_data is empty, so it doesn't go to the UPDATE query. I noticed that when printing $GLOBALS['dbi'] and $GLOBALS['controllink'] are also empty. Not sure if that is the issue. phpMyAdmin member devenbansod commented Dec