Error No 1005 En Mysql
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Error 1005 Mysql Errno 121
Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just error code 1005 mysql like you, helping each other. Join them; it only takes a minute: Sign up Error Code: 1005. Can't create table '…' (errno: 150) up vote 74 down vote favorite 30 I searched for a solution to this error code 1005 mysql errno 150 problem on internet and checked the SO questions but no solution worked for my case. I want to create a foreign key from table sira_no to metal_kod. ALTER TABLE sira_no ADD CONSTRAINT METAL_KODU FOREIGN KEY(METAL_KODU) REFERENCES metal_kod(METAL_KODU) ON DELETE SET NULL ON UPDATE SET NULL ; This script returns: Error Code: 1005. Can't create table 'ebs.#sql-f48_1a3' (errno: 150) I tried adding index to the referenced table: CREATE INDEX METAL_KODU_INDEX ON metal_kod (METAL_KODU); I checked METAL_KODU
Mysql Error 1005 (hy000)
on both tables (charset and collation). But couldn't find a solution to this problem. Does anyone have any idea? Thanks in advance. EDIT: Here is the metal_kod table: METAL_KODU varchar(4) NO PRI DURUM bit(1) NO METAL_ISMI varchar(30) NO AYAR_YOGUNLUK smallint(6) YES 100 mysql mysql-error-1005 share|improve this question edited Jan 27 '14 at 7:57 Melon 786617 asked Jan 26 '12 at 13:14 lamostreta 85122045 Can you show the schema for the metal_kod table ... which field in that table should the Foreign Key reference ? –ManseUK Jan 26 '12 at 13:28 add a comment| 9 Answers 9 active oldest votes up vote 199 down vote accepted Error Code: 1005 -- there is a wrong primary key reference in your code usually it's due to a reference FK field not exist. might be you have typo mistake,or check case it should be same, or there's a field-type mismatch. FK-linked fields must match definitions exactly. Some Known causes may be : The two key fields type and/or size doesn’t match exactly. For example, if one is INT(10) the key field needs to be INT(10) as well and not INT(11) or TINYINT. You may want to confirm the field size using SHOW CREATE TABLE because Query Browser will sometimes visually show just INTEGER for both INT(10) and INT(11). You should also check that one i
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#1005 - Can't Create Table (errno 150) Foreign Key
Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like http://stackoverflow.com/questions/9018584/error-code-1005-cant-create-table-errno-150 you, helping each other. Join them; it only takes a minute: Sign up MySQL ERROR 1005: Can't create table (errno: 150) up vote 6 down vote favorite I am trying to create the following table create table messaInScena ( data date, ora time, spazio varchar(20), spettacolo varchar(40), postiDisponibili smallint, prezzoIntero decimal(5,2), prezzoRidotto decimal(5,2), prezzoStudenti decimal(5,2), primary key http://stackoverflow.com/questions/17812616/mysql-error-1005-cant-create-table-errno-150 (data, ora, spazio), foreign key (spazio) references spazio(nome) on update cascade on delete set null, foreign key (spettacolo) references spettacolo(titolo) on update cascade on delete set null, constraint RA3_1 check (postiDisponibili >= 0) ) ; but I get the following error: Error Code: 1005 Can not create table 'teatrosql.messainscena' (errno: 150) The tables that are referenced by foreign keys are: create table spazio ( nome varchar(20) primary key, indirizzo varchar(40) not null, pianta varchar(20), capienza smallint ); create table spettacolo ( titolo varchar(40) primary key, descrizione LONGBLOB, annoProduzione char(4) ); I have already verified that the fk are unique and that there are no typos (but given a control also you that you never know :D). As you can see the reference fields are primary keys. between fields and fk reference types and dimensions coincide .. where am I wrong?? the the other tables of DB create table teatro ( nome varchar(20) primary key, telefono varchar(15), fax varchar(15), indirizzo varchar(40) not null, email varchar(30), url varchar(30) ); create tab
log in tour help Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About http://dba.stackexchange.com/questions/62114/create-table-shows-error-1005hy000-errno-150 Us Learn more about Stack Overflow the company Business Learn more about hiring https://mariadb.org/mariadb-innodb-foreign-key-constraint-errors/ developers or posting ads with us Database Administrators Questions Tags Users Badges Unanswered Ask Question _ Database Administrators Stack Exchange is a question and answer site for database professionals who wish to improve their database skills and learn from others in the community. Join them; it only takes a minute: Sign up Here's how error 1005 it works: Anybody can ask a question Anybody can answer The best answers are voted up and rise to the top Create table shows ERROR 1005(HY000) errno 150 up vote 0 down vote favorite i tried to create tables as per given in my textbook in MySQL server as follows: create table department (dept_name varchar(20), building varchar(15), budget numeric(12,2), primary key (dept_name) ); create table course (course_id error 1005 mysql varchar(8), title varchar(50), dept_name varchar(20), credits numeric(2,0), primary key (course_id), foreign key (dept_name) references department ); the department table gets created, but an error ERROR 1005 (HY000): Can't create table 'test.course' (errno: 150) is displayed. The queries seem very simple. And i am unable to find any mistake. What can be the possible error that is preventing me to create the table? mysql foreign-key share|improve this question asked Mar 31 '14 at 5:29 Amita 312 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote accepted You are missing column name of parent table to which your child refer, while creating child table, do like below create table department (dept_name varchar(20), building varchar(15), budget numeric(12,2), primary key (dept_name) ); create table course (course_id varchar(8), title varchar(50), dept_name varchar(20), credits numeric(2,0), primary key (course_id), foreign key (dept_name) references department(dept_name) ); share|improve this answer answered Mar 31 '14 at 5:32 Abdul Manaf 4,75063864 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your
for Developers MariaDB Contributor Agreement MariaDB Contributor Agreement FAQs Community Ambassadors Events Past Events and Conferences Sponsor Sponsors List of Donors Blog About MariaDB Sponsors Governance Logos and Badges MariaDB Trademark Usage Statistics Service Providers Maintenance Policy Security Policy Download Learn Get Involved Social Media Getting Started for Developers MariaDB Contributor Agreement MariaDB Contributor Agreement FAQs Community Ambassadors Events Past Events and Conferences Sponsor Sponsors List of Donors Blog HomeGeneralMariaDB: InnoDB foreign key constraint errors MariaDB: InnoDB foreign key constraint errors 2015-08-07 4 Comments Written by Jan Lindstrom Introduction A foreign key is a field (or collection of fields) in one table that uniquely identifies a row of another table. The table containing the foreign key is called the child table, and the table containing the candidate key is called the referenced or parent table. The purpose of the foreign key is to identify a particular row of the referenced table. Therefore, it is required that the foreign key is equal to the candidate key in some row of the primary table, or else have no value (the NULL value). This is called a referential integrity constraint between the two tables. Because violations of these constraints can be the source of many database problems, most database management systems provide mechanisms to ensure that every non-null foreign key corresponds to a row of the referenced table. Consider following simple example: create table parent ( id int not null primary key, name char(80) ) engine=innodb; create table child ( id int not null, name char(80), parent_id int, foreign key(parent_id) references parent(id) ) engine=innodb; As far as I know, the following storage engines for MariaDB and/or MySQL support foreign keys: InnoDB (both innodb_plugin and XtraDB) PBXT (https://mariadb.com/kb/en/mariadb/about-pbxt/) SolidDB for MySQL (http://sourceforge