C2664 Error
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C2664 Parameters
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C2664 Function
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Error C2664 Lpcwstr
other. Join them; it only takes a minute: Sign up error C2664: cannot convert parameter 1 from 'int' to 'int []' up vote 0 down vote favorite #include
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs error c2664 in c++ Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community error c2664 messageboxw of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up error C2664: cannot convert parameter 1 from 'int' error c2059 to 'int (__cdecl *)(int)' up vote 1 down vote favorite 2 having some trouble passing a function as a parameter of another function... ERROR: Error 1 error C2664: 'wrapper' : cannot convert parameter 1 from 'int' to 'int (__cdecl *)(int)' int inc( int n ) http://stackoverflow.com/questions/22150353/error-c2664-cannot-convert-parameter-1-from-int-to-int { return n + 1 ; } int dec( int n ) { return n - 1 ; } int wrapper( int i, int func(int) ) { return func( i ) ; } int main(){ int a = 0 ; a = wrapper( 3, inc( 3 ) ) ; return 0 ; } c++ function parameters c2664 share|improve this question edited Jun 22 '11 at 18:07 user195488 asked Jun 13 '11 at 14:52 tuk 4718 add a comment| 5 Answers 5 active oldest votes up vote 5 down vote http://stackoverflow.com/questions/6332078/error-c2664-cannot-convert-parameter-1-from-int-to-int-cdecl-int accepted You're passing the result of a function call inc(3) to wrapper, NOT a function pointer as it expects. a = wrapper(3, &inc) ; share|improve this answer answered Jun 13 '11 at 14:54 Mark B 76.4k465138 add a comment| up vote 1 down vote Your call is passing an integer, the return value from calling inc(3), i.e. 4. That is not a function pointer. Perhaps you meant: a = wrapper(3, inc); This would work, and assign a to the value of calling int with the parameter 3. share|improve this answer answered Jun 13 '11 at 14:54 unwind 253k38330460 add a comment| up vote 1 down vote The line: a = wrapper( 3, inc( 3 ) ) ; is effectively: a = wrapper(3, 4); I think you mean: a = wrapper(3, inc); This passes a pointer to the inc() function as the second argument to wrapper(). share|improve this answer answered Jun 13 '11 at 14:55 janm 12.5k12646 add a comment| up vote 1 down vote As it is now, wrapper takes an int and a pointer to a function that takes one int and returns an int. You are trying to pass it an int and an int, because instead of passing the a pointer to the function, you're calling the function and passing the return value (an int). To get your code to work as (I think) you expect, change your call to wrapper to this: a = wrapper(3, &inc); share|improve this answer edited Jun 13 '11 at 15:17 answered Jun 13 '11 at 14:55 Seth Carnegie 52.2k8110170 1 many thanks for the quick replies ever
Verbs Diet Index 2010-03-28 Error C2664 http://cboard.cprogramming.com/cplusplus-programming/86608-error-c2664-cannot-convert-parameter-1-int-int-[].html LoadLibraryW cannot convert parameter to LPCWSTR I recently used Microsoft Visual Studio 2008 to write a simple program to load a dynamic link library error c2664 (DLL) module and invoke some of its entry points. I did not expect to get the error message C2664 from the simple LoadLibrary statement:HINSTANCE hinstLib = LoadLibrary("azspellaid.dll"); Error C2664: 'LoadLibraryW': error c2664 lpcwstr cannot convert parameter 1 from 'const char [15]' to 'LPCWSTR' There are two ways of fixing this problem. The first one is to cast the quoted string with a Long Pointer to Const Wide String (LPCWSTR):HINSTANCE hinstLib = LoadLibrary((LPCWSTR)L"azspellaid.dll"); The C2664 error can also be resolved by keeping the original code and changing the character set of the project defaults from "unicode character set" to "multi-byte character set" as shown in this image: © Copyright2012 - Antonio Zamora
Programming Boards C++ Programming error C2664: cannot convert parameter 1 from 'int' to 'int []' Getting started with C or C++ | C Tutorial | C++ Tutorial | C and C++ FAQ | Get a compiler | Fixes for common problems Thread: error C2664: cannot convert parameter 1 from 'int' to 'int []' Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 12-15-2006 #1 mai077 View Profile View Forum Posts Registered User Join Date Dec 2006 Posts 4 error C2664: cannot convert parameter 1 from 'int' to 'int []' Hello all. I'm so new in C++ Programming that a simple problem seems extremely difficult!! The only thing that I have to do is to calculate the sum, the average, the max and the min of 10 numbers given by the user!! My code is: Code: #include