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Error C2664 Cannot Convert Argument

requested has been removed. You’ll be auto redirected in 1 second. C/C++ Building Reference C/C++ Build Errors Compiler Errors C2600 Through C2699 Compiler Errors

Error C2664 In C++

C2600 Through C2699 Compiler Error C2664 Compiler Error C2664 Compiler Error C2664 Compiler Error C2600 Compiler Error C2601 Compiler Error C2602 Compiler Error C2603 Compiler Error C2605 Compiler Error C2611 Compiler Error C2612 Compiler Error C2613 Compiler Error C2614 Compiler Error C2616 Compiler Error C2617 Compiler Error C2619 Compiler visual studio error c2664 Error C2624 Compiler Error C2626 Compiler Error C2627 Compiler Error C2628 Compiler Error C2630 Compiler Error C2632 Compiler Error C2633 Compiler Error C2634 Compiler Error C2635 Compiler Error C2636 Compiler Error C2637 Compiler Error C2638 Compiler Error C2640 Compiler Error C2645 Compiler Error C2646 Compiler Error C2647 Compiler Error C2648 Compiler Error C2649 Compiler Error C2650 Compiler Error C2651 Compiler Error C2652 Compiler Error C2653 Compiler Error C2654 Compiler Error C2655 Compiler Error C2656 Compiler Error C2657 Compiler Error C2658 Compiler Error C2659 Compiler Error C2660 Compiler Error C2661 Compiler Error C2662 Compiler Error C2663 Compiler Error C2664 Compiler Error C2665 Compiler Error C2666 Compiler Error C2667 Compiler Error C2668 Compiler Error C2669 Compiler Error C2670 Compiler Error C2671 Compiler Error C2673 Compiler Error C2674 Compiler Error C2675 Compiler Error C2676 Compiler Error C2677 Compiler Error C2678 Compiler Error C2679 Compiler Error C268

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Error C2664 In Visual C++

Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community error c2664 cannot convert parameter 1 from 'const char *' to 'char *' Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up error C2664: error c2664 cannot convert parameter 1 from 'const char *' to 'lpcwstr' cannot convert parameter 1 from 'int' to 'int (__cdecl *)(int)' up vote 1 down vote favorite 2 having some trouble passing a function as a parameter of another function... ERROR: Error 1 error C2664: 'wrapper' : cannot convert parameter 1 from 'int' https://msdn.microsoft.com/en-us/library/s5b150wd.aspx to 'int (__cdecl *)(int)' int inc( int n ) { return n + 1 ; } int dec( int n ) { return n - 1 ; } int wrapper( int i, int func(int) ) { return func( i ) ; } int main(){ int a = 0 ; a = wrapper( 3, inc( 3 ) ) ; return 0 ; } c++ function parameters c2664 share|improve this question edited Jun 22 '11 at 18:07 user195488 asked Jun 13 '11 at 14:52 tuk 4718 add a http://stackoverflow.com/questions/6332078/error-c2664-cannot-convert-parameter-1-from-int-to-int-cdecl-int comment| 5 Answers 5 active oldest votes up vote 5 down vote accepted You're passing the result of a function call inc(3) to wrapper, NOT a function pointer as it expects. a = wrapper(3, &inc) ; share|improve this answer answered Jun 13 '11 at 14:54 Mark B 76.4k465138 add a comment| up vote 1 down vote Your call is passing an integer, the return value from calling inc(3), i.e. 4. That is not a function pointer. Perhaps you meant: a = wrapper(3, inc); This would work, and assign a to the value of calling int with the parameter 3. share|improve this answer answered Jun 13 '11 at 14:54 unwind 254k38331460 add a comment| up vote 1 down vote The line: a = wrapper( 3, inc( 3 ) ) ; is effectively: a = wrapper(3, 4); I think you mean: a = wrapper(3, inc); This passes a pointer to the inc() function as the second argument to wrapper(). share|improve this answer answered Jun 13 '11 at 14:55 janm 12.6k12646 add a comment| up vote 1 down vote As it is now, wrapper takes an int and a pointer to a function that takes one int and returns an int. You are trying to pass it an int and an int, because instead of passing the a pointer to the function, you're calling the function and passing the return value (an int). To get your code to work as (I think) you expect, change your call to wrapper to this: a = wrapper(3, &inc); share|improve this

here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of http://stackoverflow.com/questions/28003599/c-error-c2664-cannot-convert-argument-1 this site About Us Learn more about Stack Overflow the company Business http://www.cplusplus.com/forum/general/31741/ Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up error c2664 c++ error C2664 cannot convert argument 1 up vote 0 down vote favorite I'm creating a binary tree and I'm trying to implement a function for creating that tree. So that is the code for every member of the tree template struct Node { T data; Node* left; Node* right; Node() { data = NULL; left = NULL; right = NULL; error c2664 cannot } }; The "BinaryTree" class have only one member called "root" whose type is Node and my function for creating the tree is: void CreateTree(istream &in) { char help; int data; in >> help; while (help == 'y') { in >> data; addLeaf(root, data); in >> help; } } and the addLeaf function is: void addLeaf(Node* &nod, int data) { if (nod == NULL) { nod = new Node(); nod->data = data; } else if (data < nod.data) addLeaf(nod->left, data); else addLeaf(nod->right, data); } The result is: error C2664: 'void BinaryTree::addLeaf(Node *&,int)' : cannot convert argument 1 from 'Node' to 'Node *&' What should I do? c++ share|improve this question edited Jan 17 '15 at 19:51 Borgleader 11.4k42342 asked Jan 17 '15 at 19:50 Никола Хилендаров 638 4 The type of root is Node or Node* ? –P0W Jan 17 '15 at 19:53 3 The compiler says exactly what is wrong. root is a Node but addLeaf expects a Node*&. –Raymond Chen Jan 17 '15 at 20:04 Thank you, that was my mistake –Никола Хилендаров Jan 17 '15 at 20:05 add a c

consists of 13 header files and of 12 cpp file. I've created a procedure in a cpp file called PCA.cpp. This is the content of the file: 1
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#include "stdafx.h" #include "alglibinternal.h" #include "alglibmisc.h" #include "ap.h" #include "dataanalysis.h" #include "gauss.h" #include "linalg.h" #include "optimization.h" #include "solvers.h" #include "specialfunctions.h" #include "statistics.h" #include using namespace std; using namespace alglib; using namespace alglib_impl; void Princ(char img1[30], char img2[30], char img3[30], char img4[30]) { //remove(argv[5]); TIFF *tif1, *tif2, *tif3, *tif4; tif1 = TIFFOpen(img1, "r"); tif2 = TIFFOpen(img2, "r"); tif3 = TIFFOpen(img3, "r"); tif4 = TIFFOpen(img4, "r"); // ... others parts of code, but img1 img2 img3 img4 will no longer be used } Header files that I've included are needed to solve some function used in Princ procedure. In the main file called pcasogl.cpp I wrote: 1
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#include "gauss.h" #include #include #include #include using namespace std; extern void Princ(char, char, char, char); // main program int main(int argc, char *argv[]) { // ..... Princ(argv[1],argv[2],argv[3],argv[4]); // ..... } where in the .bat file argv[1], argv[2], argv[3], argv[4] are the names of the image I want to open. Compiling I receive this error: 1>c:\users\...\pcasogl.cpp(46) : error C2664: 'Princ' : cannot convert parameter 1 from 'char *' to 'char' The strange thing is that if I copy the content of PCA.cpp file in the main file it works perfectly, so probably it's a problem with the "extern" called. Thanks so much to anyone who will try to help me. Last edited on Nov 18, 2010 at 9:59am UTC Nov 18, 2010 at 10:19am UTC coder777 (5934) so probably it's a problem with the "extern" called. No. extern is just unnecessary for

 

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