Error C2664 Cannot Convert Parameter 1
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here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn error c2664 in visual c++ more about Stack Overflow the company Business Learn more about hiring developers or error c2664 cannot convert parameter 1 from 'const char *' to 'char *' posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community error c2664 cannot convert parameter from const char to lpcwstr Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up error C2664: cannot convert parameter 1 from 'int' to 'int error c2664 visual studio []' up vote 0 down vote favorite #include
Error C2664 Cannot Convert Parameter 1 From 'const Char *' To 'lpcwstr'
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Cannot Convert Argument 1 From Int [] To Int
the company Business Learn more about hiring developers or posting ads with us Stack Overflow cannot convert parameter 1 from 'char *' to 'lpcwstr' Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of error c2440 4.7 million programmers, just like you, helping each other. Join them; it only takes a minute: Sign up error C2664: cannot convert parameter 1 from 'int' to 'int (__cdecl *)(int)' up vote 1 down vote favorite http://stackoverflow.com/questions/22150353/error-c2664-cannot-convert-parameter-1-from-int-to-int 2 having some trouble passing a function as a parameter of another function... ERROR: Error 1 error C2664: 'wrapper' : cannot convert parameter 1 from 'int' to 'int (__cdecl *)(int)' int inc( int n ) { return n + 1 ; } int dec( int n ) { return n - 1 ; } int wrapper( int i, int func(int) ) { return func( i ) ; } int main(){ int a = http://stackoverflow.com/questions/6332078/error-c2664-cannot-convert-parameter-1-from-int-to-int-cdecl-int 0 ; a = wrapper( 3, inc( 3 ) ) ; return 0 ; } c++ function parameters c2664 share|improve this question edited Jun 22 '11 at 18:07 user195488 asked Jun 13 '11 at 14:52 tuk 4718 add a comment| 5 Answers 5 active oldest votes up vote 5 down vote accepted You're passing the result of a function call inc(3) to wrapper, NOT a function pointer as it expects. a = wrapper(3, &inc) ; share|improve this answer answered Jun 13 '11 at 14:54 Mark B 76.4k465138 add a comment| up vote 1 down vote Your call is passing an integer, the return value from calling inc(3), i.e. 4. That is not a function pointer. Perhaps you meant: a = wrapper(3, inc); This would work, and assign a to the value of calling int with the parameter 3. share|improve this answer answered Jun 13 '11 at 14:54 unwind 254k38331460 add a comment| up vote 1 down vote The line: a = wrapper( 3, inc( 3 ) ) ; is effectively: a = wrapper(3, 4); I think you mean: a = wrapper(3, inc); This passes a pointer to the inc() function as the second argument to wrapper(). share|improve this answer answered Jun 13 '11 at 14:55 janm 12.6k12646 add a comment| up vote 1 down vote
here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings http://stackoverflow.com/questions/28003599/c-error-c2664-cannot-convert-argument-1 and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. Join them; it error c2664 only takes a minute: Sign up c++ error C2664 cannot convert argument 1 up vote 0 down vote favorite I'm creating a binary tree and I'm trying to implement a function for creating that tree. So that is the code for every member of the tree template